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Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 10 atoms:
Atom 1: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Sulfur, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Sulfur, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 18 bonds:
Between Atom 1 to 2: double bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: double bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: double bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: double bond, no stereochemistry, not conjugated.
Between Atom 2 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: double bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: double bond, no stereochemistry, not conjugated.
Between Atom 7 to 9: double bond, no stereochemistry, not conjugated.
Between Atom 9 to 7: double bond, no stereochemistry, not conjugated.
Between Atom 7 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 7: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 10 atoms:
Atom 1: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 5: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 6: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 7: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 9: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 10: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 20 bonds:
Between Atom 1 to 2: double bond, no stereochemistry, conjugated.
Between Atom 2 to 1: double bond, no stereochemistry, conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, conjugated.
Between Atom 2 to 4: single bond, no stereochemistry, conjugated.
Between Atom 4 to 2: single bond, no stereochemistry, conjugated.
Between Atom 4 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 10: single bond, no stereochemistry, conjugated.
Between Atom 10 to 9: single bond, no stereochemistry, conjugated.
Between Atom 9 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 9: aromatic bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 13 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 11: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 12: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 13: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 24 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 7: double bond, no stereochemistry, conjugated.
Between Atom 7 to 6: double bond, no stereochemistry, conjugated.
Between Atom 6 to 8: single bond, no stereochemistry, conjugated.
Between Atom 8 to 6: single bond, no stereochemistry, conjugated.
Between Atom 2 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 12: double bond, no stereochemistry, conjugated.
Between Atom 12 to 11: double bond, no stereochemistry, conjugated.
Between Atom 11 to 13: single bond, no stereochemistry, conjugated.
Between Atom 13 to 11: single bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 12 atoms:
Atom 1: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 3: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 5: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 6: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 7: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 8: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 10: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 11: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 12: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
There are 26 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 12: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 2 to 12: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 12: aromatic bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 12 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Phosphorus, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 9: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 10: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 11: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 12: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
There are 24 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 6: double bond, no stereochemistry, not conjugated.
Between Atom 6 to 4: double bond, no stereochemistry, not conjugated.
Between Atom 4 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 12: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 12: aromatic bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 12 atoms:
Atom 1: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Phosphorus, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Sulfur, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 9: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 10: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 11: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 12: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
There are 24 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: double bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: double bond, no stereochemistry, not conjugated.
Between Atom 3 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 12: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 12: aromatic bond, no stereochemistry, conjugated.
|
Yes
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 14 atoms:
Atom 1: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 3: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 5: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 6: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 7: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 9: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 10: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 11: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 12: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 13: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 14: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
There are 32 bonds:
Between Atom 1 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 2 to 1: aromatic bond, no stereochemistry, conjugated.
Between Atom 2 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 12: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 13: aromatic bond, no stereochemistry, conjugated.
Between Atom 13 to 12: aromatic bond, no stereochemistry, conjugated.
Between Atom 13 to 14: single bond, no stereochemistry, not conjugated.
Between Atom 14 to 13: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 1: aromatic bond, no stereochemistry, conjugated.
Between Atom 1 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 13 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 13: aromatic bond, no stereochemistry, conjugated.
Between Atom 14 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 14: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 9 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Sulfur, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 16 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 7: double bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: double bond, no stereochemistry, not conjugated.
Between Atom 6 to 8: double bond, no stereochemistry, not conjugated.
Between Atom 8 to 6: double bond, no stereochemistry, not conjugated.
Between Atom 6 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 6: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 14 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Phosphorus, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Sulfur, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 11: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 12: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 13: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 14: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 26 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: double bond, no stereochemistry, not conjugated.
Between Atom 6 to 5: double bond, no stereochemistry, not conjugated.
Between Atom 5 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 13: single bond, no stereochemistry, not conjugated.
Between Atom 13 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 13 to 14: single bond, no stereochemistry, not conjugated.
Between Atom 14 to 13: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 15 atoms:
Atom 1: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 3: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 5: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 7: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 9: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 10: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 11: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 12: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 13: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 14: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 15: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
There are 34 bonds:
Between Atom 1 to 2: double bond, no stereochemistry, conjugated.
Between Atom 2 to 1: double bond, no stereochemistry, conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, conjugated.
Between Atom 4 to 5: double bond, no stereochemistry, conjugated.
