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math_qa__kGEByZgTGvcqeoxK | How much time will a train of length 250 m moving at a speed of 72 kmph take to cross another train of length 300 m, moving at 36 kmph in the same direction? Select the correct option
A) 55 B) 99 C) 88 D) 76 E) 12 | <gadget id="calculator">250 + 300</gadget>
<output>550</output>
<gadget id="calculator">72 - 36</gadget>
<output>36</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">550 / 10</gadget>
<output>55</output>
<result>A</result> | A | 55 | How much time will a train of length 250 m moving at a speed of 72 kmph take to cross another train of length 300 m, moving at 36 kmph in the same direction? | {
"A": "55",
"B": "99",
"C": "88",
"D": "76",
"E": "12"
} | divide(add(250, 300), multiply(subtract(72, 36), const_0_2778)) | add(n0,n2)|subtract(n1,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "the distance to be covered = sum of their lengths = 250 + 300 = 550 m . relative speed = 72 - 36 = 36 kmph = 36 * 5 / 18 = 10 mps . time required = d / s = 550 / 10 = 55 sec . answer : a" | physics |
math_qa__CEXGW65vxISWhhNj | For all real numbers v, an operation is defined by the equation v* = v - v/3. If (v*)* = 20, then v= Choose the most appropriate option
A) 36 B) 39 C) 42 D) 45 E) 48 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">20 / (2/3)</gadget>
<output>30</output>
<gadget id="calculator">30 / (2/3)</gadget>
<output>45</output>
<result>D</result> | D | 45 | For all real numbers v, an operation is defined by the equation v* = v - v/3. If (v*)* = 20, then v= | {
"A": "36",
"B": "39",
"C": "42",
"D": "45",
"E": "48"
} | divide(divide(20, subtract(const_1, divide(const_1, 3))), subtract(const_1, divide(const_1, 3))) | divide(const_1,n0)|subtract(const_1,#0)|divide(n1,#1)|divide(#2,#1)| | "( v * ) * = ( v - v / 3 ) - ( v - v / 3 ) / 3 20 = 2 v / 3 - 2 v / 9 = 4 v / 9 v = 45 the answer is d ." | general |
math_qa__6mpLQdvAxTfVVnGJ | The difference of 2 digit no. & the no. obtained by interchanging the digits is 36. What is the difference the sum and the number if the ratio between the digits of the number is 1:2 ? Choose the correct choice from the following.
A) 6 B) 8 C) 10 D) 12 E) 13 | <gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">20 - 10</gadget>
<output>10</output>
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">36 / 9</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">4 + 8</gadget>
<output>12</output>
<gadget id="calculator">8 - 4</gadget>
<output>4</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<result>B</result> | B | 8 | The difference of 2 digit no. & the no. obtained by interchanging the digits is 36. What is the difference the sum and the number if the ratio between the digits of the number is 1:2 ? | {
"A": "6",
"B": "8",
"C": "10",
"D": "12",
"E": "13"
} | subtract(add(divide(36, subtract(subtract(multiply(const_10, 2), const_10), const_1)), multiply(divide(36, subtract(subtract(multiply(const_10, 2), const_10), const_1)), 2)), subtract(multiply(divide(36, subtract(subtract(multiply(const_10, 2), const_10), const_1)), 2), divide(36, subtract(subtract(multiply(const_10, 2), const_10), const_1)))) | multiply(n0,const_10)|subtract(#0,const_10)|subtract(#1,const_1)|divide(n1,#2)|multiply(n0,#3)|add(#3,#4)|subtract(#4,#3)|subtract(#5,#6) | let the number be xy . given xy – yx = 36 . this means the number is greater is than the number got on reversing the digits . this shows that the ten ’ s digit x > unit digit y . also given ratio between digits is 1 : 2 = > x = 2 y ( 10 x + y ) – ( 10 y + x ) = 36 = > x – y = 4 = > 2 y – y = 4 . hence , ( x + y ) – ( x – y ) = 3 y – y = 2 y = 8 b | general |
math_qa__MgKhVmcDyQ12ethW | The length of a rectangle is reduced by 10%. By what % would the width have to be increased to maintain the original area?
Choose the correct answer:
A) 10 % B) 11.1 % C) 25 % D) 30 % E) 35 % | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">1 - (9/10)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) / (9/10)</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">(1/9) * 100</gadget>
<output>100/9 = around 11.111111</output>
<result>B</result> | B | 11.1 | The length of a rectangle is reduced by 10%. By what % would the width have to be increased to maintain the original area? | {
"A": "10 %",
"B": "11.1 %",
"C": "25 %",
"D": "30 %",
"E": "35 %"
} | multiply(divide(subtract(const_1, divide(subtract(const_100, 10), const_100)), divide(subtract(const_100, 10), const_100)), const_100) | subtract(const_100,n0)|divide(#0,const_100)|subtract(const_1,#1)|divide(#2,#1)|multiply(#3,const_100)| | "sol . required change = ( 10 * 100 ) / ( 100 - 10 ) = 11.1 % b" | geometry |
math_qa__ugFxmlHMWfqcvDAX | Rs 3500 is divided into two parts such that one part is put out at 3% and the other at 5%. If the annual interest earned from both the investments be Rs 144, find the first part.
Choose the correct answer:
A) s 4000
B) s 2800
C) s 1800
D) s 1500
E) s 1550 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">3_500 * (1/20)</gadget>
<output>175</output>
<gadget id="calculator">175 - 144</gadget>
<output>31</output>
<gadget id="calculator">3 / 100</gadget>
<output>3/100 = around 0.03</output>
<gadget id="calculator">(1/20) - (3/100)</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">31 / (1/50)</gadget>
<output>1_550</output>
<result>E</result> | E | 1,550 | Rs 3500 is divided into two parts such that one part is put out at 3% and the other at 5%. If the annual interest earned from both the investments be Rs 144, find the first part. | {
"A": "s 4000",
"B": "s 2800",
"C": "s 1800",
"D": "s 1500",
"E": "s 1550"
} | divide(subtract(multiply(3500, divide(5, const_100)), 144), subtract(divide(5, const_100), divide(3, const_100))) | divide(n2,const_100)|divide(n1,const_100)|multiply(n0,#0)|subtract(#0,#1)|subtract(#2,n3)|divide(#4,#3)| | "explanation : average rate = ( 144 / 3500 ) * 100 = 4.11 ratio = 8.85 : 11.14 so , first part = ( 8.85 / 20 ) * 3500 = rs 1550 . answer : e" | gain |
math_qa__lSG7h9rhXr28LxOG | A train 110 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going? Choose one
A) 7 sec
B) 6 sec
C) 4 sec
D) 2 sec
E) 9 sec | <gadget id="calculator">60 + 6</gadget>
<output>66</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">66 * (5/18)</gadget>
<output>55/3 = around 18.333333</output>
<gadget id="calculator">110 / (55/3)</gadget>
<output>6</output>
<result>B</result> | B | 6 | A train 110 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going? | {
"A": "7 sec",
"B": "6 sec",
"C": "4 sec",
"D": "2 sec",
"E": "9 sec"
} | divide(110, multiply(add(60, 6), const_0_2778)) | add(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 60 + 6 = 66 km / hr . = 66 * 5 / 18 = 55 / 3 m / sec . time taken to pass the men = 110 * 3 / 55 = 6 sec . answer : b" | physics |
math_qa__t12jngsmdidSaDUE | what is the sum of all 4 digit integers formed using the digits 2 , 3 , 4 and 5 ( repetition is allowed )
Select: A) 444440 B) 610000 C) 666640 D) 995456 E) 880000 | <gadget id="calculator">4 ** 3</gadget>
<output>64</output>
<gadget id="calculator">5 + 4</gadget>
<output>9</output>
<gadget id="calculator">9 + 3</gadget>
<output>12</output>
<gadget id="calculator">12 + 2</gadget>
<output>14</output>
<gadget id="calculator">64 * 14</gadget>
<output>896</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 + 100</gadget>
<output>1_100</output>
<gadget id="calculator">1_100 + 10</gadget>
<output>1_110</output>
<gadget id="calculator">1_110 + 1</gadget>
<output>1_111</output>
<gadget id="calculator">896 * 1_111</gadget>
<output>995_456</output>
<result>D</result> | D | 995,456 | what is the sum of all 4 digit integers formed using the digits 2 , 3 , 4 and 5 ( repetition is allowed ) | {
"A": "444440",
"B": "610000",
"C": "666640",
"D": "995456",
"E": "880000"
} | multiply(multiply(power(4, const_3), add(add(add(5, 4), 3), 2)), add(add(add(multiply(const_100, const_10), const_100), const_10), const_1)) | add(n0,n4)|multiply(const_10,const_100)|power(n0,const_3)|add(#1,const_100)|add(n2,#0)|add(#3,const_10)|add(n1,#4)|add(#5,const_1)|multiply(#6,#2)|multiply(#7,#8) | n = 4 * 4 * 4 * 4 = 256 < x > = ( 5555 + 2222 ) / 2 = 3888.5 sum = number of integers x average value n * < x > = 256 * 3888.5 = 711040 answer = d | general |
math_qa__noYw7SgRJUVFqXhe | Length of a rectangular plot is 10 mtr more than its breadth. If the cost of fencin g the plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr? Choose the correct choice from the following answers:
A) 55 m B) 60 m C) 80 m D) 82 m E) 84 m | <gadget id="calculator">5_300 / 26.5</gadget>
<output>200</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">200 + 20</gadget>
<output>220</output>
<gadget id="calculator">220 / 4</gadget>
<output>55</output>
<result>A</result> | A | 55 | Length of a rectangular plot is 10 mtr more than its breadth. If the cost of fencin g the plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr? | {
"A": "55 m",
"B": "60 m",
"C": "80 m",
"D": "82 m",
"E": "84 m"
} | divide(add(divide(5300, 26.50), multiply(const_2, 10)), const_4) | divide(n2,n1)|multiply(n0,const_2)|add(#0,#1)|divide(#2,const_4)| | "let breadth = x metres . then , length = ( x + 10 ) metres . perimeter = 5300 m = 200 m . 26.50 2 [ ( x + 10 ) + x ] = 200 2 x + 10 = 100 2 x = 90 x = 45 . hence , length = x + 10 = 55 m a" | physics |
math_qa__QHRvlncgraFvdOWq | The average age of an adult class is 40 years. 2 new students with an avg age of 32 years join the class. Therefore decreasing the average by 4 year. Find what was the original strength of class? Choose the correct choice from the following options.
