import_str
listlengths 0
1
| doc_string
stringclasses 164
values | suffix
stringlengths 0
837
| compare_func
listlengths 0
0
| data_id
stringlengths 34
37
| task_name
stringclasses 1
value | solution
stringlengths 6
141
| demos
listlengths 0
8
| prefix
stringlengths 65
1.8k
| dataset_name
stringclasses 1
value | entry_func
stringclasses 158
values | tgt_lang
stringclasses 1
value | src_lang
stringclasses 1
value | test_cases
listlengths 0
100
|
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
[] |
Implement the function f that takes n as a parameter,
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
|
ret += [x]
return ret
|
[] |
SingleLineInfilling/HumanEval/106/L8
|
code_infilling
|
for j in range(1,i+1): x += j
|
[
[
"5",
"[1, 2, 6, 24, 15]"
]
] |
def f(n):
""" Implement the function f that takes n as a parameter,
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
"""
ret = []
for i in range(1,n+1):
if i%2 == 0:
x = 1
for j in range(1,i+1): x *= j
ret += [x]
else:
x = 0
|
HumanEval_SingleLineInfillingLight
|
f
|
python
|
python
|
[
[
"5",
"[1, 2, 6, 24, 15]"
],
[
"7",
"[1, 2, 6, 24, 15, 720, 28]"
],
[
"1",
"[1]"
],
[
"3",
"[1, 2, 6]"
]
] |
[] |
Implement the function f that takes n as a parameter,
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
|
return ret
|
[] |
SingleLineInfilling/HumanEval/106/L9
|
code_infilling
|
ret += [x]
|
[
[
"5",
"[1, 2, 6, 24, 15]"
]
] |
def f(n):
""" Implement the function f that takes n as a parameter,
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
"""
ret = []
for i in range(1,n+1):
if i%2 == 0:
x = 1
for j in range(1,i+1): x *= j
ret += [x]
else:
x = 0
for j in range(1,i+1): x += j
|
HumanEval_SingleLineInfillingLight
|
f
|
python
|
python
|
[
[
"5",
"[1, 2, 6, 24, 15]"
],
[
"7",
"[1, 2, 6, 24, 15, 720, 28]"
],
[
"1",
"[1]"
],
[
"3",
"[1, 2, 6]"
]
] |
[] |
Implement the function f that takes n as a parameter,
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
|
[] |
SingleLineInfilling/HumanEval/106/L10
|
code_infilling
|
return ret
|
[
[
"5",
"[1, 2, 6, 24, 15]"
]
] |
def f(n):
""" Implement the function f that takes n as a parameter,
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
"""
ret = []
for i in range(1,n+1):
if i%2 == 0:
x = 1
for j in range(1,i+1): x *= j
ret += [x]
else:
x = 0
for j in range(1,i+1): x += j
ret += [x]
|
HumanEval_SingleLineInfillingLight
|
f
|
python
|
python
|
[
[
"5",
"[1, 2, 6, 24, 15]"
],
[
"7",
"[1, 2, 6, 24, 15, 720, 28]"
],
[
"1",
"[1]"
],
[
"3",
"[1, 2, 6]"
]
] |
|
[] |
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
|
return str(n) == str(n)[::-1]
even_palindrome_count = 0
odd_palindrome_count = 0
for i in range(1, n+1):
if i%2 == 1 and is_palindrome(i):
odd_palindrome_count += 1
elif i%2 == 0 and is_palindrome(i):
even_palindrome_count += 1
return (even_palindrome_count, odd_palindrome_count)
|
[] |
SingleLineInfilling/HumanEval/107/L0
|
code_infilling
|
def is_palindrome(n):
|
[
[
"3",
"(1, 2)"
],
[
"12",
"(4, 6)"
]
] |
def even_odd_palindrome(n):
"""
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
"""
|
HumanEval_SingleLineInfillingLight
|
even_odd_palindrome
|
python
|
python
|
[
[
"123",
"(8, 13)"
],
[
"12",
"(4, 6)"
],
[
"3",
"(1, 2)"
],
[
"63",
"(6, 8)"
],
[
"25",
"(5, 6)"
],
[
"19",
"(4, 6)"
],
[
"9",
"(4, 5)"
],
[
"1",
"(0, 1)"
]
] |
[] |
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
|
even_palindrome_count = 0
odd_palindrome_count = 0
for i in range(1, n+1):
if i%2 == 1 and is_palindrome(i):
odd_palindrome_count += 1
elif i%2 == 0 and is_palindrome(i):
even_palindrome_count += 1
return (even_palindrome_count, odd_palindrome_count)
|
[] |
SingleLineInfilling/HumanEval/107/L1
|
code_infilling
|
return str(n) == str(n)[::-1]
|
[
[
"3",
"(1, 2)"
],
[
"12",
"(4, 6)"
]
] |
def even_odd_palindrome(n):
"""
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
"""
def is_palindrome(n):
|
HumanEval_SingleLineInfillingLight
|
even_odd_palindrome
|
python
|
python
|
[
[
"123",
"(8, 13)"
],
[
"12",
"(4, 6)"
],
[
"3",
"(1, 2)"
],
[
"63",
"(6, 8)"
],
[
"25",
"(5, 6)"
],
[
"19",
"(4, 6)"
],
[
"9",
"(4, 5)"
],
[
"1",
"(0, 1)"
]
] |
[] |
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
|
odd_palindrome_count = 0
for i in range(1, n+1):
if i%2 == 1 and is_palindrome(i):
odd_palindrome_count += 1
elif i%2 == 0 and is_palindrome(i):
even_palindrome_count += 1
return (even_palindrome_count, odd_palindrome_count)
|
[] |
SingleLineInfilling/HumanEval/107/L3
|
code_infilling
|
even_palindrome_count = 0
|
[
[
"3",
"(1, 2)"
],
[
"12",
"(4, 6)"
]
] |
def even_odd_palindrome(n):
"""
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
"""
def is_palindrome(n):
return str(n) == str(n)[::-1]
|
HumanEval_SingleLineInfillingLight
|
even_odd_palindrome
|
python
|
python
|
[
[
"123",
"(8, 13)"
],
[
"12",
"(4, 6)"
],
[
"3",
"(1, 2)"
],
[
"63",
"(6, 8)"
],
[
"25",
"(5, 6)"
],
[
"19",
"(4, 6)"
],
[
"9",
"(4, 5)"
],
[
"1",
"(0, 1)"
]
] |
[] |
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
|
for i in range(1, n+1):
if i%2 == 1 and is_palindrome(i):
odd_palindrome_count += 1
elif i%2 == 0 and is_palindrome(i):
even_palindrome_count += 1
return (even_palindrome_count, odd_palindrome_count)
|
[] |
SingleLineInfilling/HumanEval/107/L4
|
code_infilling
|
odd_palindrome_count = 0
|
[
[
"3",
"(1, 2)"
],
[
"12",
"(4, 6)"
]
] |
def even_odd_palindrome(n):
"""
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
"""
def is_palindrome(n):
return str(n) == str(n)[::-1]
even_palindrome_count = 0
|
HumanEval_SingleLineInfillingLight
|
even_odd_palindrome
|
python
|
python
|
[
[
"123",
"(8, 13)"
],
[
"12",
"(4, 6)"
],
[
"3",
"(1, 2)"
],
[
"63",
"(6, 8)"
],
[
"25",
"(5, 6)"
],
[
"19",
"(4, 6)"
],
[
"9",
"(4, 5)"
],
[
"1",
"(0, 1)"
]
] |
[] |
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
|
if i%2 == 1 and is_palindrome(i):
odd_palindrome_count += 1
elif i%2 == 0 and is_palindrome(i):
even_palindrome_count += 1
return (even_palindrome_count, odd_palindrome_count)
|
[] |
SingleLineInfilling/HumanEval/107/L6
|
code_infilling
|
for i in range(1, n+1):
|
[
[
"3",
"(1, 2)"
],
[
"12",
"(4, 6)"
]
] |
def even_odd_palindrome(n):
"""
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
"""
def is_palindrome(n):
return str(n) == str(n)[::-1]
even_palindrome_count = 0
odd_palindrome_count = 0
|
HumanEval_SingleLineInfillingLight
|
even_odd_palindrome
|
python
|
python
|
[
[
"123",
"(8, 13)"
],
[
"12",
"(4, 6)"
],
[
"3",
"(1, 2)"
],
[
"63",
"(6, 8)"
],
[
"25",
"(5, 6)"
],
[
"19",
"(4, 6)"
],
[
"9",
"(4, 5)"
],
[
"1",
"(0, 1)"
]
] |
[] |
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
|
odd_palindrome_count += 1
elif i%2 == 0 and is_palindrome(i):
even_palindrome_count += 1
return (even_palindrome_count, odd_palindrome_count)
|
[] |
SingleLineInfilling/HumanEval/107/L7
|
code_infilling
|
if i%2 == 1 and is_palindrome(i):
|
[
[
"3",
"(1, 2)"
],
[
"12",
"(4, 6)"
]
] |
def even_odd_palindrome(n):
"""
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
"""
def is_palindrome(n):
return str(n) == str(n)[::-1]
even_palindrome_count = 0
odd_palindrome_count = 0
for i in range(1, n+1):
|
HumanEval_SingleLineInfillingLight
|
even_odd_palindrome
|
python
|
python
|
[
[
"123",
"(8, 13)"
],
[
"12",
"(4, 6)"
],
[
"3",
"(1, 2)"
],
[
"63",
"(6, 8)"
],
[
"25",
"(5, 6)"
],
[
"19",
"(4, 6)"
],
[
"9",
"(4, 5)"
],
[
"1",
"(0, 1)"
]
] |
[] |
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
|
elif i%2 == 0 and is_palindrome(i):
even_palindrome_count += 1
return (even_palindrome_count, odd_palindrome_count)
|
[] |
SingleLineInfilling/HumanEval/107/L8
|
code_infilling
|
odd_palindrome_count += 1
|
[
[
"3",
"(1, 2)"
],
[
"12",
"(4, 6)"
]
] |
def even_odd_palindrome(n):
"""
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
"""
def is_palindrome(n):
return str(n) == str(n)[::-1]
even_palindrome_count = 0
odd_palindrome_count = 0