Between Atom 5 to 4: double bond, no stereochemistry, conjugated.
Between Atom 4 to 6: single bond, no stereochemistry, conjugated.
Between Atom 6 to 4: single bond, no stereochemistry, conjugated.
Between Atom 6 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 12: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 13: aromatic bond, no stereochemistry, conjugated.
Between Atom 13 to 12: aromatic bond, no stereochemistry, conjugated.
Between Atom 13 to 14: aromatic bond, no stereochemistry, conjugated.
Between Atom 14 to 13: aromatic bond, no stereochemistry, conjugated.
Between Atom 14 to 15: aromatic bond, no stereochemistry, conjugated.
Between Atom 15 to 14: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 2: single bond, no stereochemistry, conjugated.
Between Atom 2 to 7: single bond, no stereochemistry, conjugated.
Between Atom 15 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 15: aromatic bond, no stereochemistry, conjugated.
Between Atom 15 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 15: aromatic bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 9 atoms:
Atom 1: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 3: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 5: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 6: Sulfur, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 7: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 9: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
There are 20 bonds:
Between Atom 1 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 2 to 1: aromatic bond, no stereochemistry, conjugated.
Between Atom 2 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 1: aromatic bond, no stereochemistry, conjugated.
Between Atom 1 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 8: aromatic bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 6 atoms:
Atom 1: Sulfur, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 3: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 4: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 5: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 6: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
There are 12 bonds:
Between Atom 1 to 2: double bond, no stereochemistry, conjugated.
Between Atom 2 to 1: double bond, no stereochemistry, conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 6: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 13 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 5: Sulfur, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 1, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 6: Zinc, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge -2, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 7: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 8: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 9: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 10: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 11: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 12: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 13: Sulfur, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 1, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
There are 28 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 4: single bond, no stereochemistry, conjugated.
Between Atom 4 to 2: single bond, no stereochemistry, conjugated.
Between Atom 4 to 5: double bond, no stereochemistry, conjugated.
Between Atom 5 to 4: double bond, no stereochemistry, conjugated.
Between Atom 5 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 10: single bond, no stereochemistry, conjugated.
Between Atom 10 to 9: single bond, no stereochemistry, conjugated.
Between Atom 10 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 13: double bond, no stereochemistry, conjugated.
Between Atom 13 to 9: double bond, no stereochemistry, conjugated.
Between Atom 7 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 13 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 13: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 12 atoms:
Atom 1: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge -1, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Nitrogen, SP hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 1, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 11: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 12: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 22 bonds:
Between Atom 1 to 2: double bond, no stereochemistry, conjugated.
Between Atom 2 to 1: double bond, no stereochemistry, conjugated.
Between Atom 2 to 3: double bond, no stereochemistry, conjugated.
Between Atom 3 to 2: double bond, no stereochemistry, conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, conjugated.
Between Atom 4 to 5: double bond, no stereochemistry, conjugated.
Between Atom 5 to 4: double bond, no stereochemistry, conjugated.
Between Atom 4 to 6: single bond, no stereochemistry, conjugated.
Between Atom 6 to 4: single bond, no stereochemistry, conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 11: double bond, no stereochemistry, conjugated.
Between Atom 11 to 10: double bond, no stereochemistry, conjugated.
Between Atom 10 to 12: single bond, no stereochemistry, conjugated.
Between Atom 12 to 10: single bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 11 atoms:
Atom 1: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 3: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 5: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 7: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 8: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 9: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 10: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 11: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
There are 24 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, conjugated.
Between Atom 2 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, conjugated.
Between Atom 4 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 2 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 10: aromatic bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 14 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Sulfur, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 11: Sulfur, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 12: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 13: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 14: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 26 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: double bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: double bond, no stereochemistry, not conjugated.
Between Atom 2 to 4: double bond, no stereochemistry, not conjugated.
Between Atom 4 to 2: double bond, no stereochemistry, not conjugated.
Between Atom 2 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 13: double bond, no stereochemistry, not conjugated.
Between Atom 13 to 11: double bond, no stereochemistry, not conjugated.
Between Atom 11 to 14: double bond, no stereochemistry, not conjugated.
Between Atom 14 to 11: double bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 11 atoms:
Atom 1: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 3: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 5: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 7: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 9: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 10: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 11: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
There are 24 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, conjugated.