A) 10 B) 12 C) 16 D) 2 E) 22 | <gadget id="calculator">40 - 4</gadget>
<output>36</output>
<gadget id="calculator">2 * 36</gadget>
<output>72</output>
<gadget id="calculator">2 * 32</gadget>
<output>64</output>
<gadget id="calculator">72 - 64</gadget>
<output>8</output>
<gadget id="calculator">8 / 4</gadget>
<output>2</output>
<result>D</result> | D | 2 | The average age of an adult class is 40 years. 2 new students with an avg age of 32 years join the class. Therefore decreasing the average by 4 year. Find what was the original strength of class? | {
"A": "10",
"B": "12",
"C": "16",
"D": "2",
"E": "22"
} | divide(subtract(multiply(2, subtract(40, 4)), multiply(2, 32)), 4) | multiply(n1,n2)|subtract(n0,n3)|multiply(n1,#1)|subtract(#2,#0)|divide(#3,n3)| | "let original strength = y then , 40 y + 2 x 32 = ( y + 2 ) x 36 â ‡ ’ 40 y + 64 = 36 y + 72 â ‡ ’ 4 y = 8 â ˆ ´ y = 2 d" | general |
math_qa__XOHV2tkj1uhjJDfc | Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 16 hours and 9 hours respectively. The ratio of their speeds is?
Choose the correct answer: A) 4 : 5 B) 4 : 3 C) 4 : 4 D) 4 : 9 E) 3 : 4 | <gadget id="calculator">9 ** (1/2)</gadget>
<output>3</output>
<gadget id="calculator">16 ** (1/2)</gadget>
<output>4</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<result>E</result> | E | 0.75 | Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 16 hours and 9 hours respectively. The ratio of their speeds is? | {
"A": "4 : 5",
"B": "4 : 3",
"C": "4 : 4",
"D": "4 : 9",
"E": "3 : 4"
} | divide(sqrt(9), sqrt(16)) | sqrt(n1)|sqrt(n0)|divide(#0,#1)| | "let us name the trains a and b . then , ( a ' s speed ) : ( b ' s speed ) = √ b : √ a = √ 9 : √ 16 = 3 : 4 answer : e" | physics |
math_qa__DPyy9zhNK34h9w8m | The product of a and b is equal to 11 more than twice the sum of a and b. If b = 5, what is the value of b - a? Choices.
A) - 2 B) 5 C) 7 D) 24 E) 35 | <gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 + 11</gadget>
<output>21</output>
<gadget id="calculator">5 - 2</gadget>
<output>3</output>
<gadget id="calculator">21 / 3</gadget>
<output>7</output>
<gadget id="calculator">5 - 7</gadget>
<output>-2</output>
<result>A</result> | A | -2 | The product of a and b is equal to 11 more than twice the sum of a and b. If b = 5, what is the value of b - a? | {
"A": "- 2",
"B": "5",
"C": "7",
"D": "24",
"E": "35"
} | subtract(5, divide(add(multiply(5, const_2), 11), subtract(5, const_2))) | multiply(n1,const_2)|subtract(n1,const_2)|add(n0,#0)|divide(#2,#1)|subtract(n1,#3)| | "ab = 11 + 2 ( a + b ) 5 a = 11 + 2 a + 10 3 a = 21 a = 7 b - a = 5 - 7 = - 2 a is the answer" | general |
math_qa__xm7jMkIpc8scPIfk | In Town X, 64 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females? Pick one.
A) 16 % B) 25 % C) 32 % D) 40 % E) 52 % | <gadget id="calculator">64 - 48</gadget>
<output>16</output>
<gadget id="calculator">16 / 64</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>B</result> | B | 25 | In Town X, 64 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females? | {
"A": "16 %",
"B": "25 %",
"C": "32 %",
"D": "40 %",
"E": "52 %"
} | multiply(divide(subtract(64, 48), 64), const_100) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_100)| | "let population be 100 total employed people = 64 % of the population = 64 employed males = 48 % of the population = 48 employed females = 16 % of the population = 16 employed females % in terms of employed people = ( 16 / 64 ) * 100 = 25 % answer is b ." | gain |
math_qa__ul7Bv7TwkTZEhaox | The arithmetic mean and standard deviation of a certain normal distribution are 14.0 and 1.5, respectively. What value is exactly 2 standard deviations less than the mean?
Select the correct option.
A) 10.5 B) 11 C) 11.5 D) 12 E) 12.5 | <gadget id="calculator">2 * 1.5</gadget>
<output>3</output>
<gadget id="calculator">14 - 3</gadget>
<output>11</output>
<result>B</result> | B | 11 | The arithmetic mean and standard deviation of a certain normal distribution are 14.0 and 1.5, respectively. What value is exactly 2 standard deviations less than the mean? | {
"A": "10.5",
"B": "11",
"C": "11.5",
"D": "12",
"E": "12.5"
} | subtract(14.0, multiply(2, 1.5)) | multiply(n1,n2)|subtract(n0,#0)| | "the value which isexactlytwo sd less than the mean is : mean - 2 * sd = 14.0 - 2 * 1.5 = 11 . answer : b ." | general |
math_qa__2mfDLfqRCRJnkC0R | If a*b denotes the greatest common divisor of a and b, then ((16*20)*(18*24)) = ? Options.
A) 24 B) 12 C) 6 D) 4 E) 2 | <gadget id="calculator">18 / 3</gadget>
<output>6</output>
<gadget id="calculator">6 / 3</gadget>
<output>2</output>
<result>E</result> | E | 2 | If a*b denotes the greatest common divisor of a and b, then ((16*20)*(18*24)) = ? | {
"A": "24",
"B": "12",
"C": "6",
"D": "4",
"E": "2"
} | divide(divide(18, const_3), const_3) | divide(n2,const_3)|divide(#0,const_3) | the greatest common divisor of 16 and 20 is 4 . hence 16 * 20 = 4 ( note that * here denotes the function not multiplication ) . the greatest common divisor of 18 and 24 is 6 . hence 18 * 24 = 6 . hence ( ( 16 * 20 ) * ( 18 * 24 ) ) = 4 * 6 . the greatest common divisor of 4 and 6 is 2 . answer ; e . | general |
math_qa__EuKLvNFLOFAbgt9t | Solution P is 20 percent lemonade and 80 percent carbonated water by volume; solution Q is 45 percent lemonade and 55 percent carbonated water by volume. If a mixture of PQ contains 65 percent carbonated water, what percent of the volume of the mixture is P? Choose the correct option.