for i in range(1, n+1):
if i%2 == 1 and is_palindrome(i):
|
HumanEval_SingleLineInfillingLight
|
even_odd_palindrome
|
python
|
python
|
[
[
"123",
"(8, 13)"
],
[
"12",
"(4, 6)"
],
[
"3",
"(1, 2)"
],
[
"63",
"(6, 8)"
],
[
"25",
"(5, 6)"
],
[
"19",
"(4, 6)"
],
[
"9",
"(4, 5)"
],
[
"1",
"(0, 1)"
]
] |
[] |
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
|
even_palindrome_count += 1
return (even_palindrome_count, odd_palindrome_count)
|
[] |
SingleLineInfilling/HumanEval/107/L9
|
code_infilling
|
elif i%2 == 0 and is_palindrome(i):
|
[
[
"3",
"(1, 2)"
],
[
"12",
"(4, 6)"
]
] |
def even_odd_palindrome(n):
"""
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
"""
def is_palindrome(n):
return str(n) == str(n)[::-1]
even_palindrome_count = 0
odd_palindrome_count = 0
for i in range(1, n+1):
if i%2 == 1 and is_palindrome(i):
odd_palindrome_count += 1
|
HumanEval_SingleLineInfillingLight
|
even_odd_palindrome
|
python
|
python
|
[
[
"123",
"(8, 13)"
],
[
"12",
"(4, 6)"
],
[
"3",
"(1, 2)"
],
[
"63",
"(6, 8)"
],
[
"25",
"(5, 6)"
],
[
"19",
"(4, 6)"
],
[
"9",
"(4, 5)"
],
[
"1",
"(0, 1)"
]
] |
[] |
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
|
return (even_palindrome_count, odd_palindrome_count)
|
[] |
SingleLineInfilling/HumanEval/107/L10
|
code_infilling
|
even_palindrome_count += 1
|
[
[
"3",
"(1, 2)"
],
[
"12",
"(4, 6)"
]
] |
def even_odd_palindrome(n):
"""
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
"""
def is_palindrome(n):
return str(n) == str(n)[::-1]
even_palindrome_count = 0
odd_palindrome_count = 0
for i in range(1, n+1):
if i%2 == 1 and is_palindrome(i):
odd_palindrome_count += 1
elif i%2 == 0 and is_palindrome(i):
|
HumanEval_SingleLineInfillingLight
|
even_odd_palindrome
|
python
|
python
|
[
[
"123",
"(8, 13)"
],
[
"12",
"(4, 6)"
],
[
"3",
"(1, 2)"
],
[
"63",
"(6, 8)"
],
[
"25",
"(5, 6)"
],
[
"19",
"(4, 6)"
],
[
"9",
"(4, 5)"
],
[
"1",
"(0, 1)"
]
] |
[] |
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
|
[] |
SingleLineInfilling/HumanEval/107/L11
|
code_infilling
|
return (even_palindrome_count, odd_palindrome_count)
|
[
[
"3",
"(1, 2)"
],
[
"12",
"(4, 6)"
]
] |
def even_odd_palindrome(n):
"""
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
"""
def is_palindrome(n):
return str(n) == str(n)[::-1]
even_palindrome_count = 0
odd_palindrome_count = 0
for i in range(1, n+1):
if i%2 == 1 and is_palindrome(i):
odd_palindrome_count += 1
elif i%2 == 0 and is_palindrome(i):
even_palindrome_count += 1
|
HumanEval_SingleLineInfillingLight
|
even_odd_palindrome
|
python
|
python
|
[
[
"123",
"(8, 13)"
],
[
"12",
"(4, 6)"
],
[
"3",
"(1, 2)"
],
[
"63",
"(6, 8)"
],
[
"25",
"(5, 6)"
],
[
"19",
"(4, 6)"
],
[
"9",
"(4, 5)"
],
[
"1",
"(0, 1)"
]
] |
|
[] |
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
|
neg = 1
if n < 0: n, neg = -1 * n, -1
n = [int(i) for i in str(n)]
n[0] = n[0] * neg
return sum(n)
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr])))
|
[] |
SingleLineInfilling/HumanEval/108/L0
|
code_infilling
|
def digits_sum(n):
|
[
[
"[]",
"0"
],
[
"[-1, 11, -11]",
"1"
],
[
"[1, 1, 2]",
"3"
]
] |
def count_nums(arr):
"""
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
"""
|
HumanEval_SingleLineInfillingLight
|
count_nums
|
python
|
python
|
[
[
"[]",
"0"
],
[
"[-1, -2, 0]",
"0"
],
[
"[1, 1, 2, -2, 3, 4, 5]",
"6"
],
[
"[1, 6, 9, -6, 0, 1, 5]",
"5"
],
[
"[1, 100, 98, -7, 1, -1]",
"4"
],
[
"[12, 23, 34, -45, -56, 0]",
"5"
],
[
"[-0, 1**0]",
"1"
],
[
"[1]",
"1"
]
] |
[] |
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
|
if n < 0: n, neg = -1 * n, -1
n = [int(i) for i in str(n)]
n[0] = n[0] * neg
return sum(n)
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr])))
|
[] |
SingleLineInfilling/HumanEval/108/L1
|
code_infilling
|
neg = 1
|
[
[
"[]",
"0"
],
[
"[-1, 11, -11]",
"1"
],
[
"[1, 1, 2]",
"3"
]
] |
def count_nums(arr):
"""
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
"""
def digits_sum(n):
|
HumanEval_SingleLineInfillingLight
|
count_nums
|
python
|
python
|
[
[
"[]",
"0"
],
[
"[-1, -2, 0]",
"0"
],
[
"[1, 1, 2, -2, 3, 4, 5]",
"6"
],
[
"[1, 6, 9, -6, 0, 1, 5]",
"5"
],
[
"[1, 100, 98, -7, 1, -1]",
"4"
],
[
"[12, 23, 34, -45, -56, 0]",
"5"
],
[
"[-0, 1**0]",
"1"
],
[
"[1]",
"1"
]
] |
[] |
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
|
n = [int(i) for i in str(n)]
n[0] = n[0] * neg
return sum(n)
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr])))
|
[] |
SingleLineInfilling/HumanEval/108/L2
|
code_infilling
|
if n < 0: n, neg = -1 * n, -1
|
[
[
"[]",
"0"
],
[
"[-1, 11, -11]",
"1"
],
[
"[1, 1, 2]",
"3"
]
] |
def count_nums(arr):
"""
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
"""
def digits_sum(n):
neg = 1
|
HumanEval_SingleLineInfillingLight
|
count_nums
|
python
|
python
|
[
[
"[]",
"0"
],
[
"[-1, -2, 0]",
"0"
],
[
"[1, 1, 2, -2, 3, 4, 5]",
"6"
],
[
"[1, 6, 9, -6, 0, 1, 5]",
"5"
],
[
"[1, 100, 98, -7, 1, -1]",
"4"
],
[
"[12, 23, 34, -45, -56, 0]",
"5"
],
[
"[-0, 1**0]",
"1"
],
[
"[1]",
"1"
]
] |
[] |
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
|
n[0] = n[0] * neg
return sum(n)
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr])))
|
[] |
SingleLineInfilling/HumanEval/108/L3
|
code_infilling
|
n = [int(i) for i in str(n)]
|
[
[
"[]",
"0"
],
[
"[-1, 11, -11]",
"1"
],
[
"[1, 1, 2]",
"3"
]
] |
def count_nums(arr):
"""
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
"""
def digits_sum(n):
neg = 1
if n < 0: n, neg = -1 * n, -1
|
HumanEval_SingleLineInfillingLight
|
count_nums
|
python
|
python
|
[
[
"[]",
"0"
],
[
"[-1, -2, 0]",
"0"
],
[
"[1, 1, 2, -2, 3, 4, 5]",
"6"
],
[
"[1, 6, 9, -6, 0, 1, 5]",
"5"
],
[
"[1, 100, 98, -7, 1, -1]",
"4"
],
[
"[12, 23, 34, -45, -56, 0]",
"5"
],
[
"[-0, 1**0]",
"1"
],
[
"[1]",
"1"
]
] |
[] |
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
|
return sum(n)
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr])))
|
[] |
SingleLineInfilling/HumanEval/108/L4
|
code_infilling
|
n[0] = n[0] * neg
|
[
[
"[]",
"0"
],
[
"[-1, 11, -11]",
"1"
],
[
"[1, 1, 2]",
"3"
]
] |
def count_nums(arr):
"""
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
"""
def digits_sum(n):
neg = 1
if n < 0: n, neg = -1 * n, -1
n = [int(i) for i in str(n)]
|
HumanEval_SingleLineInfillingLight
|
count_nums
|
python
|
python
|
[
[
"[]",
"0"
],
[
"[-1, -2, 0]",
"0"
],
[
"[1, 1, 2, -2, 3, 4, 5]",
"6"
],
[
"[1, 6, 9, -6, 0, 1, 5]",
"5"
],
[
"[1, 100, 98, -7, 1, -1]",
"4"
],
[
"[12, 23, 34, -45, -56, 0]",
"5"
],
[
"[-0, 1**0]",
"1"
],
[
"[1]",
"1"
]
] |
[] |
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
|
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr])))
|
[] |
SingleLineInfilling/HumanEval/108/L5
|
code_infilling
|
return sum(n)
|
[
[
"[]",
"0"
],
[
"[-1, 11, -11]",
"1"
],
[
"[1, 1, 2]",
"3"
]
] |
def count_nums(arr):
"""
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
"""
def digits_sum(n):
neg = 1
if n < 0: n, neg = -1 * n, -1
n = [int(i) for i in str(n)]
n[0] = n[0] * neg
|
HumanEval_SingleLineInfillingLight
|
count_nums
|
python
|
python
|
[
[
"[]",
"0"
],
[
"[-1, -2, 0]",
"0"
],
[
"[1, 1, 2, -2, 3, 4, 5]",
"6"
],
[
"[1, 6, 9, -6, 0, 1, 5]",
"5"
],
[
"[1, 100, 98, -7, 1, -1]",
"4"
],
[
"[12, 23, 34, -45, -56, 0]",
"5"
],
[
"[-0, 1**0]",
"1"
],
[
"[1]",
"1"
]
] |
[] |
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
|
[] |
SingleLineInfilling/HumanEval/108/L6
|
code_infilling
|
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr])))
|
[
[
"[]",
"0"
],
[
"[-1, 11, -11]",
"1"
],
[
"[1, 1, 2]",
"3"
]
] |
def count_nums(arr):
"""
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
"""
def digits_sum(n):
neg = 1
if n < 0: n, neg = -1 * n, -1
n = [int(i) for i in str(n)]
n[0] = n[0] * neg
return sum(n)
|
HumanEval_SingleLineInfillingLight
|
count_nums
|
python
|
python
|
[
[
"[]",
"0"
],
[
"[-1, -2, 0]",
"0"
],
[
"[1, 1, 2, -2, 3, 4, 5]",
"6"
],
[
"[1, 6, 9, -6, 0, 1, 5]",
"5"
],
[