Between Atom 2 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 2 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 10: aromatic bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 10 atoms:
Atom 1: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 3: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 5: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 6: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 7: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 9: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 10: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
There are 22 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 2 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 10: aromatic bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 8 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Chlorine, SP3 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Chlorine, SP3 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 14 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 4 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Sulfur, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 6 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 4: double bond, no stereochemistry, not conjugated.
Between Atom 4 to 2: double bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 9 atoms:
Atom 1: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 3: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 4: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 5: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 6: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 7: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 9: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
There are 20 bonds:
Between Atom 1 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 2 to 1: aromatic bond, no stereochemistry, conjugated.
Between Atom 2 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 1: aromatic bond, no stereochemistry, conjugated.
Between Atom 1 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 8: aromatic bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 9 atoms:
Atom 1: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 3: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 4: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 5: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 6: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 7: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 9: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
There are 20 bonds:
Between Atom 1 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 2 to 1: aromatic bond, no stereochemistry, conjugated.
Between Atom 2 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 1: aromatic bond, no stereochemistry, conjugated.
Between Atom 1 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 8: aromatic bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 9 atoms:
Atom 1: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 3: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 7: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 8: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 9: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
There are 18 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: double bond, no stereochemistry, conjugated.
Between Atom 4 to 3: double bond, no stereochemistry, conjugated.
Between Atom 3 to 5: single bond, no stereochemistry, conjugated.
Between Atom 5 to 3: single bond, no stereochemistry, conjugated.
Between Atom 2 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 9: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 9 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Bromine, SP3 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Bromine, SP3 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Bromine, SP3 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 16 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: double bond, no stereochemistry, not conjugated.
Between Atom 6 to 5: double bond, no stereochemistry, not conjugated.
Between Atom 5 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 7: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 10 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Sulfur, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 18 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, conjugated.
Between Atom 4 to 5: double bond, no stereochemistry, conjugated.
Between Atom 5 to 4: double bond, no stereochemistry, conjugated.
Between Atom 4 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 9: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 13 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 11: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 12: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 13: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 24 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 13: single bond, no stereochemistry, not conjugated.
Between Atom 13 to 12: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 6 atoms:
Atom 1: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 5: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 6: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
There are 12 bonds:
Between Atom 1 to 2: double bond, no stereochemistry, conjugated.
Between Atom 2 to 1: double bond, no stereochemistry, conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, conjugated.
Between Atom 2 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 6: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 13 atoms:
Atom 1: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 5: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 7: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 8: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 10: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 11: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 12: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 13: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
There are 26 bonds:
Between Atom 1 to 2: double bond, no stereochemistry, conjugated.
Between Atom 2 to 1: double bond, no stereochemistry, conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, conjugated.
Between Atom 2 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 13: single bond, no stereochemistry, not conjugated.
Between Atom 13 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 13 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 13: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 12 atoms:
Atom 1: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 3: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 4: Chlorine, SP3 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 6: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 7: Chlorine, SP3 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 9: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 10: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 11: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 12: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 24 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, conjugated.
Between Atom 2 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 10: single bond, no stereochemistry, conjugated.
Between Atom 10 to 9: single bond, no stereochemistry, conjugated.
Between Atom 10 to 11: double bond, no stereochemistry, conjugated.
Between Atom 11 to 10: double bond, no stereochemistry, conjugated.
Between Atom 10 to 12: single bond, no stereochemistry, conjugated.
Between Atom 12 to 10: single bond, no stereochemistry, conjugated.
Between Atom 9 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 2 to 9: aromatic bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 9 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Sulfur, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 16 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, conjugated.
Between Atom 7 to 8: double bond, no stereochemistry, conjugated.
Between Atom 8 to 7: double bond, no stereochemistry, conjugated.
Between Atom 7 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 7: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 12 atoms:
Atom 1: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 5: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 6: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 7: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 9: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 11: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 12: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
There are 24 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, conjugated.
Between Atom 2 to 3: double bond, no stereochemistry, conjugated.
Between Atom 3 to 2: double bond, no stereochemistry, conjugated.
Between Atom 2 to 4: single bond, no stereochemistry, conjugated.
Between Atom 4 to 2: single bond, no stereochemistry, conjugated.
Between Atom 4 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, conjugated.
Between Atom 6 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 9: single bond, no stereochemistry, conjugated.