A) 20 % B) 40 % C) 50 % D) 60 % E) 80 % | <gadget id="calculator">65 / 100</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">55 / 100</gadget>
<output>11/20 = around 0.55</output>
<gadget id="calculator">(13/20) - (11/20)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) - (13/20)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(1/10) + (3/20)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/10) / (1/4)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>B</result> | B | 40 | Solution P is 20 percent lemonade and 80 percent carbonated water by volume; solution Q is 45 percent lemonade and 55 percent carbonated water by volume. If a mixture of PQ contains 65 percent carbonated water, what percent of the volume of the mixture is P? | {
"A": "20 %",
"B": "40 %",
"C": "50 %",
"D": "60 %",
"E": "80 %"
} | multiply(divide(subtract(divide(65, const_100), divide(55, const_100)), add(subtract(divide(65, const_100), divide(55, const_100)), subtract(divide(80, const_100), divide(65, const_100)))), const_100) | divide(n4,const_100)|divide(n3,const_100)|divide(n1,const_100)|subtract(#0,#1)|subtract(#2,#0)|add(#3,#4)|divide(#3,#5)|multiply(#6,const_100)| | "65 % is 15 % - points below 80 % and 10 % - points above 55 % . so the ratio of solution p to solution q is 2 : 3 . mixture p is 2 / 5 = 40 % of the volume of mixture pq . the answer is b ." | gain |
math_qa__PMlhcUZ2sYJ5mt1Y | In a class of 40 students, 2 students did not borrow any books from the library, 12 students each borrowed 1 book, 12 students each borrowed 2 books, and the rest borrowed at least 3 books. If the average number of books per student was 2, what is the maximum number of books any single student could have borrowed? Choose the correct choice from the following choices
A) 3
B) 4
C) 5
D) 6
E) 7 | <gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">12 * 1</gadget>
<output>12</output>
<gadget id="calculator">12 + 12</gadget>
<output>24</output>
<gadget id="calculator">24 + 2</gadget>
<output>26</output>
<gadget id="calculator">40 - 26</gadget>
<output>14</output>
<gadget id="calculator">14 - 1</gadget>
<output>13</output>
<gadget id="calculator">13 * 3</gadget>
<output>39</output>
<gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">12 + 24</gadget>
<output>36</output>
<gadget id="calculator">39 + 36</gadget>
<output>75</output>
<gadget id="calculator">80 - 75</gadget>
<output>5</output>
<result>C</result> | C | 5 | In a class of 40 students, 2 students did not borrow any books from the library, 12 students each borrowed 1 book, 12 students each borrowed 2 books, and the rest borrowed at least 3 books. If the average number of books per student was 2, what is the maximum number of books any single student could have borrowed? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | subtract(multiply(40, 2), add(multiply(subtract(subtract(40, add(add(multiply(12, 1), 12), 2)), 1), 3), add(multiply(12, 1), multiply(12, 2)))) | multiply(n0,n1)|multiply(n2,n3)|multiply(n1,n4)|add(#1,#2)|add(n4,#1)|add(n1,#4)|subtract(n0,#5)|subtract(#6,n3)|multiply(n6,#7)|add(#3,#8)|subtract(#0,#9)| | "the class borrowed a total of 40 * 2 = 80 books . the 26 students who borrowed 0 , 1 , or 2 books borrowed a total of 12 + 12 * 2 = 36 . to maximize the number of books borrowed by 1 student , let ' s assume that 13 students borrowed 3 books and 1 student borrowed the rest . 80 - 36 - 3 * 13 = 5 the maximum number of books borrowed by any student is 5 . the answer is c ." | general |
math_qa__UpEFHOjmrMctETJT | Shop Offered 40% offer for every Shirt, Smith bought a shirt at Rs. 560. and What was the shop's original selling Price? Choose the correct choice from the following answers.
A) 500 B) 550 C) 600 D) 933 E) 750 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">560 / (3/5)</gadget>
<output>2_800/3 = around 933.333333</output>
<result>D</result> | D | 933 | Shop Offered 40% offer for every Shirt, Smith bought a shirt at Rs. 560. and What was the shop's original selling Price? | {
"A": "500",
"B": "550",
"C": "600",
"D": "933",
"E": "750"
} | divide(560, subtract(const_1, divide(40, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|divide(n1,#1)| | "sp * ( 60 / 100 ) = 560 sp = 9.33 * 100 = > cp = 933 answer : d" | gain |
math_qa__Ll49or7J6q1coUUV | the average score of a cricketer for 12 matches is 48 runs . if the average for first 8 matches is 40 , then average for last 4 matches is Choose the correct choice:
A) 33.25 B) 89 C) 64 D) 68 E) 90 | <gadget id="calculator">48 + 12</gadget>
<output>60</output>
<gadget id="calculator">40 / 8</gadget>
<output>5</output>
<gadget id="calculator">60 + 5</gadget>
<output>65</output>
<gadget id="calculator">4 - 3</gadget>
<output>1</output>
<gadget id="calculator">65 - 1</gadget>
<output>64</output>
<result>C</result> | C | 64 | the average score of a cricketer for 12 matches is 48 runs . if the average for first 8 matches is 40 , then average for last 4 matches is | {
"A": "33.25",
"B": "89",
"C": "64",
"D": "68",
"E": "90"
} | subtract(add(add(48, 12), divide(40, 8)), subtract(4, const_3)) | add(n0,n1)|divide(n3,n2)|subtract(n4,const_3)|add(#0,#1)|subtract(#3,#2) | explanation : = ( 48 × 12 ) − ( 40 × 8 ) / 4 = ( 576 − 320 ) / 4 = 64 answer : option c | general |
math_qa__IjQs29JZb84sKTEh | The average of 40 results is 30 and the average of other 30 results is 40 . what is the average of all the results? Pick
A) 34 B) 25 C) 48 D) 50 E) none | <gadget id="calculator">40 * 30</gadget>
<output>1_200</output>
<gadget id="calculator">30 * 40</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 + 1_200</gadget>
<output>2_400</output>
<gadget id="calculator">40 + 30</gadget>
<output>70</output>
<gadget id="calculator">2_400 / 70</gadget>
<output>240/7 = around 34.285714</output>
<result>A</result> | A | 34 | The average of 40 results is 30 and the average of other 30 results is 40 . what is the average of all the results? | {
"A": "34",
"B": "25",
"C": "48",
"D": "50",
"E": "none"
} | divide(add(multiply(40, 30), multiply(30, 40)), add(40, 30)) | add(n0,n1)|multiply(n0,n1)|add(#1,#1)|divide(#2,#0) | answer sum of 70 result = sum of 40 result + sum of 30 result . = 40 x 30 + 30 x 40 = 2400 / 70 correct option : a | general |
math_qa__H7FbpB157c50vI3G | A candidate got 35% of the votes polled and he lost to his rival by 2340 votes. How many votes were cast?
Choose the correct choice from the following answers.
A) 7500
B) 3388
C) 2665
D) 7800
E) 2661 | <gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">1 - (7/20)</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">(13/20) - (7/20)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">2_340 / (3/10)</gadget>
<output>7_800</output>
<result>D</result> | D | 7,800 | A candidate got 35% of the votes polled and he lost to his rival by 2340 votes. How many votes were cast? | {
"A": "7500",
"B": "3388",
"C": "2665",
"D": "7800",
"E": "2661"
} | divide(2340, subtract(subtract(const_1, divide(35, const_100)), divide(35, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|subtract(#1,#0)|divide(n1,#2)| | "35 % - - - - - - - - - - - l 65 % - - - - - - - - - - - w - - - - - - - - - - - - - - - - - - 30 % - - - - - - - - - - 2340 100 % - - - - - - - - - ? = > 7800 answer : d" | gain |
math_qa__bNqXyZPIi96cZnxk | In a box of 12 pens, a total of 4 are defective. If a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective? Choose the correct option:
A) 1 / 6 B) 2 / 33 C) 14 / 33 D) 9 / 16 E) 3 / 44 | <gadget id="calculator">12 - 4</gadget>
<output>8</output>
<gadget id="calculator">8 / 12</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">7 / 11</gadget>
<output>7/11 = around 0.636364</output>
<gadget id="calculator">(2/3) * (7/11)</gadget>
<output>14/33 = around 0.424242</output>
<result>C</result> | C | 0.424242 | In a box of 12 pens, a total of 4 are defective. If a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective? | {
"A": "1 / 6",
"B": "2 / 33",
"C": "14 / 33",
"D": "9 / 16",
"E": "3 / 44"
} | multiply(divide(subtract(12, 4), 12), divide(subtract(subtract(12, 4), const_1), subtract(12, const_1))) | subtract(n0,n1)|subtract(n0,const_1)|divide(#0,n0)|subtract(#0,const_1)|divide(#3,#1)|multiply(#2,#4)| | "method - 1 there are 9 fine pieces of pen and 4 defective in a lot of 12 pens i . e . probability of first pen not being defective = ( 8 / 12 ) i . e . probability of second pen not being defective = ( 7 / 11 ) [ 11 pen remaining with 8 defective remaining considering that first was defective ] probability of both pen being non - defective = ( 8 / 12 ) * ( 7 / 11 ) = 14 / 33 answer : option c" | general |
math_qa__pgvYGLftdAmHsCk6 | A bowl was filled with 10 ounces of water, and 0.007 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period? Choices
A) 0.004 % B) 0.04 % C) 0.40 % D) 4 % E) 3.5 % | <gadget id="calculator">50 * 0.007</gadget>
<output>0.35</output>
<gadget id="calculator">0.35 / 10</gadget>
<output>0.035</output>
<gadget id="calculator">0.035 * 100</gadget>
<output>3.5</output>
<result>E</result> | E | 3.5 | A bowl was filled with 10 ounces of water, and 0.007 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period? | {
"A": "0.004 %",
"B": "0.04 %",
"C": "0.40 %",
"D": "4 %",
"E": "3.5 %"
} | multiply(divide(multiply(50, 0.007), 10), const_100) | multiply(n1,n2)|divide(#0,n0)|multiply(#1,const_100)| | "total amount of water evaporated each day during a 50 - day period = . 007 * 50 = . 007 * 100 / 2 = . 7 / 2 = . 35 percent of the original amount of water evaporated during this period = ( . 35 / 10 ) * 100 % = 3.5 % answer e" | gain |
math_qa__ks0QYrFCLtkWxcet | The price of a certain painting increased by 30% during the first year and decreased by 20% during the second year. The price of the painting at the end of the 2-year period was what percent of the original price? Choices.