"[1, 100, 98, -7, 1, -1]",
"4"
],
[
"[12, 23, 34, -45, -56, 0]",
"5"
],
[
"[-0, 1**0]",
"1"
],
[
"[1]",
"1"
]
] |
|
[] |
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
|
return True
sorted_array=sorted(arr)
my_arr=[]
min_value=min(arr)
min_index=arr.index(min_value)
my_arr=arr[min_index:]+arr[0:min_index]
for i in range(len(arr)):
if my_arr[i]!=sorted_array[i]:
return False
return True
|
[] |
SingleLineInfilling/HumanEval/109/L0
|
code_infilling
|
if len(arr)==0:
|
[
[
"[3, 4, 5, 1, 2]",
">True"
],
[
"[3, 5, 4, 1, 2]",
">False"
]
] |
def move_one_ball(arr):
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
"""
|
HumanEval_SingleLineInfillingLight
|
move_one_ball
|
python
|
python
|
[
[
"[3, 4, 5, 1, 2]",
"True"
],
[
"[3, 5, 10, 1, 2]",
"True"
],
[
"[4, 3, 1, 2]",
"False"
],
[
"[3, 5, 4, 1, 2]",
"False"
],
[
"[]",
"True"
]
] |
[] |
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
|
sorted_array=sorted(arr)
my_arr=[]
min_value=min(arr)
min_index=arr.index(min_value)
my_arr=arr[min_index:]+arr[0:min_index]
for i in range(len(arr)):
if my_arr[i]!=sorted_array[i]:
return False
return True
|
[] |
SingleLineInfilling/HumanEval/109/L1
|
code_infilling
|
return True
|
[
[
"[3, 4, 5, 1, 2]",
">True"
],
[
"[3, 5, 4, 1, 2]",
">False"
]
] |
def move_one_ball(arr):
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
"""
if len(arr)==0:
|
HumanEval_SingleLineInfillingLight
|
move_one_ball
|
python
|
python
|
[
[
"[3, 4, 5, 1, 2]",
"True"
],
[
"[3, 5, 10, 1, 2]",
"True"
],
[
"[4, 3, 1, 2]",
"False"
],
[
"[3, 5, 4, 1, 2]",
"False"
],
[
"[]",
"True"
]
] |
[] |
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
|
my_arr=[]
min_value=min(arr)
min_index=arr.index(min_value)
my_arr=arr[min_index:]+arr[0:min_index]
for i in range(len(arr)):
if my_arr[i]!=sorted_array[i]:
return False
return True
|
[] |
SingleLineInfilling/HumanEval/109/L2
|
code_infilling
|
sorted_array=sorted(arr)
|
[
[
"[3, 4, 5, 1, 2]",
">True"
],
[
"[3, 5, 4, 1, 2]",
">False"
]
] |
def move_one_ball(arr):
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
"""
if len(arr)==0:
return True
|
HumanEval_SingleLineInfillingLight
|
move_one_ball
|
python
|
python
|
[
[
"[3, 4, 5, 1, 2]",
"True"
],
[
"[3, 5, 10, 1, 2]",
"True"
],
[
"[4, 3, 1, 2]",
"False"
],
[
"[3, 5, 4, 1, 2]",
"False"
],
[
"[]",
"True"
]
] |
[] |
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
|
min_value=min(arr)
min_index=arr.index(min_value)
my_arr=arr[min_index:]+arr[0:min_index]
for i in range(len(arr)):
if my_arr[i]!=sorted_array[i]:
return False
return True
|
[] |
SingleLineInfilling/HumanEval/109/L3
|
code_infilling
|
my_arr=[]
|
[
[
"[3, 4, 5, 1, 2]",
">True"
],
[
"[3, 5, 4, 1, 2]",
">False"
]
] |
def move_one_ball(arr):
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
"""
if len(arr)==0:
return True
sorted_array=sorted(arr)
|
HumanEval_SingleLineInfillingLight
|
move_one_ball
|
python
|
python
|
[
[
"[3, 4, 5, 1, 2]",
"True"
],
[
"[3, 5, 10, 1, 2]",
"True"
],
[
"[4, 3, 1, 2]",
"False"
],
[
"[3, 5, 4, 1, 2]",
"False"
],
[
"[]",
"True"
]
] |
[] |
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
|
min_index=arr.index(min_value)
my_arr=arr[min_index:]+arr[0:min_index]
for i in range(len(arr)):
if my_arr[i]!=sorted_array[i]:
return False
return True
|
[] |
SingleLineInfilling/HumanEval/109/L5
|
code_infilling
|
min_value=min(arr)
|
[
[
"[3, 4, 5, 1, 2]",
">True"
],
[
"[3, 5, 4, 1, 2]",
">False"
]
] |
def move_one_ball(arr):
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
"""
if len(arr)==0:
return True
sorted_array=sorted(arr)
my_arr=[]
|
HumanEval_SingleLineInfillingLight
|
move_one_ball
|
python
|
python
|
[
[
"[3, 4, 5, 1, 2]",
"True"
],
[
"[3, 5, 10, 1, 2]",
"True"
],
[
"[4, 3, 1, 2]",
"False"
],
[
"[3, 5, 4, 1, 2]",
"False"
],
[
"[]",
"True"
]
] |
[] |
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
|
my_arr=arr[min_index:]+arr[0:min_index]
for i in range(len(arr)):
if my_arr[i]!=sorted_array[i]:
return False
return True
|
[] |
SingleLineInfilling/HumanEval/109/L6
|
code_infilling
|
min_index=arr.index(min_value)
|
[
[
"[3, 4, 5, 1, 2]",
">True"
],
[
"[3, 5, 4, 1, 2]",
">False"
]
] |
def move_one_ball(arr):
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
"""
if len(arr)==0:
return True
sorted_array=sorted(arr)
my_arr=[]
min_value=min(arr)
|
HumanEval_SingleLineInfillingLight
|
move_one_ball
|
python
|
python
|
[
[
"[3, 4, 5, 1, 2]",
"True"
],
[
"[3, 5, 10, 1, 2]",
"True"
],
[
"[4, 3, 1, 2]",
"False"
],
[
"[3, 5, 4, 1, 2]",
"False"
],
[
"[]",
"True"
]
] |
[] |
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
|
for i in range(len(arr)):
if my_arr[i]!=sorted_array[i]:
return False
return True
|
[] |
SingleLineInfilling/HumanEval/109/L7
|
code_infilling
|
my_arr=arr[min_index:]+arr[0:min_index]
|
[
[
"[3, 4, 5, 1, 2]",
">True"
],
[
"[3, 5, 4, 1, 2]",
">False"
]
] |
def move_one_ball(arr):
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
"""
if len(arr)==0:
return True
sorted_array=sorted(arr)
my_arr=[]
min_value=min(arr)
min_index=arr.index(min_value)
|
HumanEval_SingleLineInfillingLight
|
move_one_ball
|
python
|
python
|
[
[
"[3, 4, 5, 1, 2]",
"True"
],
[
"[3, 5, 10, 1, 2]",
"True"
],
[
"[4, 3, 1, 2]",
"False"
],
[
"[3, 5, 4, 1, 2]",
"False"
],
[
"[]",
"True"
]
] |
[] |
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
|
if my_arr[i]!=sorted_array[i]:
return False
return True
|
[] |
SingleLineInfilling/HumanEval/109/L8
|
code_infilling
|
for i in range(len(arr)):
|
[
[
"[3, 4, 5, 1, 2]",
">True"
],
[
"[3, 5, 4, 1, 2]",
">False"
]
] |
def move_one_ball(arr):
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
"""
if len(arr)==0:
return True
sorted_array=sorted(arr)
my_arr=[]
min_value=min(arr)
min_index=arr.index(min_value)
my_arr=arr[min_index:]+arr[0:min_index]
|
HumanEval_SingleLineInfillingLight
|
move_one_ball
|
python
|
python
|
[
[
"[3, 4, 5, 1, 2]",
"True"
],
[
"[3, 5, 10, 1, 2]",
"True"
],
[
"[4, 3, 1, 2]",
"False"
],
[
"[3, 5, 4, 1, 2]",
"False"
],
[
"[]",
"True"
]
] |
[] |
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
|
return False
return True
|
[] |
SingleLineInfilling/HumanEval/109/L9
|
code_infilling
|
if my_arr[i]!=sorted_array[i]:
|
[
[
"[3, 4, 5, 1, 2]",
">True"
],
[
"[3, 5, 4, 1, 2]",
">False"
]
] |
def move_one_ball(arr):
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
"""
if len(arr)==0:
return True
sorted_array=sorted(arr)
my_arr=[]
min_value=min(arr)
min_index=arr.index(min_value)
my_arr=arr[min_index:]+arr[0:min_index]
for i in range(len(arr)):
|
HumanEval_SingleLineInfillingLight
|
move_one_ball
|
python
|
python
|
[
[
"[3, 4, 5, 1, 2]",
"True"
],
[
"[3, 5, 10, 1, 2]",
"True"
],
[
"[4, 3, 1, 2]",
"False"
],
[
"[3, 5, 4, 1, 2]",
"False"
],
[
"[]",
"True"
]
] |
[] |
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
|
return True
|
[] |
SingleLineInfilling/HumanEval/109/L10
|
code_infilling
|
return False
|
[
[
"[3, 4, 5, 1, 2]",
">True"
],
[
"[3, 5, 4, 1, 2]",
">False"
]
] |
def move_one_ball(arr):
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
"""
if len(arr)==0:
return True
sorted_array=sorted(arr)
my_arr=[]
min_value=min(arr)
min_index=arr.index(min_value)
my_arr=arr[min_index:]+arr[0:min_index]
for i in range(len(arr)):
if my_arr[i]!=sorted_array[i]:
|
HumanEval_SingleLineInfillingLight
|
move_one_ball
|
python
|
python
|
[
[
"[3, 4, 5, 1, 2]",
"True"
],
[
"[3, 5, 10, 1, 2]",
"True"
],
[
"[4, 3, 1, 2]",
"False"
],
[
"[3, 5, 4, 1, 2]",
"False"
],
[
"[]",
"True"
]
] |
[] |
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
|
[] |
SingleLineInfilling/HumanEval/109/L11
|
code_infilling
|
return True
|
[
[
"[3, 4, 5, 1, 2]",
">True"
],
[
"[3, 5, 4, 1, 2]",
">False"
]
] |
def move_one_ball(arr):
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return True else return False.
If the given array is empty then return True.
Note: The given list is guaranteed to have unique elements.