Between Atom 9 to 8: single bond, no stereochemistry, conjugated.
Between Atom 8 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 11: single bond, no stereochemistry, conjugated.
Between Atom 11 to 10: single bond, no stereochemistry, conjugated.
Between Atom 10 to 12: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 12: aromatic bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 8 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 3: Sulfur, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 1, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 4: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 5: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 6: Sulfur, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 1, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 7: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 8: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
There are 18 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 1 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 8: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 13 atoms:
Atom 1: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 3: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 5: Chlorine, SP3 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 7: Sulfur, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 11: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 12: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 13: Chlorine, SP3 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 26 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, conjugated.
Between Atom 2 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: double bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: double bond, no stereochemistry, not conjugated.
Between Atom 7 to 9: double bond, no stereochemistry, not conjugated.
Between Atom 9 to 7: double bond, no stereochemistry, not conjugated.
Between Atom 7 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 12: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 13: single bond, no stereochemistry, not conjugated.
Between Atom 13 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 2 to 12: aromatic bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 10 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 18 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: double bond, no stereochemistry, conjugated.
Between Atom 6 to 5: double bond, no stereochemistry, conjugated.
Between Atom 5 to 7: single bond, no stereochemistry, conjugated.
Between Atom 7 to 5: single bond, no stereochemistry, conjugated.
Between Atom 3 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 9: double bond, no stereochemistry, conjugated.
Between Atom 9 to 8: double bond, no stereochemistry, conjugated.
Between Atom 8 to 10: single bond, no stereochemistry, conjugated.
Between Atom 10 to 8: single bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 10 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 18 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: double bond, no stereochemistry, conjugated.
Between Atom 6 to 5: double bond, no stereochemistry, conjugated.
Between Atom 5 to 7: single bond, no stereochemistry, conjugated.
Between Atom 7 to 5: single bond, no stereochemistry, conjugated.
Between Atom 4 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 9: double bond, no stereochemistry, conjugated.
Between Atom 9 to 8: double bond, no stereochemistry, conjugated.
Between Atom 8 to 10: single bond, no stereochemistry, conjugated.
Between Atom 10 to 8: single bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 14 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 9: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 10: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 11: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 12: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 13: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 14: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 28 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, conjugated.
Between Atom 4 to 5: double bond, no stereochemistry, conjugated.
Between Atom 5 to 4: double bond, no stereochemistry, conjugated.
Between Atom 4 to 6: single bond, no stereochemistry, conjugated.
Between Atom 6 to 4: single bond, no stereochemistry, conjugated.
Between Atom 6 to 7: double bond, no stereochemistry, conjugated.
Between Atom 7 to 6: double bond, no stereochemistry, conjugated.
Between Atom 6 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 13: single bond, no stereochemistry, not conjugated.
Between Atom 13 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 13 to 14: double bond, no stereochemistry, not conjugated.
Between Atom 14 to 13: double bond, no stereochemistry, not conjugated.
Between Atom 13 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 13: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 10 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 18 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 9: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 13 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 3: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 4: Cobalt, misc hybridized, unspecified chirality, bonded to 6 other atoms, formal charge -4, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 5: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 6: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 7: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 8: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 9: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 10: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 11: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 12: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 13: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, in a ring.
There are 30 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 13: single bond, no stereochemistry, not conjugated.
Between Atom 13 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 1 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 13 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 13: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 14 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Sulfur, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Sulfur, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 11: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 12: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 13: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 14: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 26 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, conjugated.
Between Atom 5 to 6: double bond, no stereochemistry, conjugated.
Between Atom 6 to 5: double bond, no stereochemistry, conjugated.
Between Atom 5 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 10: double bond, no stereochemistry, conjugated.
Between Atom 10 to 9: double bond, no stereochemistry, conjugated.
Between Atom 9 to 11: single bond, no stereochemistry, conjugated.
Between Atom 11 to 9: single bond, no stereochemistry, conjugated.
Between Atom 11 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 13: single bond, no stereochemistry, not conjugated.
Between Atom 13 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 14: single bond, no stereochemistry, not conjugated.
Between Atom 14 to 12: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 12 atoms:
Atom 1: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 4: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 5: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 6: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 7: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 8: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 9: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 10: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 11: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 12: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, in a ring.