A) 102 % B) 105 % C) 120 % D) 135 % E) 104 % | <gadget id="calculator">30 - 20</gadget>
<output>10</output>
<gadget id="calculator">20 * 30</gadget>
<output>600</output>
<gadget id="calculator">600 / 100</gadget>
<output>6</output>
<gadget id="calculator">10 - 6</gadget>
<output>4</output>
<gadget id="calculator">4 + 100</gadget>
<output>104</output>
<result>E</result> | E | 104 | The price of a certain painting increased by 30% during the first year and decreased by 20% during the second year. The price of the painting at the end of the 2-year period was what percent of the original price? | {
"A": "102 %",
"B": "105 %",
"C": "120 %",
"D": "135 %",
"E": "104 %"
} | add(subtract(subtract(30, 20), divide(multiply(20, 30), const_100)), const_100) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,const_100)|subtract(#1,#2)|add(#3,const_100)| | "easiest thing to do : assume that price is 100 price at the end of yr 1 : 100 + 30 = 130 price at the end of year 2 = 130 - 130 * 0.20 = 130 * 0.80 = 104 hence required answer = ( 104 / 100 ) * 100 % = 104 % answer is e ." | general |
math_qa__nlyhfzwB05NdytnQ | The least whole number which when subtracted from both the terms of the ratio 6 : 7 to give a raƟo
less than 16 : 21, is Select: A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">21 * 6</gadget>
<output>126</output>
<gadget id="calculator">7 * 16</gadget>
<output>112</output>
<gadget id="calculator">126 - 112</gadget>
<output>14</output>
<gadget id="calculator">21 - 16</gadget>
<output>5</output>
<gadget id="calculator">14 / 5</gadget>
<output>14/5 = around 2.8</output>
<gadget id="calculator">floor(14/5)</gadget>
<output>2</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<result>A</result> | A | 3 | The least whole number which when subtracted from both the terms of the ratio 6 : 7 to give a raƟo
less than 16 : 21, is | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | add(floor(divide(subtract(multiply(21, 6), multiply(7, 16)), subtract(21, 16))), const_1) | multiply(n0,n3)|multiply(n1,n2)|subtract(n3,n2)|subtract(#0,#1)|divide(#3,#2)|floor(#4)|add(#5,const_1) | explanation : let x is subtracted . then , ( 6 − x ) ( 7 − x ) < 162121 ( 6 � x ) < 16 ( 7 � x ) = > 5 x > 14 = x > 2.8 least such number is 3 answer : a | other |
math_qa__NvJ0C41o2zQJpG5l | In what time will a train 134 m long cross an electric pole, it its speed be 169 km/hr?
Choose the correct choice from the following choices: A) 2.5 B) 2.7 C) 2.9 D) 2.3 E) 2.1 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">169 * (5/18)</gadget>
<output>845/18 = around 46.944444</output>
<gadget id="calculator">134 / (845/18)</gadget>
<output>2_412/845 = around 2.854438</output>
<result>C</result> | C | 2.9 | In what time will a train 134 m long cross an electric pole, it its speed be 169 km/hr? | {
"A": "2.5",
"B": "2.7",
"C": "2.9",
"D": "2.3",
"E": "2.1"
} | divide(134, multiply(169, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 169 * 5 / 18 = 46.9 m / sec time taken = 134 / 46.9 = 2.9 sec . answer : c" | physics |
math_qa__IXHutmKP2sxVIPUl | If (5^13)(9^7)=3(15^x), what is the value of x?
Choose the correct choice from the following answers
A) 7 B) 9 C) 11 D) 13 E) 15 | <gadget id="calculator">5 ** 13</gadget>
<output>1_220_703_125</output>
<gadget id="calculator">9 ** 7</gadget>
<output>4_782_969</output>
<gadget id="calculator">1_220_703_125 * 4_782_969</gadget>
<output>5_838_585_205_078_125</output>
<gadget id="calculator">5_838_585_205_078_125 / 3</gadget>
<output>1_946_195_068_359_375</output>
<gadget id="calculator">log(1_946_195_068_359_375)</gadget>
<output>log(1946195068359375) = around 35.204653</output>
<gadget id="calculator">log(15)</gadget>
<output>log(15) = around 2.70805</output>
<gadget id="calculator">log(1946195068359375) / log(15)</gadget>
<output>log(1946195068359375)/log(15) = around 13</output>
<result>D</result> | D | 13 | If (5^13)(9^7)=3(15^x), what is the value of x? | {
"A": "7",
"B": "9",
"C": "11",
"D": "13",
"E": "15"
} | divide(log(divide(multiply(power(5, 13), power(9, 7)), 3)), log(15)) | log(n5)|power(n0,n1)|power(n2,n3)|multiply(#1,#2)|divide(#3,n4)|log(#4)|divide(#5,#0) | ( 5 ^ 13 ) ( 9 ^ 7 ) = 3 ( 15 ^ x ) = > 5 ^ 13 * 3 ^ 14 = 3 * 3 ^ x * 5 ^ x = > 5 ^ 13 * 3 ^ 14 = 3 ^ ( x + 1 ) * 5 ^ x value of x = 13 answer d | general |
math_qa__78e6ksLcN3AbCQfX | a,b,c,d,e,f,g,h sitting in a row what is the probability that a,b,d are sitting together? Pick:
A) 1 / 5
B) 3 / 28
C) 1 / 7
D) 1 / 14
E) 5 / 28 | <gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">720 * 6</gadget>
<output>4_320</output>
<gadget id="calculator">factorial(8)</gadget>
<output>40_320</output>
<gadget id="calculator">4_320 / 40_320</gadget>
<output>3/28 = around 0.107143</output>
<result>B</result> | B | 0.107143 | a,b,c,d,e,f,g,h sitting in a row what is the probability that a,b,d are sitting together? | {
"A": "1 / 5",
"B": "3 / 28",
"C": "1 / 7",
"D": "1 / 14",
"E": "5 / 28"
} | divide(multiply(factorial(add(subtract(add(const_4, const_4), const_3), const_1)), factorial(const_3)), factorial(add(const_4, const_4))) | add(const_4,const_4)|factorial(const_3)|factorial(#0)|subtract(#0,const_3)|add(#3,const_1)|factorial(#4)|multiply(#5,#1)|divide(#6,#2)| | "total number of arrangement is = 8 ! = 40320 favorable event i . e a , b and d can be arranged in 3 ! and the remaining can be arranged in 6 ! since abd can be in any of the six positions . so 3 ! * 6 ! / 8 ! = 3 / 28 answer : b" | probability |
math_qa__emWOYEAyTFuQd5QQ | The divisor is 21, the quotient is 14 and the remainder is 7.
What is the dividend? Choose one:
A) 201 B) 394 C) 302 D) 301 E) 294 | <gadget id="calculator">21 * 14</gadget>
<output>294</output>
<gadget id="calculator">294 + 7</gadget>
<output>301</output>
<result>D</result> | D | 301 | The divisor is 21, the quotient is 14 and the remainder is 7.
What is the dividend? | {
"A": "201",
"B": "394",
"C": "302",
"D": "301",
"E": "294"
} | add(multiply(21, 14), 7) | multiply(n0,n1)|add(n2,#0) | d = d * q + r d = 21 * 14 + 7 d = 294 + 7 d = 301 | general |
math_qa__yEaSgohubpodTR1L | Tabby is training for a triathlon. She swims at a speed of 1 mile per hour. She runs at a speed of 6 miles per hour. She wants to figure out her average speed for these two events. What is the correct answer for her?
Choose the correct choice from the following answers
A) 8 mph B) 5.25 mph C) 3.5 mph D) 4 mph E) 0.5 mph | <gadget id="calculator">1 + 6</gadget>
<output>7</output>
<gadget id="calculator">7 / 2</gadget>
<output>7/2 = around 3.5</output>
<result>C</result> | C | 3.5 | Tabby is training for a triathlon. She swims at a speed of 1 mile per hour. She runs at a speed of 6 miles per hour. She wants to figure out her average speed for these two events. What is the correct answer for her? | {
"A": "8 mph",
"B": "5.25 mph",
"C": "3.5 mph",
"D": "4 mph",
"E": "0.5 mph"
} | divide(add(1, 6), const_2) | add(n0,n1)|divide(#0,const_2)| | "( 1 mph + 6 mph ) / 2 = 3.5 mph correct option is : c" | physics |
math_qa__h6FKNlmaaso88l6Z | What annual payment will discharge a debt of Rs. 1050 due in 2 years at the rate of 5% compound interest?