"""
if len(arr)==0:
return True
sorted_array=sorted(arr)
my_arr=[]
min_value=min(arr)
min_index=arr.index(min_value)
my_arr=arr[min_index:]+arr[0:min_index]
for i in range(len(arr)):
if my_arr[i]!=sorted_array[i]:
return False
|
HumanEval_SingleLineInfillingLight
|
move_one_ball
|
python
|
python
|
[
[
"[3, 4, 5, 1, 2]",
"True"
],
[
"[3, 5, 10, 1, 2]",
"True"
],
[
"[4, 3, 1, 2]",
"False"
],
[
"[3, 5, 4, 1, 2]",
"False"
],
[
"[]",
"True"
]
] |
|
[] |
In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
|
even = 0
for i in lst1:
if i%2 == 1:
odd += 1
for i in lst2:
if i%2 == 0:
even += 1
if even >= odd:
return "YES"
return "NO"
|
[] |
SingleLineInfilling/HumanEval/110/L0
|
code_infilling
|
odd = 0
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
]
] |
def exchange(lst1, lst2):
"""In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
"""
|
HumanEval_SingleLineInfillingLight
|
exchange
|
python
|
python
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
],
[
"[1, 2, 3, 4], [2, 1, 4, 3]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 4]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 3]",
"\"NO\""
],
[
"[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]",
"\"NO\""
],
[
"[100, 200], [200, 200]",
"\"YES\""
]
] |
[] |
In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
|
for i in lst1:
if i%2 == 1:
odd += 1
for i in lst2:
if i%2 == 0:
even += 1
if even >= odd:
return "YES"
return "NO"
|
[] |
SingleLineInfilling/HumanEval/110/L1
|
code_infilling
|
even = 0
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
]
] |
def exchange(lst1, lst2):
"""In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
"""
odd = 0
|
HumanEval_SingleLineInfillingLight
|
exchange
|
python
|
python
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
],
[
"[1, 2, 3, 4], [2, 1, 4, 3]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 4]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 3]",
"\"NO\""
],
[
"[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]",
"\"NO\""
],
[
"[100, 200], [200, 200]",
"\"YES\""
]
] |
[] |
In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
|
if i%2 == 1:
odd += 1
for i in lst2:
if i%2 == 0:
even += 1
if even >= odd:
return "YES"
return "NO"
|
[] |
SingleLineInfilling/HumanEval/110/L2
|
code_infilling
|
for i in lst1:
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
]
] |
def exchange(lst1, lst2):
"""In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
"""
odd = 0
even = 0
|
HumanEval_SingleLineInfillingLight
|
exchange
|
python
|
python
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
],
[
"[1, 2, 3, 4], [2, 1, 4, 3]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 4]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 3]",
"\"NO\""
],
[
"[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]",
"\"NO\""
],
[
"[100, 200], [200, 200]",
"\"YES\""
]
] |
[] |
In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
|
odd += 1
for i in lst2:
if i%2 == 0:
even += 1
if even >= odd:
return "YES"
return "NO"
|
[] |
SingleLineInfilling/HumanEval/110/L3
|
code_infilling
|
if i%2 == 1:
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
]
] |
def exchange(lst1, lst2):
"""In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
"""
odd = 0
even = 0
for i in lst1:
|
HumanEval_SingleLineInfillingLight
|
exchange
|
python
|
python
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
],
[
"[1, 2, 3, 4], [2, 1, 4, 3]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 4]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 3]",
"\"NO\""
],
[
"[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]",
"\"NO\""
],
[
"[100, 200], [200, 200]",
"\"YES\""
]
] |
[] |
In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
|
for i in lst2:
if i%2 == 0:
even += 1
if even >= odd:
return "YES"
return "NO"
|
[] |
SingleLineInfilling/HumanEval/110/L4
|
code_infilling
|
odd += 1
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
]
] |
def exchange(lst1, lst2):
"""In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
"""
odd = 0
even = 0
for i in lst1:
if i%2 == 1:
|
HumanEval_SingleLineInfillingLight
|
exchange
|
python
|
python
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
],
[
"[1, 2, 3, 4], [2, 1, 4, 3]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 4]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 3]",
"\"NO\""
],
[
"[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]",
"\"NO\""
],
[
"[100, 200], [200, 200]",
"\"YES\""
]
] |
[] |
In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
|
if i%2 == 0:
even += 1
if even >= odd:
return "YES"
return "NO"
|
[] |
SingleLineInfilling/HumanEval/110/L5
|
code_infilling
|
for i in lst2:
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
]
] |
def exchange(lst1, lst2):
"""In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
"""
odd = 0
even = 0
for i in lst1:
if i%2 == 1:
odd += 1
|
HumanEval_SingleLineInfillingLight
|
exchange
|
python
|
python
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
],
[
"[1, 2, 3, 4], [2, 1, 4, 3]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 4]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 3]",
"\"NO\""
],
[
"[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]",
"\"NO\""
],
[
"[100, 200], [200, 200]",
"\"YES\""
]
] |
[] |
In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
|
even += 1
if even >= odd:
return "YES"
return "NO"
|
[] |
SingleLineInfilling/HumanEval/110/L6
|
code_infilling
|
if i%2 == 0:
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
]
] |
def exchange(lst1, lst2):
"""In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
"""
odd = 0
even = 0
for i in lst1:
if i%2 == 1:
odd += 1
for i in lst2:
|
HumanEval_SingleLineInfillingLight
|
exchange
|
python
|
python
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
],
[
"[1, 2, 3, 4], [2, 1, 4, 3]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 4]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 3]",
"\"NO\""
],
[
"[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]",
"\"NO\""
],
[
"[100, 200], [200, 200]",
"\"YES\""
]
] |
[] |
In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
|
if even >= odd:
return "YES"
return "NO"
|
[] |
SingleLineInfilling/HumanEval/110/L7
|
code_infilling
|
even += 1
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
]
] |
def exchange(lst1, lst2):
"""In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
"""
odd = 0
even = 0
for i in lst1:
if i%2 == 1:
odd += 1
for i in lst2:
if i%2 == 0:
|
HumanEval_SingleLineInfillingLight
|
exchange
|
python
|
python
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
],
[
"[1, 2, 3, 4], [2, 1, 4, 3]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 4]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 3]",
"\"NO\""
],
[
"[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]",
"\"NO\""
],
[
"[100, 200], [200, 200]",
"\"YES\""
]
] |
[] |
In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
|
return "YES"
return "NO"
|
[] |
SingleLineInfilling/HumanEval/110/L8
|
code_infilling
|
if even >= odd:
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
]
] |
def exchange(lst1, lst2):
"""In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
"""
odd = 0
even = 0
for i in lst1:
if i%2 == 1:
odd += 1
for i in lst2:
if i%2 == 0:
even += 1
|
HumanEval_SingleLineInfillingLight
|
exchange
|
python
|
python
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
],
[
"[1, 2, 3, 4], [2, 1, 4, 3]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 4]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 3]",
"\"NO\""
],
[
"[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]",
"\"NO\""
],
[
"[100, 200], [200, 200]",
"\"YES\""
]
] |
[] |
In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
|
return "NO"
|
[] |
SingleLineInfilling/HumanEval/110/L9
|
code_infilling
|
return "YES"
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
]
] |
def exchange(lst1, lst2):
"""In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
"""
odd = 0
even = 0
for i in lst1:
if i%2 == 1:
odd += 1
for i in lst2:
if i%2 == 0:
even += 1
if even >= odd:
|
HumanEval_SingleLineInfillingLight
|
exchange
|
python
|
python
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
],
[
"[1, 2, 3, 4], [2, 1, 4, 3]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 4]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 3]",
"\"NO\""
],
[
"[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]",
"\"NO\""
],
[
"[100, 200], [200, 200]",
"\"YES\""
]
] |
[] |
In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
|
[] |
SingleLineInfilling/HumanEval/110/L10
|
code_infilling
|
return "NO"
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
]
] |
def exchange(lst1, lst2):
"""In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
"""
odd = 0
even = 0
for i in lst1:
if i%2 == 1:
odd += 1
for i in lst2:
if i%2 == 0:
even += 1
if even >= odd:
return "YES"
|
HumanEval_SingleLineInfillingLight
|
exchange
|
python
|
python
|
[
[
"[1, 2, 3, 4], [1, 2, 3, 4]",
"\"YES\""
],
[
"[1, 2, 3, 4], [1, 5, 3, 4]",
"\"NO\""
],
[
"[1, 2, 3, 4], [2, 1, 4, 3]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 4]",
"\"YES\""
],
[
"[5, 7, 3], [2, 6, 3]",
"\"NO\""
],
[
"[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]",
"\"NO\""
],
[
"[100, 200], [200, 200]",
"\"YES\""
]
] |
|
[] |
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
|
list1=test.split(" ")
t=0
for i in list1:
if(list1.count(i)>t) and i!='':
t=list1.count(i)
if t>0:
for i in list1:
if(list1.count(i)==t):
dict1[i]=t
return dict1
|
[] |
SingleLineInfilling/HumanEval/111/L0
|
code_infilling
|
dict1={}
|
[
[
"'a b c'",
"{'a': 1, 'b': 1, 'c': 1}"