There are 26 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 12: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 14 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 9: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 10: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 11: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 12: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 13: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 14: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
There are 28 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 6: single bond, no stereochemistry, conjugated.
Between Atom 6 to 3: single bond, no stereochemistry, conjugated.
Between Atom 6 to 7: double bond, no stereochemistry, conjugated.
Between Atom 7 to 6: double bond, no stereochemistry, conjugated.
Between Atom 6 to 8: single bond, no stereochemistry, conjugated.
Between Atom 8 to 6: single bond, no stereochemistry, conjugated.
Between Atom 8 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 13: single bond, no stereochemistry, not conjugated.
Between Atom 13 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 13 to 14: single bond, no stereochemistry, not conjugated.
Between Atom 14 to 13: single bond, no stereochemistry, not conjugated.
Between Atom 14 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 14: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 10 atoms:
Atom 1: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 3: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 5: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 6: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 7: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 8: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 9: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 10: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
There are 22 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, conjugated.
Between Atom 2 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 2 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 10: aromatic bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 15 atoms:
Atom 1: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 3: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 4: Copper, misc hybridized, unspecified chirality, bonded to 6 other atoms, formal charge -5, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 5: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 9: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 11: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 12: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 13: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 14: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 15: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
There are 32 bonds:
Between Atom 1 to 2: double bond, no stereochemistry, conjugated.
Between Atom 2 to 1: double bond, no stereochemistry, conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: single bond, no stereochemistry, conjugated.
Between Atom 8 to 7: single bond, no stereochemistry, conjugated.
Between Atom 8 to 9: double bond, no stereochemistry, conjugated.
Between Atom 9 to 8: double bond, no stereochemistry, conjugated.
Between Atom 4 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 11: single bond, no stereochemistry, conjugated.
Between Atom 11 to 10: single bond, no stereochemistry, conjugated.
Between Atom 11 to 12: double bond, no stereochemistry, conjugated.
Between Atom 12 to 11: double bond, no stereochemistry, conjugated.
Between Atom 11 to 13: single bond, no stereochemistry, conjugated.
Between Atom 13 to 11: single bond, no stereochemistry, conjugated.
Between Atom 13 to 14: double bond, no stereochemistry, conjugated.
Between Atom 14 to 13: double bond, no stereochemistry, conjugated.
Between Atom 13 to 15: single bond, no stereochemistry, conjugated.
Between Atom 15 to 13: single bond, no stereochemistry, conjugated.
Between Atom 8 to 2: single bond, no stereochemistry, conjugated.
Between Atom 2 to 8: single bond, no stereochemistry, conjugated.
Between Atom 15 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 15: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 12 atoms:
Atom 1: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 5: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 6: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 7: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 9: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 11: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 12: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 24 bonds:
Between Atom 1 to 2: double bond, no stereochemistry, conjugated.
Between Atom 2 to 1: double bond, no stereochemistry, conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, conjugated.
Between Atom 3 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, conjugated.
Between Atom 6 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 9: single bond, no stereochemistry, conjugated.
Between Atom 9 to 8: single bond, no stereochemistry, conjugated.
Between Atom 9 to 10: double bond, no stereochemistry, conjugated.
Between Atom 10 to 9: double bond, no stereochemistry, conjugated.
Between Atom 8 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 12: single bond, no stereochemistry, conjugated.
Between Atom 12 to 11: single bond, no stereochemistry, conjugated.
Between Atom 11 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 11: aromatic bond, no stereochemistry, conjugated.
|
Yes
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 14 atoms:
Atom 1: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 3: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 5: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 6: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 9: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 10: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 11: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 12: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 13: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 14: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
There are 30 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, conjugated.
Between Atom 2 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 6: single bond, no stereochemistry, conjugated.
Between Atom 6 to 5: single bond, no stereochemistry, conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, conjugated.
Between Atom 7 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 12: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 13: aromatic bond, no stereochemistry, conjugated.
Between Atom 13 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 13 to 14: aromatic bond, no stereochemistry, conjugated.
Between Atom 14 to 13: aromatic bond, no stereochemistry, conjugated.
Between Atom 14 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 2 to 14: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 12: aromatic bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 14 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 9: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 10: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 11: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 12: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 13: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 14: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 28 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 10 to 11: single bond, no stereochemistry, conjugated.
Between Atom 11 to 10: single bond, no stereochemistry, conjugated.