Choices:
A) 993.2 B) 551.25 C) 534.33 D) 543.33 E) 564.69 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) + 1</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">(441/400) * 1_050</gadget>
<output>9_261/8 = around 1_157.625</output>
<gadget id="calculator">(9_261/8) / 2</gadget>
<output>9_261/16 = around 578.8125</output>
<result>E</result> | E | 564.69 | What annual payment will discharge a debt of Rs. 1050 due in 2 years at the rate of 5% compound interest? | {
"A": "993.2",
"B": "551.25",
"C": "534.33",
"D": "543.33",
"E": "564.69"
} | divide(multiply(power(add(divide(5, const_100), const_1), 2), 1050), 2) | divide(n2,const_100)|add(#0,const_1)|power(#1,n1)|multiply(n0,#2)|divide(#3,n1)| | "explanation : let each installment be rs . x . then , x / ( 1 + 5 / 100 ) + x / ( 1 + 5 / 100 ) 2 = 1050 820 x + 1050 * 441 x = 564.69 so , value of each installment = rs . 564.69 answer : option e" | gain |
math_qa__raMk3sTkPWDwUYAZ | A dishonest dealer professes to sell goods at the cost price but uses a weight of 880 grams per kg, what is his percent? Choose the correct choice
A) 15 % B) 13.6 % C) 65 % D) 45 % E) 35 % | <gadget id="calculator">100 / 880</gadget>
<output>5/44 = around 0.113636</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">(5/44) * 1_000</gadget>
<output>1_250/11 = around 113.636364</output>
<gadget id="calculator">(1_250/11) - 100</gadget>
<output>150/11 = around 13.636364</output>
<result>B</result> | B | 13.6 | A dishonest dealer professes to sell goods at the cost price but uses a weight of 880 grams per kg, what is his percent? | {
"A": "15 %",
"B": "13.6 %",
"C": "65 %",
"D": "45 %",
"E": "35 %"
} | subtract(multiply(divide(const_100, 880), multiply(const_100, multiply(add(const_3, const_2), const_2))), const_100) | add(const_2,const_3)|divide(const_100,n0)|multiply(#0,const_2)|multiply(#2,const_100)|multiply(#1,#3)|subtract(#4,const_100)| | "explanation : 880 - - - 120 100 - - - ? = > 13.6 % answer : b" | gain |
math_qa__I3zU7On93fOrIyMP | The number of positive integer solutions for the equation x +y +z + t = 21 is
Choose the correct choice.
A) 1140 B) 1145 C) 1240 D) 1340 E) 15640 | <gadget id="calculator">21 - 1</gadget>
<output>20</output>
<gadget id="calculator">factorial(20)</gadget>
<output>2_432_902_008_176_640_000</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">20 - 3</gadget>
<output>17</output>
<gadget id="calculator">factorial(17)</gadget>
<output>355_687_428_096_000</output>
<gadget id="calculator">6 * 355_687_428_096_000</gadget>
<output>2_134_124_568_576_000</output>
<gadget id="calculator">2_432_902_008_176_640_000 / 2_134_124_568_576_000</gadget>
<output>1_140</output>
<result>A</result> | A | 1,140 | The number of positive integer solutions for the equation x +y +z + t = 21 is | {
"A": "1140",
"B": "1145",
"C": "1240",
"D": "1340",
"E": "15640"
} | divide(factorial(subtract(21, const_1)), multiply(factorial(subtract(const_4, const_1)), factorial(subtract(subtract(21, const_1), subtract(const_4, const_1))))) | subtract(n0,const_1)|subtract(const_4,const_1)|factorial(#0)|factorial(#1)|subtract(#0,#1)|factorial(#4)|multiply(#3,#5)|divide(#2,#6)| | "the number of positive integer solutions for the equatio fx 1 + x 2 + ⋯ + xn = k ( k - 1 ) c ( n - 1 ) - where k is the number and n is number of variable in the equation . 21 - 1 c 4 - 1 = 20 c 3 = 1140 answer : a" | general |
math_qa__Ko1nRkzHOQPw8pyc | Machine P and Machine Q are each used to manufacture 330 sprockets. It takes Machine P 10 hours longer to produce 330 sprockets than Machine Q. Machine Q produces 10% more sprockets per hour than Machine A. How many sprockets per hour does Machine A produce?
Choose the correct choice from the following answers:
A) 5
B) 15
C) 3
D) 95
E) 125 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">330 / (11/10)</gadget>
<output>300</output>
<gadget id="calculator">330 - 300</gadget>
<output>30</output>
<gadget id="calculator">30 / 10</gadget>
<output>3</output>
<result>C</result> | C | 3 | Machine P and Machine Q are each used to manufacture 330 sprockets. It takes Machine P 10 hours longer to produce 330 sprockets than Machine Q. Machine Q produces 10% more sprockets per hour than Machine A. How many sprockets per hour does Machine A produce? | {
"A": "5",
"B": "15",
"C": "3",
"D": "95",
"E": "125"
} | divide(subtract(330, divide(330, add(divide(10, const_100), const_1))), 10) | divide(n1,const_100)|add(#0,const_1)|divide(n0,#1)|subtract(n0,#2)|divide(#3,n1)| | "p makes x sprockets per hour . then q makes 1.1 x sprockets per hour . 330 / x = 330 / 1.1 x + 10 1.1 ( 330 ) = 330 + 11 x 11 x = 33 x = 3 the answer is c ." | gain |
math_qa__cjbYq60TMpi9Jume | At Veridux Corporation, there are 250 employees. Of these, 90 are female, and the rest are males. There are a total of 40 managers, and the rest of the employees are associates. If there are a total of 160 male associates, how many female managers are there? Options.
A) 40
B) 20
C) 25
D) 30
E) 35 | <gadget id="calculator">40 * 1</gadget>
<output>40</output>
<result>A</result> | A | 40 | At Veridux Corporation, there are 250 employees. Of these, 90 are female, and the rest are males. There are a total of 40 managers, and the rest of the employees are associates. If there are a total of 160 male associates, how many female managers are there? | {
"A": "40",
"B": "20",
"C": "25",
"D": "30",
"E": "35"
} | multiply(40, const_1) | multiply(n2,const_1) | 250 employees : 90 male , 160 female 40 managers , 210 associates 160 male associates implies 50 female associates which means the remaining 40 females must be managers a . 40 | general |
math_qa__kSq9Xje9E3BkUHvp | Think of a number, divide it by 5 and add 8 to it. The result is 61. What is the number thought of? Choose the correct choice from the following choices:
A) 24 B) 77 C) 297 D) 265 E) 29 | <gadget id="calculator">61 - 8</gadget>
<output>53</output>
<gadget id="calculator">53 * 5</gadget>
<output>265</output>
<result>D</result> | D | 265 | Think of a number, divide it by 5 and add 8 to it. The result is 61. What is the number thought of? | {
"A": "24",
"B": "77",
"C": "297",
"D": "265",
"E": "29"
} | multiply(subtract(61, 8), 5) | subtract(n2,n1)|multiply(n0,#0)| | "explanation : 61 - 6 = 53 53 x 5 = 265 answer : d" | general |
math_qa__3LObGxnBi14zi7gV | The ratio by weight, measured in pounds, of books to clothes to electronics in a suitcase initially stands at 7:4:3. Someone removes 8 pounds of clothing from the suitcase, thereby doubling the ratio of books to clothes. How many pounds do the electronics in the suitcase weigh? Select:
A) 6 B) 8 C) 10 D) 12 E) 14 | <gadget id="calculator">7 + 4</gadget>
<output>11</output>
<gadget id="calculator">11 + 3</gadget>
<output>14</output>
<gadget id="calculator">14 * 8</gadget>
<output>112</output>
<gadget id="calculator">-112</gadget>
<output>-112</output>
<gadget id="calculator">14 * 2</gadget>
<output>28</output>
<gadget id="calculator">14 * 4</gadget>
<output>56</output>
<gadget id="calculator">28 - 56</gadget>
<output>-28</output>
<gadget id="calculator">(-112) / (-28)</gadget>
<output>4</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<result>D</result> | D | 12 | The ratio by weight, measured in pounds, of books to clothes to electronics in a suitcase initially stands at 7:4:3. Someone removes 8 pounds of clothing from the suitcase, thereby doubling the ratio of books to clothes. How many pounds do the electronics in the suitcase weigh? | {
"A": "6",
"B": "8",
"C": "10",
"D": "12",
"E": "14"
} | multiply(3, divide(negate(multiply(add(add(7, 4), 3), 8)), subtract(multiply(add(add(7, 4), 3), const_2), multiply(add(add(7, 4), 3), 4)))) | add(n0,n1)|add(n2,#0)|multiply(n3,#1)|multiply(#1,const_2)|multiply(n1,#1)|negate(#2)|subtract(#3,#4)|divide(#5,#6)|multiply(n2,#7) | the weights of the items in the suitcase are 7 k , 4 k , and 3 k . if removing 8 pounds of clothes doubles the ratio of books to clothes , then 8 pounds represents half the weight of the clothes . 2 k = 8 pounds and then k = 4 pounds . the electronics weigh 3 ( 4 ) = 12 pounds . the answer is d . | other |
math_qa__JaemH6vg2nT4o02N | The radius of a semi circle is 2.1 cm then its perimeter is? Choose the correct choice from the following choices.