],
[
"'a b b a'",
"{'a': 2, 'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"''",
"{}"
]
] |
def histogram(test):
"""Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
"""
|
HumanEval_SingleLineInfillingLight
|
histogram
|
python
|
python
|
[
[
"'a b b a'",
"{'a':2,'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'a b c d g'",
"{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"''",
"{}"
],
[
"'a'",
"{'a': 1}"
]
] |
[] |
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
|
t=0
for i in list1:
if(list1.count(i)>t) and i!='':
t=list1.count(i)
if t>0:
for i in list1:
if(list1.count(i)==t):
dict1[i]=t
return dict1
|
[] |
SingleLineInfilling/HumanEval/111/L1
|
code_infilling
|
list1=test.split(" ")
|
[
[
"'a b c'",
"{'a': 1, 'b': 1, 'c': 1}"
],
[
"'a b b a'",
"{'a': 2, 'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"''",
"{}"
]
] |
def histogram(test):
"""Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
"""
dict1={}
|
HumanEval_SingleLineInfillingLight
|
histogram
|
python
|
python
|
[
[
"'a b b a'",
"{'a':2,'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'a b c d g'",
"{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"''",
"{}"
],
[
"'a'",
"{'a': 1}"
]
] |
[] |
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
|
for i in list1:
if(list1.count(i)>t) and i!='':
t=list1.count(i)
if t>0:
for i in list1:
if(list1.count(i)==t):
dict1[i]=t
return dict1
|
[] |
SingleLineInfilling/HumanEval/111/L2
|
code_infilling
|
t=0
|
[
[
"'a b c'",
"{'a': 1, 'b': 1, 'c': 1}"
],
[
"'a b b a'",
"{'a': 2, 'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"''",
"{}"
]
] |
def histogram(test):
"""Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
"""
dict1={}
list1=test.split(" ")
|
HumanEval_SingleLineInfillingLight
|
histogram
|
python
|
python
|
[
[
"'a b b a'",
"{'a':2,'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'a b c d g'",
"{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"''",
"{}"
],
[
"'a'",
"{'a': 1}"
]
] |
[] |
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
|
if(list1.count(i)>t) and i!='':
t=list1.count(i)
if t>0:
for i in list1:
if(list1.count(i)==t):
dict1[i]=t
return dict1
|
[] |
SingleLineInfilling/HumanEval/111/L4
|
code_infilling
|
for i in list1:
|
[
[
"'a b c'",
"{'a': 1, 'b': 1, 'c': 1}"
],
[
"'a b b a'",
"{'a': 2, 'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"''",
"{}"
]
] |
def histogram(test):
"""Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
"""
dict1={}
list1=test.split(" ")
t=0
|
HumanEval_SingleLineInfillingLight
|
histogram
|
python
|
python
|
[
[
"'a b b a'",
"{'a':2,'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'a b c d g'",
"{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"''",
"{}"
],
[
"'a'",
"{'a': 1}"
]
] |
[] |
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
|
t=list1.count(i)
if t>0:
for i in list1:
if(list1.count(i)==t):
dict1[i]=t
return dict1
|
[] |
SingleLineInfilling/HumanEval/111/L5
|
code_infilling
|
if(list1.count(i)>t) and i!='':
|
[
[
"'a b c'",
"{'a': 1, 'b': 1, 'c': 1}"
],
[
"'a b b a'",
"{'a': 2, 'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"''",
"{}"
]
] |
def histogram(test):
"""Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
"""
dict1={}
list1=test.split(" ")
t=0
for i in list1:
|
HumanEval_SingleLineInfillingLight
|
histogram
|
python
|
python
|
[
[
"'a b b a'",
"{'a':2,'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'a b c d g'",
"{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"''",
"{}"
],
[
"'a'",
"{'a': 1}"
]
] |
[] |
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
|
if t>0:
for i in list1:
if(list1.count(i)==t):
dict1[i]=t
return dict1
|
[] |
SingleLineInfilling/HumanEval/111/L6
|
code_infilling
|
t=list1.count(i)
|
[
[
"'a b c'",
"{'a': 1, 'b': 1, 'c': 1}"
],
[
"'a b b a'",
"{'a': 2, 'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"''",
"{}"
]
] |
def histogram(test):
"""Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
"""
dict1={}
list1=test.split(" ")
t=0
for i in list1:
if(list1.count(i)>t) and i!='':
|
HumanEval_SingleLineInfillingLight
|
histogram
|
python
|
python
|
[
[
"'a b b a'",
"{'a':2,'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'a b c d g'",
"{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"''",
"{}"
],
[
"'a'",
"{'a': 1}"
]
] |
[] |
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
|
for i in list1:
if(list1.count(i)==t):
dict1[i]=t
return dict1
|
[] |
SingleLineInfilling/HumanEval/111/L7
|
code_infilling
|
if t>0:
|
[
[
"'a b c'",
"{'a': 1, 'b': 1, 'c': 1}"
],
[
"'a b b a'",
"{'a': 2, 'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"''",
"{}"
]
] |
def histogram(test):
"""Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
"""
dict1={}
list1=test.split(" ")
t=0
for i in list1:
if(list1.count(i)>t) and i!='':
t=list1.count(i)
|
HumanEval_SingleLineInfillingLight
|
histogram
|
python
|
python
|
[
[
"'a b b a'",
"{'a':2,'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'a b c d g'",
"{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"''",
"{}"
],
[
"'a'",
"{'a': 1}"
]
] |
[] |
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
|
if(list1.count(i)==t):
dict1[i]=t
return dict1
|
[] |
SingleLineInfilling/HumanEval/111/L8
|
code_infilling
|
for i in list1:
|
[
[
"'a b c'",
"{'a': 1, 'b': 1, 'c': 1}"
],
[
"'a b b a'",
"{'a': 2, 'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"''",
"{}"
]
] |
def histogram(test):
"""Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
"""
dict1={}
list1=test.split(" ")
t=0
for i in list1:
if(list1.count(i)>t) and i!='':
t=list1.count(i)
if t>0:
|
HumanEval_SingleLineInfillingLight
|
histogram
|
python
|
python
|
[
[
"'a b b a'",
"{'a':2,'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'a b c d g'",
"{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"''",
"{}"
],
[
"'a'",
"{'a': 1}"
]
] |
[] |
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
|
dict1[i]=t
return dict1
|
[] |
SingleLineInfilling/HumanEval/111/L9
|
code_infilling
|
if(list1.count(i)==t):
|
[
[
"'a b c'",
"{'a': 1, 'b': 1, 'c': 1}"
],
[
"'a b b a'",
"{'a': 2, 'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"''",
"{}"
]
] |
def histogram(test):
"""Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
"""
dict1={}
list1=test.split(" ")
t=0
for i in list1:
if(list1.count(i)>t) and i!='':
t=list1.count(i)
if t>0:
for i in list1:
|
HumanEval_SingleLineInfillingLight
|
histogram
|
python
|
python
|
[
[
"'a b b a'",
"{'a':2,'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'a b c d g'",
"{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"''",
"{}"
],
[
"'a'",
"{'a': 1}"
]
] |
[] |
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
|
return dict1
|
[] |
SingleLineInfilling/HumanEval/111/L11
|
code_infilling
|
dict1[i]=t
|
[
[
"'a b c'",
"{'a': 1, 'b': 1, 'c': 1}"
],
[
"'a b b a'",
"{'a': 2, 'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"''",
"{}"
]
] |
def histogram(test):
"""Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
"""
dict1={}
list1=test.split(" ")
t=0
for i in list1:
if(list1.count(i)>t) and i!='':
t=list1.count(i)
if t>0:
for i in list1:
if(list1.count(i)==t):
|
HumanEval_SingleLineInfillingLight
|
histogram
|
python
|
python
|
[
[
"'a b b a'",
"{'a':2,'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'a b c d g'",
"{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"''",
"{}"
],
[
"'a'",
"{'a': 1}"
]
] |
[] |
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
|
[] |
SingleLineInfilling/HumanEval/111/L12
|
code_infilling
|
return dict1
|
[
[
"'a b c'",
"{'a': 1, 'b': 1, 'c': 1}"
],
[
"'a b b a'",
"{'a': 2, 'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"''",
"{}"
]
] |
def histogram(test):
"""Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
"""
dict1={}
list1=test.split(" ")
t=0
for i in list1:
if(list1.count(i)>t) and i!='':
t=list1.count(i)
if t>0:
for i in list1:
if(list1.count(i)==t):
dict1[i]=t
|
HumanEval_SingleLineInfillingLight
|
histogram
|
python
|
python
|
[
[
"'a b b a'",
"{'a':2,'b': 2}"
],
[
"'a b c a b'",
"{'a': 2, 'b': 2}"
],
[
"'a b c d g'",
"{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"'b b b b a'",
"{'b': 4}"
],
[
"'r t g'",
"{'r': 1,'t': 1,'g': 1}"
],
[
"''",
"{}"
],
[
"'a'",
"{'a': 1}"
]
] |
|
[] |
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and True/False for the check.
|
return (s,s[::-1] == s)
|
[] |
SingleLineInfilling/HumanEval/112/L0
|
code_infilling
|
s = ''.join([char for char in s if char not in c])
|
[
[
"'abcde', 'ae'",
"('bcd', False)"
],
[
"'abcdef', 'b'",
"('acdef',False)"
],
[
"'abcdedcba', 'ab'",
"('cdedc',True)"
]
] |
def reverse_delete(s,c):
"""Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and True/False for the check.
"""
|
HumanEval_SingleLineInfillingLight
|
reverse_delete
|
python
|
python
|
[
[
"\"abcde\", \"ae\"",
"('bcd',False)"
],
[
"\"abcdef\", \"b\"",
"('acdef',False)"
],
[
"\"abcdedcba\", \"ab\"",
"('cdedc',True)"
],
[
"\"dwik\", \"w\"",
"('dik',False)"
],
[
"\"a\", \"a\"",
"('',True)"
],
[
"\"abcdedcba\", \"\"",
"('abcdedcba',True)"
],
[
"\"abcdedcba\", \"v\"",
"('abcdedcba',True)"
],
[
"\"vabba\", \"v\"",
"('abba',True)"
],
[
"\"mamma\", \"mia\"",
"(\"\", True)"
]
] |
[] |
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and True/False for the check.
|
[] |
SingleLineInfilling/HumanEval/112/L1
|
code_infilling
|
return (s,s[::-1] == s)
|
[
[
"'abcde', 'ae'",
"('bcd', False)"
],
[
"'abcdef', 'b'",
"('acdef',False)"
],
[
"'abcdedcba', 'ab'",
"('cdedc',True)"
]
] |
def reverse_delete(s,c):
"""Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and True/False for the check.