Between Atom 10 to 12: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 10: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 13: aromatic bond, no stereochemistry, conjugated.
Between Atom 13 to 12: aromatic bond, no stereochemistry, conjugated.
Between Atom 13 to 14: single bond, no stereochemistry, conjugated.
Between Atom 14 to 13: single bond, no stereochemistry, conjugated.
Between Atom 13 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 13: aromatic bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 12 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Sulfur, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Sulfur, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 11: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 12: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 22 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 4: single bond, no stereochemistry, conjugated.
Between Atom 4 to 2: single bond, no stereochemistry, conjugated.
Between Atom 4 to 5: double bond, no stereochemistry, conjugated.
Between Atom 5 to 4: double bond, no stereochemistry, conjugated.
Between Atom 4 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 9: double bond, no stereochemistry, conjugated.
Between Atom 9 to 8: double bond, no stereochemistry, conjugated.
Between Atom 8 to 10: single bond, no stereochemistry, conjugated.
Between Atom 10 to 8: single bond, no stereochemistry, conjugated.
Between Atom 10 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 10: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 7 atoms:
Atom 1: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 3: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 4: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 5: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 6: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
There are 14 bonds:
Between Atom 1 to 2: double bond, no stereochemistry, conjugated.
Between Atom 2 to 1: double bond, no stereochemistry, conjugated.
Between Atom 2 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 3 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 3: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 6: double bond, no stereochemistry, conjugated.
Between Atom 6 to 5: double bond, no stereochemistry, conjugated.
Between Atom 5 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 2: aromatic bond, no stereochemistry, conjugated.
Between Atom 2 to 7: aromatic bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 7 atoms:
Atom 1: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Sulfur, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 12 bonds:
Between Atom 1 to 2: double bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: double bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: double bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: double bond, no stereochemistry, not conjugated.
Between Atom 2 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 7 atoms:
Atom 1: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 3: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 4: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 5: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 6: Sulfur, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, in a ring.
There are 14 bonds:
Between Atom 1 to 2: double bond, no stereochemistry, conjugated.
Between Atom 2 to 1: double bond, no stereochemistry, conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: double bond, no stereochemistry, conjugated.
Between Atom 6 to 5: double bond, no stereochemistry, conjugated.
Between Atom 5 to 7: single bond, no stereochemistry, conjugated.
Between Atom 7 to 5: single bond, no stereochemistry, conjugated.
Between Atom 7 to 2: single bond, no stereochemistry, conjugated.
Between Atom 2 to 7: single bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 15 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 3: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 4: Nitrogen, SP3 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 5: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 6: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 7: Sulfur, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 11: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 12: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 13: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 14: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 15: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
There are 30 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: double bond, no stereochemistry, conjugated.
Between Atom 8 to 7: double bond, no stereochemistry, conjugated.
Between Atom 8 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 8: single bond, no stereochemistry, not conjugated.
Between Atom 8 to 10: single bond, no stereochemistry, conjugated.
Between Atom 10 to 8: single bond, no stereochemistry, conjugated.
Between Atom 10 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 11 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 11: single bond, no stereochemistry, not conjugated.
Between Atom 12 to 13: single bond, no stereochemistry, not conjugated.
Between Atom 13 to 12: single bond, no stereochemistry, not conjugated.
Between Atom 13 to 14: single bond, no stereochemistry, not conjugated.
Between Atom 14 to 13: single bond, no stereochemistry, not conjugated.
Between Atom 14 to 15: single bond, no stereochemistry, not conjugated.
Between Atom 15 to 14: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 1 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 15 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 15: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 6 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 2: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 3: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 4: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 5: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, in a ring.
Atom 6: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, in a ring.
There are 12 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 1 to 6: single bond, no stereochemistry, not conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 11 atoms:
Atom 1: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Carbon, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 3 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 7: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 11: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 20 bonds:
Between Atom 1 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 1: single bond, no stereochemistry, not conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 4 to 5: single bond, no stereochemistry, not conjugated.
Between Atom 5 to 4: single bond, no stereochemistry, not conjugated.
Between Atom 3 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 7: double bond, no stereochemistry, conjugated.
Between Atom 7 to 6: double bond, no stereochemistry, conjugated.
Between Atom 6 to 8: single bond, no stereochemistry, conjugated.