A) 32.5
B) 11.12
C) 32.1
D) 10.8
E) 32.3 | <gadget id="calculator">2 * pi * 2.1</gadget>
<output>4.2*pi = around 13.194689</output>
<gadget id="calculator">(4.2*pi) / 2</gadget>
<output>2.1*pi = around 6.597345</output>
<gadget id="calculator">2.1 * 2</gadget>
<output>4.2</output>
<gadget id="calculator">(2.1*pi) + 4.2</gadget>
<output>4.2 + 2.1*pi = around 10.797345</output>
<result>D</result> | D | 10.8 | The radius of a semi circle is 2.1 cm then its perimeter is? | {
"A": "32.5",
"B": "11.12",
"C": "32.1",
"D": "10.8",
"E": "32.3"
} | add(divide(circumface(2.1), const_2), multiply(2.1, const_2)) | circumface(n0)|multiply(n0,const_2)|divide(#0,const_2)|add(#2,#1)| | "36 / 7 r = 2.1 = 10.80 answer : d" | physics |
math_qa__V1tQjzJvxLghZjom | Which number should replace both the asterisks in (* /21) x (*/189) = 1 ? Choose the correct choice from the following answers.
A) 21 B) 63 C) 3969 D) 147 E) 167 | <gadget id="calculator">189 * 21</gadget>
<output>3_969</output>
<gadget id="calculator">3_969 ** (1/2)</gadget>
<output>63</output>
<result>B</result> | B | 63 | Which number should replace both the asterisks in (* /21) x (*/189) = 1 ? | {
"A": "21",
"B": "63",
"C": "3969",
"D": "147",
"E": "167"
} | sqrt(multiply(189, 21)) | multiply(n0,n1)|sqrt(#0)| | "answer let ( y / 21 ) x ( y / 189 ) = 1 then , y 2 = 21 x 189 = 21 x 21 x 9 ∴ y = ( 21 x 3 ) = 63 . option : b" | general |
math_qa__yRwurnsxIimSPuns | Trains A and B start simultaneously from stations 200 miles apart, and travel the same route toward each other on adjacent parallel tracks. If Train A and Train B travel at a constant rate of 20 miles per hour and 20 miles per hour, respectively, how many miles will Train A have traveled when the trains pass each other, to the nearest mile? Choose the correct choice from the following answers.
A) 100 B) 133 C) 150 D) 167 E) 188 | <gadget id="calculator">20 + 20</gadget>
<output>40</output>
<gadget id="calculator">200 / 40</gadget>
<output>5</output>
<gadget id="calculator">20 * 5</gadget>
<output>100</output>
<result>A</result> | A | 100 | Trains A and B start simultaneously from stations 200 miles apart, and travel the same route toward each other on adjacent parallel tracks. If Train A and Train B travel at a constant rate of 20 miles per hour and 20 miles per hour, respectively, how many miles will Train A have traveled when the trains pass each other, to the nearest mile? | {
"A": "100",
"B": "133",
"C": "150",
"D": "167",
"E": "188"
} | multiply(20, divide(200, add(20, 20))) | add(n1,n2)|divide(n0,#0)|multiply(n1,#1)| | "since we know the distance ( 200 ) and the combined rate ( 40 ) , we plug it into the formula : distance = rate * time 200 = 40 * time we can solve for the time they will meet cause we added the rate of train a and train b together . so the time will be 200 / 40 from dividing 40 on both sides to isolate time in the equation above . time will be 5 hours so now you can plug that in for train a ’ s distance . distance = rate * time distance = 20 * 5 distance = 100 according to answer choice a ." | physics |
math_qa__rFE2HRyTtCFWj06z | x = 13.165
y = 7.686
z = 11.545
The number A is obtained by first rounding the values of x, y, and z to the hundredths place and then adding the resulting values. The number B is obtained by first adding the values of x, y, and z and then rounding the sum to the hundredths place. What is the value of A – B? Pick one.
A) 0.01
B) 0.02
C) 0.03
D) 0.1
E) 0.2 | <gadget id="calculator">13.165 + 7.686</gadget>
<output>20.851</output>
<gadget id="calculator">20.851 + 11.545</gadget>
<output>32.396</output>
<gadget id="calculator">32.396 * 100</gadget>
<output>3_239.6</output>
<gadget id="calculator">floor(3_239.6)</gadget>
<output>3_239</output>
<gadget id="calculator">3_239 + 1</gadget>
<output>3_240</output>
<gadget id="calculator">11.545 * 100</gadget>
<output>1_154.5</output>
<gadget id="calculator">floor(1_154.5)</gadget>
<output>1_154</output>
<gadget id="calculator">13.165 * 100</gadget>
<output>1_316.5</output>
<gadget id="calculator">floor(1_316.5)</gadget>
<output>1_316</output>
<gadget id="calculator">7.686 * 100</gadget>
<output>768.6</output>
<gadget id="calculator">floor(768.6)</gadget>
<output>768</output>
<gadget id="calculator">1_316 + 768</gadget>
<output>2_084</output>
<gadget id="calculator">1_154 + 2_084</gadget>
<output>3_238</output>
<gadget id="calculator">3_240 - 3_238</gadget>
<output>2</output>
<gadget id="calculator">2 / 10</gadget>
<output>1/5 = around 0.2</output>
<result>E</result> | E | 0.2 | x = 13.165
y = 7.686
z = 11.545
The number A is obtained by first rounding the values of x, y, and z to the hundredths place and then adding the resulting values. The number B is obtained by first adding the values of x, y, and z and then rounding the sum to the hundredths place. What is the value of A – B? | {
"A": "0.01",
"B": "0.02",
"C": "0.03",
"D": "0.1",
"E": "0.2"
} | divide(subtract(add(floor(multiply(add(add(13.165, 7.686), 11.545), const_100)), const_1), add(floor(multiply(11.545, const_100)), add(floor(multiply(13.165, const_100)), floor(multiply(7.686, const_100))))), const_10) | add(n0,n1)|multiply(n0,const_100)|multiply(n1,const_100)|multiply(n2,const_100)|add(n2,#0)|floor(#1)|floor(#2)|floor(#3)|add(#5,#6)|multiply(#4,const_100)|add(#8,#7)|floor(#9)|add(#11,const_1)|subtract(#12,#10)|divide(#13,const_10) | rounding off the values : x = 13.17 y = 7.69 z = 11.55 a = 13.17 + 7.69 + 11.55 = 32.41 x + y + z = 13.165 + 7.686 + 11.545 = 32.206 b = 32.21 a - b = 0.2 option e | general |
math_qa__gELIJ4TBl7kR5t5H | The area of a square is 144 m². Find its perimeter.