"""
s = ''.join([char for char in s if char not in c])
|
HumanEval_SingleLineInfillingLight
|
reverse_delete
|
python
|
python
|
[
[
"\"abcde\", \"ae\"",
"('bcd',False)"
],
[
"\"abcdef\", \"b\"",
"('acdef',False)"
],
[
"\"abcdedcba\", \"ab\"",
"('cdedc',True)"
],
[
"\"dwik\", \"w\"",
"('dik',False)"
],
[
"\"a\", \"a\"",
"('',True)"
],
[
"\"abcdedcba\", \"\"",
"('abcdedcba',True)"
],
[
"\"abcdedcba\", \"v\"",
"('abcdedcba',True)"
],
[
"\"vabba\", \"v\"",
"('abba',True)"
],
[
"\"mamma\", \"mia\"",
"(\"\", True)"
]
] |
|
[] |
Given a list of strings, where each string consists of only digits, return a list.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
|
for arr in lst:
n = sum(int(d)%2==1 for d in arr)
res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
return res
|
[] |
SingleLineInfilling/HumanEval/113/L0
|
code_infilling
|
res = []
|
[
[
"['1234567']",
"[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]"
],
[
"['3',\"11111111\"]",
"[\"the number of odd elements 1n the str1ng 1 of the 1nput.\","
]
] |
def odd_count(lst):
"""Given a list of strings, where each string consists of only digits, return a list.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
"""
|
HumanEval_SingleLineInfillingLight
|
odd_count
|
python
|
python
|
[
[
"['1234567']",
"[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]"
],
[
"['3',\"11111111\"]",
"[\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]"
],
[
"['271', '137', '314']",
"[\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.'\n ]"
]
] |
[] |
Given a list of strings, where each string consists of only digits, return a list.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
|
n = sum(int(d)%2==1 for d in arr)
res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
return res
|
[] |
SingleLineInfilling/HumanEval/113/L1
|
code_infilling
|
for arr in lst:
|
[
[
"['1234567']",
"[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]"
],
[
"['3',\"11111111\"]",
"[\"the number of odd elements 1n the str1ng 1 of the 1nput.\","
]
] |
def odd_count(lst):
"""Given a list of strings, where each string consists of only digits, return a list.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
"""
res = []
|
HumanEval_SingleLineInfillingLight
|
odd_count
|
python
|
python
|
[
[
"['1234567']",
"[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]"
],
[
"['3',\"11111111\"]",
"[\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]"
],
[
"['271', '137', '314']",
"[\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.'\n ]"
]
] |
[] |
Given a list of strings, where each string consists of only digits, return a list.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
|
res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
return res
|
[] |
SingleLineInfilling/HumanEval/113/L2
|
code_infilling
|
n = sum(int(d)%2==1 for d in arr)
|
[
[
"['1234567']",
"[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]"
],
[
"['3',\"11111111\"]",
"[\"the number of odd elements 1n the str1ng 1 of the 1nput.\","
]
] |
def odd_count(lst):
"""Given a list of strings, where each string consists of only digits, return a list.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
"""
res = []
for arr in lst:
|
HumanEval_SingleLineInfillingLight
|
odd_count
|
python
|
python
|
[
[
"['1234567']",
"[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]"
],
[
"['3',\"11111111\"]",
"[\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]"
],
[
"['271', '137', '314']",
"[\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.'\n ]"
]
] |
[] |
Given a list of strings, where each string consists of only digits, return a list.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
|
return res
|
[] |
SingleLineInfilling/HumanEval/113/L3
|
code_infilling
|
res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
|
[
[
"['1234567']",
"[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]"
],
[
"['3',\"11111111\"]",
"[\"the number of odd elements 1n the str1ng 1 of the 1nput.\","
]
] |
def odd_count(lst):
"""Given a list of strings, where each string consists of only digits, return a list.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
"""
res = []
for arr in lst:
n = sum(int(d)%2==1 for d in arr)
|
HumanEval_SingleLineInfillingLight
|
odd_count
|
python
|
python
|
[
[
"['1234567']",
"[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]"
],
[
"['3',\"11111111\"]",
"[\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]"
],
[
"['271', '137', '314']",
"[\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.'\n ]"
]
] |
[] |
Given a list of strings, where each string consists of only digits, return a list.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
|
[] |
SingleLineInfilling/HumanEval/113/L4
|
code_infilling
|
return res
|
[
[
"['1234567']",
"[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]"
],
[
"['3',\"11111111\"]",
"[\"the number of odd elements 1n the str1ng 1 of the 1nput.\","
]
] |
def odd_count(lst):
"""Given a list of strings, where each string consists of only digits, return a list.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
"""
res = []
for arr in lst:
n = sum(int(d)%2==1 for d in arr)
res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
|
HumanEval_SingleLineInfillingLight
|
odd_count
|
python
|
python
|
[
[
"['1234567']",
"[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]"
],
[
"['3',\"11111111\"]",
"[\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]"
],
[
"['271', '137', '314']",
"[\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.'\n ]"
]
] |
|
[] |
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
|
s = 0
for num in nums:
s += -num
if (s < 0):
s = 0
max_sum = max(s, max_sum)
if max_sum == 0:
max_sum = max(-i for i in nums)
min_sum = -max_sum
return min_sum
|
[] |
SingleLineInfilling/HumanEval/114/L0
|
code_infilling
|
max_sum = 0
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
]
] |
def minSubArraySum(nums):
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
"""
|
HumanEval_SingleLineInfillingLight
|
minSubArraySum
|
python
|
python
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
],
[
"[-1, -2, -3, 2, -10]",
"-14"
],
[
"[-9999999999999999]",
"-9999999999999999"
],
[
"[0, 10, 20, 1000000]",
"0"
],
[
"[-1, -2, -3, 10, -5]",
"-6"
],
[
"[100, -1, -2, -3, 10, -5]",
"-6"
],
[
"[10, 11, 13, 8, 3, 4]",
"3"
],
[
"[100, -33, 32, -1, 0, -2]",
"-33"
],
[
"[-10]",
"-10"
],
[
"[7]",
"7"
],
[
"[1, -1]",
"-1"
]
] |
[] |
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
|
for num in nums:
s += -num
if (s < 0):
s = 0
max_sum = max(s, max_sum)
if max_sum == 0:
max_sum = max(-i for i in nums)
min_sum = -max_sum
return min_sum
|
[] |
SingleLineInfilling/HumanEval/114/L1
|
code_infilling
|
s = 0
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
]
] |
def minSubArraySum(nums):
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
"""
max_sum = 0
|
HumanEval_SingleLineInfillingLight
|
minSubArraySum
|
python
|
python
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
],
[
"[-1, -2, -3, 2, -10]",
"-14"
],
[
"[-9999999999999999]",
"-9999999999999999"
],
[
"[0, 10, 20, 1000000]",
"0"
],
[
"[-1, -2, -3, 10, -5]",
"-6"
],
[
"[100, -1, -2, -3, 10, -5]",
"-6"
],
[
"[10, 11, 13, 8, 3, 4]",
"3"
],
[
"[100, -33, 32, -1, 0, -2]",
"-33"
],
[
"[-10]",
"-10"
],
[
"[7]",
"7"
],
[
"[1, -1]",
"-1"
]
] |
[] |
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
|
s += -num
if (s < 0):
s = 0
max_sum = max(s, max_sum)
if max_sum == 0:
max_sum = max(-i for i in nums)
min_sum = -max_sum
return min_sum
|
[] |
SingleLineInfilling/HumanEval/114/L2
|
code_infilling
|
for num in nums:
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
]
] |
def minSubArraySum(nums):
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
"""
max_sum = 0
s = 0
|
HumanEval_SingleLineInfillingLight
|
minSubArraySum
|
python
|
python
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
],
[
"[-1, -2, -3, 2, -10]",
"-14"
],
[
"[-9999999999999999]",
"-9999999999999999"
],
[
"[0, 10, 20, 1000000]",
"0"
],
[
"[-1, -2, -3, 10, -5]",
"-6"
],
[
"[100, -1, -2, -3, 10, -5]",
"-6"
],
[
"[10, 11, 13, 8, 3, 4]",
"3"
],
[
"[100, -33, 32, -1, 0, -2]",
"-33"
],
[
"[-10]",
"-10"
],
[
"[7]",
"7"
],
[
"[1, -1]",
"-1"
]
] |
[] |
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
|
if (s < 0):
s = 0
max_sum = max(s, max_sum)
if max_sum == 0:
max_sum = max(-i for i in nums)
min_sum = -max_sum
return min_sum
|
[] |
SingleLineInfilling/HumanEval/114/L3
|
code_infilling
|
s += -num
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
]
] |
def minSubArraySum(nums):
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
"""
max_sum = 0
s = 0
for num in nums:
|
HumanEval_SingleLineInfillingLight
|
minSubArraySum
|
python
|
python
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
],
[
"[-1, -2, -3, 2, -10]",
"-14"
],
[
"[-9999999999999999]",
"-9999999999999999"
],
[
"[0, 10, 20, 1000000]",
"0"
],
[
"[-1, -2, -3, 10, -5]",
"-6"
],
[
"[100, -1, -2, -3, 10, -5]",
"-6"
],
[
"[10, 11, 13, 8, 3, 4]",
"3"
],
[
"[100, -33, 32, -1, 0, -2]",
"-33"
],
[
"[-10]",
"-10"
],
[
"[7]",
"7"
],
[
"[1, -1]",
"-1"
]
] |
[] |
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
|
s = 0
max_sum = max(s, max_sum)
if max_sum == 0:
max_sum = max(-i for i in nums)
min_sum = -max_sum
return min_sum
|
[] |
SingleLineInfilling/HumanEval/114/L4
|
code_infilling
|
if (s < 0):
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
]
] |
def minSubArraySum(nums):
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
"""
max_sum = 0
s = 0
for num in nums:
s += -num
|
HumanEval_SingleLineInfillingLight
|
minSubArraySum
|
python
|
python
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
],
[
"[-1, -2, -3, 2, -10]",
"-14"
],
[
"[-9999999999999999]",
"-9999999999999999"
],
[
"[0, 10, 20, 1000000]",
"0"
],
[
"[-1, -2, -3, 10, -5]",
"-6"
],
[
"[100, -1, -2, -3, 10, -5]",
"-6"
],
[
"[10, 11, 13, 8, 3, 4]",
"3"
],
[
"[100, -33, 32, -1, 0, -2]",
"-33"
],
[
"[-10]",
"-10"
],
[
"[7]",
"7"
],
[
"[1, -1]",
"-1"
]
] |
[] |
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
|
max_sum = max(s, max_sum)
if max_sum == 0:
max_sum = max(-i for i in nums)
min_sum = -max_sum
return min_sum
|
[] |
SingleLineInfilling/HumanEval/114/L5
|
code_infilling
|
s = 0
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
]
] |
def minSubArraySum(nums):
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
"""
max_sum = 0
s = 0
for num in nums:
s += -num
if (s < 0):
|
HumanEval_SingleLineInfillingLight
|