Between Atom 8 to 6: single bond, no stereochemistry, conjugated.
Between Atom 3 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 3: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 10: double bond, no stereochemistry, conjugated.
Between Atom 10 to 9: double bond, no stereochemistry, conjugated.
Between Atom 9 to 11: single bond, no stereochemistry, conjugated.
Between Atom 11 to 9: single bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 6 atoms:
Atom 1: Nitrogen, SP hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 5: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 6: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 2 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 10 bonds:
Between Atom 1 to 2: triple bond, no stereochemistry, conjugated.
Between Atom 2 to 1: triple bond, no stereochemistry, conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, conjugated.
Between Atom 3 to 4: single bond, no stereochemistry, conjugated.
Between Atom 4 to 3: single bond, no stereochemistry, conjugated.
Between Atom 4 to 5: double bond, no stereochemistry, conjugated.
Between Atom 5 to 4: double bond, no stereochemistry, conjugated.
Between Atom 4 to 6: single bond, no stereochemistry, conjugated.
Between Atom 6 to 4: single bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 14 atoms:
Atom 1: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Nitrogen, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 1, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge -1, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 5: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 6: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 7: Arsenic, SP3 hybridized, unspecified chirality, bonded to 4 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 8: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 9: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 10: Oxygen, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 11: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 12: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 13: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 14: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 28 bonds:
Between Atom 1 to 2: double bond, no stereochemistry, conjugated.
Between Atom 2 to 1: double bond, no stereochemistry, conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, conjugated.
Between Atom 2 to 4: single bond, no stereochemistry, conjugated.
Between Atom 4 to 2: single bond, no stereochemistry, conjugated.
Between Atom 4 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 6: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 8: double bond, no stereochemistry, not conjugated.
Between Atom 8 to 7: double bond, no stereochemistry, not conjugated.
Between Atom 7 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 7 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 7: single bond, no stereochemistry, not conjugated.
Between Atom 6 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 11 to 12: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 11: aromatic bond, no stereochemistry, conjugated.
Between Atom 12 to 13: aromatic bond, no stereochemistry, conjugated.
Between Atom 13 to 12: aromatic bond, no stereochemistry, conjugated.
Between Atom 13 to 14: single bond, no stereochemistry, conjugated.
Between Atom 14 to 13: single bond, no stereochemistry, conjugated.
Between Atom 13 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 13: aromatic bond, no stereochemistry, conjugated.
|
No
|
Given a description of a molecule, the task is judge whether it can inhibit HIV replication. You should format your answer as Yes or No.
This is a molecular graph with 10 atoms:
Atom 1: Oxygen, SP2 hybridized, unspecified chirality, bonded to 1 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 2: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 3: Oxygen, SP2 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
Atom 4: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 5: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 6: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 7: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 8: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 9: Carbon, SP2 hybridized, unspecified chirality, bonded to 3 other atoms, formal charge 0, has 0 hydrogen, 0 radical electrons, aromatic, in a ring.
Atom 10: Sulfur, SP3 hybridized, unspecified chirality, bonded to 2 other atoms, formal charge 0, has 1 hydrogen, 0 radical electrons, not aromatic, not in a ring.
There are 20 bonds:
Between Atom 1 to 2: double bond, no stereochemistry, conjugated.
Between Atom 2 to 1: double bond, no stereochemistry, conjugated.
Between Atom 2 to 3: single bond, no stereochemistry, conjugated.
Between Atom 3 to 2: single bond, no stereochemistry, conjugated.
Between Atom 2 to 4: single bond, no stereochemistry, conjugated.
Between Atom 4 to 2: single bond, no stereochemistry, conjugated.
Between Atom 4 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 5 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 5: aromatic bond, no stereochemistry, conjugated.
Between Atom 6 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 6: aromatic bond, no stereochemistry, conjugated.
Between Atom 7 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 7: aromatic bond, no stereochemistry, conjugated.
Between Atom 8 to 9: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 8: aromatic bond, no stereochemistry, conjugated.
Between Atom 9 to 10: single bond, no stereochemistry, not conjugated.
Between Atom 10 to 9: single bond, no stereochemistry, not conjugated.
Between Atom 9 to 4: aromatic bond, no stereochemistry, conjugated.
Between Atom 4 to 9: aromatic bond, no stereochemistry, conjugated.
|
No
|
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