Choose the correct choice from the following answers:
A) 18 m B) 28 m C) 38 m D) 42 m E) 48 m | <gadget id="calculator">144 ** (1/2)</gadget>
<output>12</output>
<gadget id="calculator">4 * 12</gadget>
<output>48</output>
<result>E</result> | E | 48 | The area of a square is 144 m². Find its perimeter. | {
"A": "18 m",
"B": "28 m",
"C": "38 m",
"D": "42 m",
"E": "48 m"
} | square_perimeter(sqrt(144)) | sqrt(n0)|square_perimeter(#0) | area of square = side × side given ; area of square = 144 m ² therefore , side ² = 144 m ² therefore , side = √ ( 144 m ² ) = √ ( 2 × 2 × 2 × 2 × 3 × 3 ) m ² = 2 × 2 × 3 m = 12 m now , the perimeter of the square = 4 x side = 4 × 12 m = 48 m answer : e | geometry |
math_qa__F1bKp8CS2TMmC9iH | How is 1% expressed as a decimal fraction? Options: A) 0.1 B) 0.001 C) 0.01 D) 0.0001 E) 1 | <gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<result>C</result> | C | 0.01 | How is 1% expressed as a decimal fraction? | {
"A": "0.1",
"B": "0.001",
"C": "0.01",
"D": "0.0001",
"E": "1"
} | divide(1, const_100) | divide(n0,const_100)| | "1 / 100 = 0.01 answer : c" | gain |
math_qa__Dcpz7OCzdDgeIBJl | A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2430 ? Choose the correct choice from the following options: A) s . 800 B) s . 810 C) s . 820 D) s . 900 E) s . 920 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">2_430 * (1/3)</gadget>
<output>810</output>
<result>B</result> | B | 810 | A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2430 ? | {
"A": "s . 800",
"B": "s . 810",
"C": "s . 820",
"D": "s . 900",
"E": "s . 920"
} | multiply(2430, divide(1, 3)) | divide(n0,n1)|multiply(n6,#0)| | "2430 * 1 / 3 = 810 option b" | general |
math_qa__nSa9cRP9c4fwAend | A person walks at a speed of 4 km/hr and runs at a speed of 8 km/hr. How many hours will the person require to cover a distance of 8 km, if the person completes half of the distance by walking and the other half by running? Pick: A) 0.5 B) 1.5 C) 2.5 D) 3.5 E) 4.5 | <gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">4 / 4</gadget>
<output>1</output>
<gadget id="calculator">4 / 8</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 + (1/2)</gadget>
<output>3/2 = around 1.5</output>
<result>B</result> | B | 1.5 | A person walks at a speed of 4 km/hr and runs at a speed of 8 km/hr. How many hours will the person require to cover a distance of 8 km, if the person completes half of the distance by walking and the other half by running? | {
"A": "0.5",
"B": "1.5",
"C": "2.5",
"D": "3.5",
"E": "4.5"
} | add(divide(divide(8, const_2), 4), divide(divide(8, const_2), 8)) | divide(n2,const_2)|divide(#0,n0)|divide(#0,n1)|add(#1,#2)| | "time = 4 / 4 + 4 / 8 = 12 / 8 = 1.5 hours the answer is b ." | physics |
math_qa__h7HyQ3jZlHwmQcS7 | Dacid obtained 45, 35, 52, 47 and 55 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?
Choose the correct choice from the following.
A) 79
B) 99
C) 47
D) 89
E) 45 | <gadget id="calculator">45 + 35</gadget>
<output>80</output>
<gadget id="calculator">80 + 52</gadget>
<output>132</output>
<gadget id="calculator">132 + 47</gadget>
<output>179</output>
<gadget id="calculator">179 + 55</gadget>
<output>234</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">234 / 5</gadget>
<output>234/5 = around 46.8</output>
<result>C</result> | C | 47 | Dacid obtained 45, 35, 52, 47 and 55 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks? | {
"A": "79",
"B": "99",
"C": "47",
"D": "89",
"E": "45"
} | divide(add(add(add(add(45, 35), 52), 47), 55), divide(const_10, const_2)) | add(n0,n1)|divide(const_10,const_2)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1) | average = ( 45 + 35 + 52 + 47 + 55 ) / 5 = 234 / 5 = 47 . answer : c | general |
math_qa__ggt3lTmg5NZZYjKw | The product of a and b is equal to 10 more than twice the sum of a and b. If b = 9, what is the value of b - a?
Select the correct option: A) 2 B) 5 C) 7 D) 24 E) 35 | <gadget id="calculator">9 * 2</gadget>
<output>18</output>
<gadget id="calculator">18 + 10</gadget>
<output>28</output>
<gadget id="calculator">9 - 2</gadget>
<output>7</output>
<gadget id="calculator">28 / 7</gadget>
<output>4</output>
<gadget id="calculator">9 - 4</gadget>
<output>5</output>
<result>B</result> | B | 5 | The product of a and b is equal to 10 more than twice the sum of a and b. If b = 9, what is the value of b - a? | {
"A": "2",
"B": "5",
"C": "7",
"D": "24",
"E": "35"
} | subtract(9, divide(add(multiply(9, const_2), 10), subtract(9, const_2))) | multiply(n1,const_2)|subtract(n1,const_2)|add(n0,#0)|divide(#2,#1)|subtract(n1,#3)| | "ab = 10 + 2 ( a + b ) 9 a = 10 + 2 a + 18 7 a = 28 a = 4 b - a = 9 - 4 = 5 b is the answer" | general |
math_qa__rmAtmSb9ugwwTWQI | How many times digit 2 is used while writing numbers from 400 to 700? Choose the most appropriate option:
A) 150
B) 190
C) 250
D) 80
E) 130 | <gadget id="calculator">700 - 400</gadget>
<output>300</output>
<gadget id="calculator">300 / 10</gadget>
<output>30</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 11</gadget>
<output>121</output>
<gadget id="calculator">30 + 121</gadget>
<output>151</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">151 + 4</gadget>
<output>155</output>
<result>A</result> | A | 150 | How many times digit 2 is used while writing numbers from 400 to 700? | {
"A": "150",
"B": "190",
"C": "250",
"D": "80",
"E": "130"
} | add(add(divide(subtract(700, 400), const_10), multiply(add(const_10, const_1), add(const_10, const_1))), multiply(2, const_2)) | add(const_1,const_10)|multiply(n0,const_2)|subtract(n2,n1)|divide(#2,const_10)|multiply(#0,#0)|add(#3,#4)|add(#5,#1)| | "in 400 to 500 there are 50 two ' s in 500 to 600 there are 50 two ' s in 600 to 700 there are 50 two ' s so total is 150 two ' s correct option : a" | general |
math_qa__S1QW42dDqBd4IgED | Lionel left his house and walked towards Walt's house, 48 miles away. Two hours later, Walt left his house and ran towards Lionel's house. If Lionel's speed was 2 miles per hour and Walt's 6 miles per hour, how many miles had Lionel walked when he met Walt? Options:
A) 12
B) 15
C) 20
D) 24
E) 28 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">48 - 4</gadget>
<output>44</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">44 / 8</gadget>
<output>11/2 = around 5.5</output>
<gadget id="calculator">(11/2) + 2</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">2 * (15/2)</gadget>
<output>15</output>
<result>B</result> | B | 15 | Lionel left his house and walked towards Walt's house, 48 miles away. Two hours later, Walt left his house and ran towards Lionel's house. If Lionel's speed was 2 miles per hour and Walt's 6 miles per hour, how many miles had Lionel walked when he met Walt? | {
"A": "12",
"B": "15",
"C": "20",
"D": "24",
"E": "28"
} | multiply(2, add(divide(subtract(48, multiply(2, const_2)), add(6, 2)), const_2)) | add(n1,n2)|multiply(n1,const_2)|subtract(n0,#1)|divide(#2,#0)|add(#3,const_2)|multiply(n1,#4) | in the first 2 hours lionel at the rate of 2 miles per hour covered distance = rate * time = 2 * 2 = 4 miles . so , the distance between him and walt was 48 - 4 = 44 miles when walt left his house . now , their combined rate to cover this distance was 2 + 6 = 8 miles per hour , hence they will meet ( they will cover that distance ) in time = distance / rate = 44 / 8 = 5.5 hours . total time that lionel was walking is 2 + 5.5 = 7.5 hours , which means that he covered in that time interval distance = rate * time = 2 * 7.5 = 15 miles . answer : b . | physics |
math_qa__8UpYWMig82bZUE2x | The ratio of the volumes of two cubes is 2744 : 3375. What is the ratio of their total surface areas? Pick:
A) 71 : 76
B) 71 : 131
C) 71 : 145
D) 71 : 167
E) 71 : 113 | <gadget id="calculator">2_744 / 3_375</gadget>
<output>2_744/3_375 = around 0.813037</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(2_744/3_375) ** (1/3)</gadget>
<output>14/15 = around 0.933333</output>
<result>A</result> | A | 0.934211 | The ratio of the volumes of two cubes is 2744 : 3375. What is the ratio of their total surface areas? | {
"A": "71 : 76",
"B": "71 : 131",
"C": "71 : 145",
"D": "71 : 167",
"E": "71 : 113"
} | power(divide(2744, 3375), divide(const_1, const_3)) | divide(n0,n1)|divide(const_1,const_3)|power(#0,#1)| | "ratio of the sides = ³ √ 2744 : ³ √ 3375 = 14 : 15 ratio of surface areas = 142 : 152 = 71 : 76 answer : a" | geometry |
math_qa__2UCuBh7Kt1cAXFwr | A and B started a business investing Rs. 90,000 and Rs 20,000 respectively. In what ratio the profit earned after 2 years be divided between A and B respectively?