minSubArraySum
|
python
|
python
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
],
[
"[-1, -2, -3, 2, -10]",
"-14"
],
[
"[-9999999999999999]",
"-9999999999999999"
],
[
"[0, 10, 20, 1000000]",
"0"
],
[
"[-1, -2, -3, 10, -5]",
"-6"
],
[
"[100, -1, -2, -3, 10, -5]",
"-6"
],
[
"[10, 11, 13, 8, 3, 4]",
"3"
],
[
"[100, -33, 32, -1, 0, -2]",
"-33"
],
[
"[-10]",
"-10"
],
[
"[7]",
"7"
],
[
"[1, -1]",
"-1"
]
] |
[] |
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
|
if max_sum == 0:
max_sum = max(-i for i in nums)
min_sum = -max_sum
return min_sum
|
[] |
SingleLineInfilling/HumanEval/114/L6
|
code_infilling
|
max_sum = max(s, max_sum)
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
]
] |
def minSubArraySum(nums):
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
"""
max_sum = 0
s = 0
for num in nums:
s += -num
if (s < 0):
s = 0
|
HumanEval_SingleLineInfillingLight
|
minSubArraySum
|
python
|
python
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
],
[
"[-1, -2, -3, 2, -10]",
"-14"
],
[
"[-9999999999999999]",
"-9999999999999999"
],
[
"[0, 10, 20, 1000000]",
"0"
],
[
"[-1, -2, -3, 10, -5]",
"-6"
],
[
"[100, -1, -2, -3, 10, -5]",
"-6"
],
[
"[10, 11, 13, 8, 3, 4]",
"3"
],
[
"[100, -33, 32, -1, 0, -2]",
"-33"
],
[
"[-10]",
"-10"
],
[
"[7]",
"7"
],
[
"[1, -1]",
"-1"
]
] |
[] |
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
|
max_sum = max(-i for i in nums)
min_sum = -max_sum
return min_sum
|
[] |
SingleLineInfilling/HumanEval/114/L7
|
code_infilling
|
if max_sum == 0:
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
]
] |
def minSubArraySum(nums):
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
"""
max_sum = 0
s = 0
for num in nums:
s += -num
if (s < 0):
s = 0
max_sum = max(s, max_sum)
|
HumanEval_SingleLineInfillingLight
|
minSubArraySum
|
python
|
python
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
],
[
"[-1, -2, -3, 2, -10]",
"-14"
],
[
"[-9999999999999999]",
"-9999999999999999"
],
[
"[0, 10, 20, 1000000]",
"0"
],
[
"[-1, -2, -3, 10, -5]",
"-6"
],
[
"[100, -1, -2, -3, 10, -5]",
"-6"
],
[
"[10, 11, 13, 8, 3, 4]",
"3"
],
[
"[100, -33, 32, -1, 0, -2]",
"-33"
],
[
"[-10]",
"-10"
],
[
"[7]",
"7"
],
[
"[1, -1]",
"-1"
]
] |
[] |
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
|
min_sum = -max_sum
return min_sum
|
[] |
SingleLineInfilling/HumanEval/114/L8
|
code_infilling
|
max_sum = max(-i for i in nums)
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
]
] |
def minSubArraySum(nums):
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
"""
max_sum = 0
s = 0
for num in nums:
s += -num
if (s < 0):
s = 0
max_sum = max(s, max_sum)
if max_sum == 0:
|
HumanEval_SingleLineInfillingLight
|
minSubArraySum
|
python
|
python
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
],
[
"[-1, -2, -3, 2, -10]",
"-14"
],
[
"[-9999999999999999]",
"-9999999999999999"
],
[
"[0, 10, 20, 1000000]",
"0"
],
[
"[-1, -2, -3, 10, -5]",
"-6"
],
[
"[100, -1, -2, -3, 10, -5]",
"-6"
],
[
"[10, 11, 13, 8, 3, 4]",
"3"
],
[
"[100, -33, 32, -1, 0, -2]",
"-33"
],
[
"[-10]",
"-10"
],
[
"[7]",
"7"
],
[
"[1, -1]",
"-1"
]
] |
[] |
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
|
return min_sum
|
[] |
SingleLineInfilling/HumanEval/114/L9
|
code_infilling
|
min_sum = -max_sum
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
]
] |
def minSubArraySum(nums):
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
"""
max_sum = 0
s = 0
for num in nums:
s += -num
if (s < 0):
s = 0
max_sum = max(s, max_sum)
if max_sum == 0:
max_sum = max(-i for i in nums)
|
HumanEval_SingleLineInfillingLight
|
minSubArraySum
|
python
|
python
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
],
[
"[-1, -2, -3, 2, -10]",
"-14"
],
[
"[-9999999999999999]",
"-9999999999999999"
],
[
"[0, 10, 20, 1000000]",
"0"
],
[
"[-1, -2, -3, 10, -5]",
"-6"
],
[
"[100, -1, -2, -3, 10, -5]",
"-6"
],
[
"[10, 11, 13, 8, 3, 4]",
"3"
],
[
"[100, -33, 32, -1, 0, -2]",
"-33"
],
[
"[-10]",
"-10"
],
[
"[7]",
"7"
],
[
"[1, -1]",
"-1"
]
] |
[] |
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
|
[] |
SingleLineInfilling/HumanEval/114/L10
|
code_infilling
|
return min_sum
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
]
] |
def minSubArraySum(nums):
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
"""
max_sum = 0
s = 0
for num in nums:
s += -num
if (s < 0):
s = 0
max_sum = max(s, max_sum)
if max_sum == 0:
max_sum = max(-i for i in nums)
min_sum = -max_sum
|
HumanEval_SingleLineInfillingLight
|
minSubArraySum
|
python
|
python
|
[
[
"[2, 3, 4, 1, 2, 4]",
"1"
],
[
"[-1, -2, -3]",
"-6"
],
[
"[-1, -2, -3, 2, -10]",
"-14"
],
[
"[-9999999999999999]",
"-9999999999999999"
],
[
"[0, 10, 20, 1000000]",
"0"
],
[
"[-1, -2, -3, 10, -5]",
"-6"
],
[
"[100, -1, -2, -3, 10, -5]",
"-6"
],
[
"[10, 11, 13, 8, 3, 4]",
"3"
],
[
"[100, -33, 32, -1, 0, -2]",
"-33"
],
[
"[-10]",
"-10"
],
[
"[7]",
"7"
],
[
"[1, -1]",
"-1"
]
] |
|
[
"import math"
] |
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
|
[] |
SingleLineInfilling/HumanEval/115/L0
|
code_infilling
|
return sum([math.ceil(sum(arr)/capacity) for arr in grid])
|
[
[
"[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1",
"6"
],
[
"[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2",
"5"
],
[
"[[0,0,0], [0,0,0]], 5",
"0"
]
] |
def max_fill(grid, capacity):
import math
"""
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
"""
|
HumanEval_SingleLineInfillingLight
|
max_fill
|
python
|
python
|
[
[
"[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1",
"6"
],
[
"[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2",
"5"
],
[
"[[0,0,0], [0,0,0]], 5",
"0"
],
[
"[[1,1,1,1], [1,1,1,1]], 2",
"4"
],
[
"[[1,1,1,1], [1,1,1,1]], 9",
"2"
]
] |
|
[] |
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
|
[] |
SingleLineInfilling/HumanEval/116/L0
|
code_infilling
|
return sorted(sorted(arr), key=lambda x: bin(x)[2:].count('1'))
|
[
[
"[1, 5, 2, 3, 4]",
"[1, 2, 3, 4, 5]"
],
[
"[-2, -3, -4, -5, -6]",
"[-6, -5, -4, -3, -2]"
]
] |
def sort_array(arr):
"""
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
"""
|
HumanEval_SingleLineInfillingLight
|
sort_array
|
python
|
python
|
[
[
"[1,5,2,3,4]",
"[1, 2, 4, 3, 5]"
],
[
"[-2,-3,-4,-5,-6]",
"[-4, -2, -6, -5, -3]"
],
[
"[1,0,2,3,4]",
"[0, 1, 2, 4, 3]"
],
[
"[]",
"[]"
],
[
"[2,5,77,4,5,3,5,7,2,3,4]",
"[2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]"
],
[
"[3,6,44,12,32,5]",
"[32, 3, 5, 6, 12, 44]"
],
[
"[2,4,8,16,32]",
"[2, 4, 8, 16, 32]"
],
[
"[2,4,8,16,32]",
"[2, 4, 8, 16, 32]"
]
] |
|
[] |
Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
|
for word in s.split():
n_consonants = 0
for i in range(0, len(word)):
if word[i].lower() not in ["a","e","i","o","u"]:
n_consonants += 1
if n_consonants == n:
result.append(word)
return result
|
[] |
SingleLineInfilling/HumanEval/117/L0
|
code_infilling
|
result = []
|
[
[
"\"Mary had a little lamb\", 4",
"> [\"little\"]"
],
[
"\"Mary had a little lamb\", 3",
"> [\"Mary\", \"lamb\"]"
],
[
"\"simple white space\", 2",
"> []"
],
[
"\"Hello world\", 4",
"> [\"world\"]"
],
[
"\"Uncle sam\", 3",
"> [\"Uncle\"]"
]
] |
def select_words(s, n):
"""Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
"""
|
HumanEval_SingleLineInfillingLight
|
select_words
|
python
|
python
|
[
[
"\"Mary had a little lamb\", 4",
"[\"little\"]"
],
[
"\"Mary had a little lamb\", 3",
"[\"Mary\", \"lamb\"]"
],
[
"\"simple white space\", 2",
"[]"
],
[
"\"Hello world\", 4",
"[\"world\"]"
],
[
"\"Uncle sam\", 3",
"[\"Uncle\"]"
],
[
"\"\", 4",
"[]"
],
[
"\"a b c d e f\", 1",
"[\"b\", \"c\", \"d\", \"f\"]"
]
] |
[] |
Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
|
n_consonants = 0
for i in range(0, len(word)):
if word[i].lower() not in ["a","e","i","o","u"]:
n_consonants += 1
if n_consonants == n:
result.append(word)
return result
|
[] |
SingleLineInfilling/HumanEval/117/L1
|
code_infilling
|
for word in s.split():
|
[
[
"\"Mary had a little lamb\", 4",
"> [\"little\"]"
],
[
"\"Mary had a little lamb\", 3",
"> [\"Mary\", \"lamb\"]"
],
[
"\"simple white space\", 2",
"> []"
],
[
"\"Hello world\", 4",
"> [\"world\"]"
],
[
"\"Uncle sam\", 3",
"> [\"Uncle\"]"
]
] |
def select_words(s, n):
"""Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
"""
result = []
|
HumanEval_SingleLineInfillingLight
|
select_words
|
python
|
python
|
[
[
"\"Mary had a little lamb\", 4",
"[\"little\"]"
],
[
"\"Mary had a little lamb\", 3",
"[\"Mary\", \"lamb\"]"
],
[
"\"simple white space\", 2",
"[]"
],
[
"\"Hello world\", 4",
"[\"world\"]"
],
[
"\"Uncle sam\", 3",
"[\"Uncle\"]"
],
[
"\"\", 4",
"[]"
],
[
"\"a b c d e f\", 1",
"[\"b\", \"c\", \"d\", \"f\"]"
]
] |
[] |
Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
|
for i in range(0, len(word)):
if word[i].lower() not in ["a","e","i","o","u"]:
n_consonants += 1
if n_consonants == n:
result.append(word)
return result
|
[] |
SingleLineInfilling/HumanEval/117/L2
|
code_infilling
|
n_consonants = 0
|
[
[
"\"Mary had a little lamb\", 4",
"> [\"little\"]"
],
[
"\"Mary had a little lamb\", 3",
"> [\"Mary\", \"lamb\"]"
],
[
"\"simple white space\", 2",
"> []"
],
[
"\"Hello world\", 4",
"> [\"world\"]"
],
[
"\"Uncle sam\", 3",
"> [\"Uncle\"]"
]
] |
def select_words(s, n):
"""Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
"""
result = []
for word in s.split():
|
HumanEval_SingleLineInfillingLight
|
select_words
|
python
|
python
|
[
[
"\"Mary had a little lamb\", 4",
"[\"little\"]"
],
[
"\"Mary had a little lamb\", 3",
"[\"Mary\", \"lamb\"]"
],
[
"\"simple white space\", 2",
"[]"
],
[
"\"Hello world\", 4",
"[\"world\"]"
],
[
"\"Uncle sam\", 3",
"[\"Uncle\"]"
],
[
"\"\", 4",
"[]"
],
[
"\"a b c d e f\", 1",
"[\"b\", \"c\", \"d\", \"f\"]"
]
] |
[] |
Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
|
if word[i].lower() not in ["a","e","i","o","u"]:
n_consonants += 1
if n_consonants == n:
result.append(word)
return result
|
[] |
SingleLineInfilling/HumanEval/117/L3
|
code_infilling
|
for i in range(0, len(word)):
|
[
[
"\"Mary had a little lamb\", 4",
"> [\"little\"]"
],
[
"\"Mary had a little lamb\", 3",
"> [\"Mary\", \"lamb\"]"
],
[
"\"simple white space\", 2",
"> []"
],
[
"\"Hello world\", 4",
"> [\"world\"]"
],
[
"\"Uncle sam\", 3",
"> [\"Uncle\"]"
]
] |
def select_words(s, n):
"""Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
"""
result = []
for word in s.split():
n_consonants = 0
|
HumanEval_SingleLineInfillingLight
|
select_words
|
python
|
python
|
[
[
"\"Mary had a little lamb\", 4",
"[\"little\"]"
],
[
"\"Mary had a little lamb\", 3",
"[\"Mary\", \"lamb\"]"
],
[
"\"simple white space\", 2",
"[]"
],
[
"\"Hello world\", 4",
"[\"world\"]"
],
[
"\"Uncle sam\", 3",
"[\"Uncle\"]"
],
[
"\"\", 4",
"[]"
],
[
"\"a b c d e f\", 1",
"[\"b\", \"c\", \"d\", \"f\"]"
]
] |
[] |
Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
|
n_consonants += 1
if n_consonants == n:
result.append(word)
return result
|
[] |
SingleLineInfilling/HumanEval/117/L4
|
code_infilling
|
if word[i].lower() not in ["a","e","i","o","u"]:
|
[
[
"\"Mary had a little lamb\", 4",
"> [\"little\"]"
],
[
"\"Mary had a little lamb\", 3",
"> [\"Mary\", \"lamb\"]"
],
[
"\"simple white space\", 2",
"> []"
],
[
"\"Hello world\", 4",
"> [\"world\"]"
],
[
"\"Uncle sam\", 3",
"> [\"Uncle\"]"
]
] |
def select_words(s, n):
"""Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
"""
result = []
for word in s.split():
n_consonants = 0
for i in range(0, len(word)):
|
HumanEval_SingleLineInfillingLight
|
select_words
|
python
|
python
|
[
[
"\"Mary had a little lamb\", 4",
"[\"little\"]"
],
[
"\"Mary had a little lamb\", 3",
"[\"Mary\", \"lamb\"]"
],
[
"\"simple white space\", 2",
"[]"
],
[
"\"Hello world\", 4",
"[\"world\"]"
],
[
"\"Uncle sam\", 3",
"[\"Uncle\"]"
],
[
"\"\", 4",
"[]"
],
[
"\"a b c d e f\", 1",
"[\"b\", \"c\", \"d\", \"f\"]"
]
] |
[] |
Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
|
if n_consonants == n:
result.append(word)
return result
|
[] |
SingleLineInfilling/HumanEval/117/L5
|
code_infilling
|
n_consonants += 1
|
[
[
"\"Mary had a little lamb\", 4",
"> [\"little\"]"
],
[
"\"Mary had a little lamb\", 3",
"> [\"Mary\", \"lamb\"]"
],
[
"\"simple white space\", 2",
"> []"
],
[
"\"Hello world\", 4",
"> [\"world\"]"
],
[
"\"Uncle sam\", 3",
"> [\"Uncle\"]"
]
] |
def select_words(s, n):
"""Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
"""
result = []
for word in s.split():
n_consonants = 0
for i in range(0, len(word)):
if word[i].lower() not in ["a","e","i","o","u"]:
|
HumanEval_SingleLineInfillingLight
|
select_words
|
python
|
python
|
[
[
"\"Mary had a little lamb\", 4",
"[\"little\"]"
],
[
"\"Mary had a little lamb\", 3",
"[\"Mary\", \"lamb\"]"
],
[
"\"simple white space\", 2",
"[]"
],
[
"\"Hello world\", 4",
"[\"world\"]"
],
[
"\"Uncle sam\", 3",
"[\"Uncle\"]"
],
[
"\"\", 4",
"[]"
],
[
"\"a b c d e f\", 1",
"[\"b\", \"c\", \"d\", \"f\"]"
]
] |
[] |
Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
|
result.append(word)
return result
|
[] |
SingleLineInfilling/HumanEval/117/L6
|
code_infilling
|
if n_consonants == n:
|
[
[
"\"Mary had a little lamb\", 4",
"> [\"little\"]"
],
[
"\"Mary had a little lamb\", 3",
"> [\"Mary\", \"lamb\"]"
],
[
"\"simple white space\", 2",
"> []"
],
[
"\"Hello world\", 4",
"> [\"world\"]"
],
[
"\"Uncle sam\", 3",
"> [\"Uncle\"]"
]
] |
def select_words(s, n):
"""Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
"""
result = []
for word in s.split():
n_consonants = 0
for i in range(0, len(word)):
if word[i].lower() not in ["a","e","i","o","u"]:
n_consonants += 1
|
HumanEval_SingleLineInfillingLight
|
select_words
|
python
|
python
|
[
[
"\"Mary had a little lamb\", 4",
"[\"little\"]"
],
[
"\"Mary had a little lamb\", 3",
"[\"Mary\", \"lamb\"]"
],
[
"\"simple white space\", 2",
"[]"
],
[
"\"Hello world\", 4",
"[\"world\"]"
],
[
"\"Uncle sam\", 3",
"[\"Uncle\"]"
],
[
"\"\", 4",
"[]"
],
[
"\"a b c d e f\", 1",
"[\"b\", \"c\", \"d\", \"f\"]"
]
] |
[] |
Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
|
return result
|
[] |
SingleLineInfilling/HumanEval/117/L7
|
code_infilling
|
result.append(word)
|
[
[
"\"Mary had a little lamb\", 4",
"> [\"little\"]"
],
[
"\"Mary had a little lamb\", 3",
"> [\"Mary\", \"lamb\"]"
],
[
"\"simple white space\", 2",
"> []"
],
[
"\"Hello world\", 4",
"> [\"world\"]"
],
[
"\"Uncle sam\", 3",
"> [\"Uncle\"]"
]
] |
def select_words(s, n):
"""Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
"""
result = []
for word in s.split():
n_consonants = 0
for i in range(0, len(word)):
if word[i].lower() not in ["a","e","i","o","u"]:
n_consonants += 1
if n_consonants == n:
|
HumanEval_SingleLineInfillingLight
|
select_words
|
python
|
python
|
[
[
"\"Mary had a little lamb\", 4",
"[\"little\"]"
],
[
"\"Mary had a little lamb\", 3",
"[\"Mary\", \"lamb\"]"
],
[
"\"simple white space\", 2",
"[]"
],
[
"\"Hello world\", 4",
"[\"world\"]"
],
[
"\"Uncle sam\", 3",
"[\"Uncle\"]"
],
[
"\"\", 4",
"[]"
],
[
"\"a b c d e f\", 1",
"[\"b\", \"c\", \"d\", \"f\"]"
]
] |
[] |
Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
|
[] |
SingleLineInfilling/HumanEval/117/L8
|
code_infilling
|
return result
|
[
[
"\"Mary had a little lamb\", 4",
"> [\"little\"]"
],
[
"\"Mary had a little lamb\", 3",
"> [\"Mary\", \"lamb\"]"
],
[
"\"simple white space\", 2",
"> []"
],
[
"\"Hello world\", 4",
"> [\"world\"]"
],
[
"\"Uncle sam\", 3",
"> [\"Uncle\"]"
]
] |
def select_words(s, n):
"""Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input string contains only letters and spaces.
"""
result = []
for word in s.split():
n_consonants = 0
for i in range(0, len(word)):
if word[i].lower() not in ["a","e","i","o","u"]:
n_consonants += 1
if n_consonants == n:
result.append(word)
|
HumanEval_SingleLineInfillingLight
|
select_words
|
python
|
python
|
[
[
"\"Mary had a little lamb\", 4",
"[\"little\"]"
],
[
"\"Mary had a little lamb\", 3",
"[\"Mary\", \"lamb\"]"
],
[
"\"simple white space\", 2",
"[]"
],
[
"\"Hello world\", 4",
"[\"world\"]"
],
[
"\"Uncle sam\", 3",
"[\"Uncle\"]"
],
[
"\"\", 4",
"[]"
],
[
"\"a b c d e f\", 1",
"[\"b\", \"c\", \"d\", \"f\"]"
]
] |
|
[] |
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
return ""
|
[] |
SingleLineInfilling/HumanEval/118/L0
|
code_infilling
|
if len(word) < 3:
|
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
|
HumanEval_SingleLineInfillingLight
|
get_closest_vowel
|
python
|
python
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
return ""
|
[] |
SingleLineInfilling/HumanEval/118/L1
|
code_infilling
|
return ""
|
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
|
HumanEval_SingleLineInfillingLight
|
get_closest_vowel
|
python
|
python
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
return ""
|
[] |
SingleLineInfilling/HumanEval/118/L3
|
code_infilling
|
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
|
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
|
HumanEval_SingleLineInfillingLight
|
get_closest_vowel
|
python
|
python
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
return ""
|
[] |
SingleLineInfilling/HumanEval/118/L4
|
code_infilling
|
for i in range(len(word)-2, 0, -1):
|
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
|
HumanEval_SingleLineInfillingLight
|
get_closest_vowel
|
python
|
python
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
return ""
|
[] |
SingleLineInfilling/HumanEval/118/L5
|
code_infilling
|
if word[i] in vowels:
|
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
|
HumanEval_SingleLineInfillingLight
|
get_closest_vowel
|
python
|
python
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
return word[i]
return ""
|
[] |
SingleLineInfilling/HumanEval/118/L6
|
code_infilling
|
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
|
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
|
HumanEval_SingleLineInfillingLight
|
get_closest_vowel
|
python
|
python
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
return ""
|
[] |
SingleLineInfilling/HumanEval/118/L7
|
code_infilling
|
return word[i]
|
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
|
HumanEval_SingleLineInfillingLight
|
get_closest_vowel
|
python
|
python
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
[] |
SingleLineInfilling/HumanEval/118/L8
|
code_infilling
|
return ""
|
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
|
HumanEval_SingleLineInfillingLight
|
get_closest_vowel
|
python
|
python
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
|
[] |
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
[] |
SingleLineInfilling/HumanEval/119/L0
|
code_infilling
|
def check(s):
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
|
HumanEval_SingleLineInfillingLight
|
match_parens
|
python
|
python
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
[] |
SingleLineInfilling/HumanEval/119/L1
|
code_infilling
|
val = 0
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
|
HumanEval_SingleLineInfillingLight
|
match_parens
|
python
|
python
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
[] |
SingleLineInfilling/HumanEval/119/L2
|
code_infilling
|
for i in s:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
|
HumanEval_SingleLineInfillingLight
|
match_parens
|
python
|
python
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
[] |
SingleLineInfilling/HumanEval/119/L3
|
code_infilling
|
if i == '(':
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
|
HumanEval_SingleLineInfillingLight
|
match_parens
|
python
|
python
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
[] |
SingleLineInfilling/HumanEval/119/L4
|
code_infilling
|
val = val + 1
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
|
HumanEval_SingleLineInfillingLight
|
match_parens
|
python
|
python
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
[] |
SingleLineInfilling/HumanEval/119/L5
|
code_infilling
|
else:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
|
HumanEval_SingleLineInfillingLight
|
match_parens
|
python
|
python
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
[] |
SingleLineInfilling/HumanEval/119/L6
|
code_infilling
|
val = val - 1
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
|
HumanEval_SingleLineInfillingLight
|
match_parens
|
python
|
python
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
[] |
SingleLineInfilling/HumanEval/119/L7
|
code_infilling
|
if val < 0:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
|
HumanEval_SingleLineInfillingLight
|
match_parens
|
python
|
python
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
[] |
SingleLineInfilling/HumanEval/119/L8
|
code_infilling
|
return False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
|
HumanEval_SingleLineInfillingLight
|
match_parens
|
python
|
python
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
[] |
SingleLineInfilling/HumanEval/119/L9
|
code_infilling
|
return True if val == 0 else False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
|
HumanEval_SingleLineInfillingLight
|
match_parens
|
python
|
python
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
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