Select
A) 3 : 2
B) 9 : 2
C) 18 : 20
D) 1 : 4
E) 18 : 4 | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<gadget id="calculator">9 * 10</gadget>
<output>90</output>
<gadget id="calculator">90 + 2</gadget>
<output>92</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">92 / 20</gadget>
<output>23/5 = around 4.6</output>
<result>B</result> | B | 4.5 | A and B started a business investing Rs. 90,000 and Rs 20,000 respectively. In what ratio the profit earned after 2 years be divided between A and B respectively? | {
"A": "3 : 2",
"B": "9 : 2",
"C": "18 : 20",
"D": "1 : 4",
"E": "18 : 4"
} | divide(add(multiply(multiply(const_3, const_3), add(multiply(const_3, const_3), const_1)), 2), multiply(2, add(multiply(const_3, const_3), const_1))) | multiply(const_3,const_3)|add(#0,const_1)|multiply(#1,#0)|multiply(n2,#1)|add(n2,#2)|divide(#4,#3)| | "a : b = 90000 : 20000 = 90 : 20 = 18 : 4 = 9 : 2 answer : b" | gain |
math_qa__zYPuAZHboebrYdkg | The compound interest on $2000 at 10% per annum is $662. The period(in years) is? Pick one:
A) 2
B) 3
C) 4
D) 5
E) 6 | <gadget id="calculator">2_000 / 662</gadget>
<output>1_000/331 = around 3.021148</output>
<result>B</result> | B | 3 | The compound interest on $2000 at 10% per annum is $662. The period(in years) is? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | divide(2000, 662) | divide(n0,n2) | a = p ( 1 + r / 100 ) ^ t 2662 = 2000 ( 1 + 10 / 100 ) ^ t ( 11 / 10 ) ^ t = 2662 / 2000 ( 11 / 10 ) ^ t = ( 11 / 10 ) ^ 3 t = 3 years answer is b | gain |
math_qa__mWGXDrTuGWHpKXng | If a 10 percent deposit that has been paid toward the purchase of a certain product is $150, how much more remains to be paid? Choose the correct choice from the following answers:
A) $ 880
B) $ 990
C) $ 1,350
D) $ 1,100
E) $ 1,210 | <gadget id="calculator">100 / 10</gadget>
<output>10</output>
<gadget id="calculator">150 * 10</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 - 150</gadget>
<output>1_350</output>
<result>C</result> | C | 1,350 | If a 10 percent deposit that has been paid toward the purchase of a certain product is $150, how much more remains to be paid? | {
"A": "$ 880",
"B": "$ 990",
"C": "$ 1,350",
"D": "$ 1,100",
"E": "$ 1,210"
} | subtract(multiply(150, divide(const_100, 10)), 150) | divide(const_100,n0)|multiply(n1,#0)|subtract(#1,n1)| | "10 / 100 p = 150 > > p = 150 * 100 / 10 = 1500 1500 - 150 = 1350 answer : c" | general |
math_qa__eBwtbFiJU4GDxWVB | An object thrown directly upward is at a height of h feet after t seconds, where h = -15 (t-3)^2 + 150. At what height, in feet, is the object 2 seconds after it reaches its maximum height? Pick: A) 90 B) 98 C) 106 D) 120 E) 136 | <gadget id="calculator">-15</gadget>
<output>-15</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">(-15) * 4</gadget>
<output>-60</output>
<gadget id="calculator">(-60) + 150</gadget>
<output>90</output>
<result>A</result> | A | 90 | An object thrown directly upward is at a height of h feet after t seconds, where h = -15 (t-3)^2 + 150. At what height, in feet, is the object 2 seconds after it reaches its maximum height? | {
"A": "90",
"B": "98",
"C": "106",
"D": "120",
"E": "136"
} | add(multiply(negate(15), power(subtract(add(3, 2), 3), const_2)), 150) | add(n1,n2)|negate(n0)|subtract(#0,n1)|power(#2,const_2)|multiply(#1,#3)|add(n3,#4) | we see that h will be a maximum h = 150 when t - 3 = 0 , that is when t = 3 . at t = 5 , h = - 15 ( 5 - 3 ) ^ 2 + 150 = - 15 ( 4 ) + 150 = 90 the answer is a . | general |
math_qa__Du7Xab3ymB5SXpoy | The average of 6 observations is 13. A new observation is included and the new average is decreased by 1. The seventh observation is?
Pick one.
A) 1 B) 3 C) 5 D) 6 E) 7 | <gadget id="calculator">13 - 1</gadget>
<output>12</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">12 * 7</gadget>
<output>84</output>
<gadget id="calculator">13 * 6</gadget>
<output>78</output>
<gadget id="calculator">84 - 78</gadget>
<output>6</output>
<result>D</result> | D | 6 | The average of 6 observations is 13. A new observation is included and the new average is decreased by 1. The seventh observation is? | {
"A": "1",
"B": "3",
"C": "5",
"D": "6",
"E": "7"
} | subtract(multiply(subtract(13, 1), add(6, 1)), multiply(13, 6)) | add(n0,n2)|multiply(n0,n1)|subtract(n1,n2)|multiply(#0,#2)|subtract(#3,#1) | let seventh observation = x . then , according to the question we have = > ( 78 + x ) / 7 = 12 = > x = 6 . hence , the seventh observation is 6 . answer : d | general |
math_qa__klrAIydFPNC69Dhm | A women in her conversation said " if u reverse my own age, in figures represent my husbands age. he is of course senior to me and difference between our age is one 0ne-eleventh of their sum. what is the woman's and her husbands age?
Pick one:
A) 4554 B) 4657 C) 8457 D) 3458 E) 5254 | <gadget id="calculator">1_000 * 1</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 * 4</gadget>
<output>4_000</output>
<gadget id="calculator">1_000 / 2</gadget>
<output>500</output>
<gadget id="calculator">4_000 + 500</gadget>
<output>4_500</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 10</gadget>
<output>50</output>
<gadget id="calculator">4_500 + 50</gadget>
<output>4_550</output>
<result>A</result> | A | 4,554 | A women in her conversation said " if u reverse my own age, in figures represent my husbands age. he is of course senior to me and difference between our age is one 0ne-eleventh of their sum. what is the woman's and her husbands age? | {
"A": "4554",
"B": "4657",
"C": "8457",
"D": "3458",
"E": "5254"
} | add(add(multiply(multiply(const_1000, const_1), const_4), divide(multiply(const_1000, const_1), const_2)), multiply(add(const_4, const_1), const_10)) | add(const_1,const_4)|multiply(const_1,const_1000)|divide(#1,const_2)|multiply(#1,const_4)|multiply(#0,const_10)|add(#2,#3)|add(#5,#4) | let man , s age be xy the woman ' s age is yx then 10 x + y - 10 y - x = 1 / 11 ( 10 x + y + 10 y + x ) 9 x - 9 y = x + y 8 x = 10 y x / y = 10 / 8 = 5 / 4 so xy = 54 and yx = 45 answer : a | general |
math_qa__2EOn6vpoFjmgrQvH | If 4 men working 10 hours a day earn Rs. 600 per week, then 9 men working 6 hours a day will earn how much per week? Choose the correct choice from the following answers
A) rs 840
B) rs 320
C) rs 810
D) rs 680
E) none of these | <gadget id="calculator">9 * 6</gadget>
<output>54</output>
<gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">54 / 40</gadget>
<output>27/20 = around 1.35</output>
<gadget id="calculator">(27/20) * 600</gadget>
<output>810</output>
<result>C</result> | C | 810 | If 4 men working 10 hours a day earn Rs. 600 per week, then 9 men working 6 hours a day will earn how much per week? | {
"A": "rs 840",
"B": "rs 320",
"C": "rs 810",
"D": "rs 680",
"E": "none of these"
} | multiply(divide(multiply(9, 6), multiply(4, 10)), 600) | multiply(n3,n4)|multiply(n0,n1)|divide(#0,#1)|multiply(n2,#2)| | "explanation : ( men 4 : 9 ) : ( hrs / day 10 : 6 ) : : 600 : x hence 4 * 10 * x = 9 * 6 * 600 or x = 9 * 6 * 600 / 4 * 10 = 810 answer : c" | physics |
math_qa__H9HoqEwwjLNAbshv | A dog breeder currently has 9 breeding dogs. 6 of the dogs have exactly 1 littermate, and 3 of the dogs have exactly 2 littermates. If 2 dogs are selected at random, what is the probability Q that both selected dogs are NOT littermates? Choose the correct choice from the following:
A) 1 / 6 B) 2 / 9 C) 5 / 6 D) 7 / 9 E) 8 / 9 | <gadget id="calculator">5 / 6</gadget>
<output>5/6 = around 0.833333</output>
<result>C</result> | C | 0.833333 | A dog breeder currently has 9 breeding dogs. 6 of the dogs have exactly 1 littermate, and 3 of the dogs have exactly 2 littermates. If 2 dogs are selected at random, what is the probability Q that both selected dogs are NOT littermates? | {
"A": "1 / 6",
"B": "2 / 9",
"C": "5 / 6",
"D": "7 / 9",
"E": "8 / 9"
} | divide(const_5, 6) | divide(const_5,n1)| | "we have three pairs of dogs for the 6 with exactly one littermate , and one triplet , with each having exactly two littermates . so , in fact there are two types of dogs : those with one littermate - say a , and the others with two littermates - b . work with probabilities : choosing two dogs , we can have either one dog of type b or none ( we can not have two dogs both of type b ) . the probability of choosing one dog of type b and one of type a is 3 / 9 * 6 / 8 * 2 = 1 / 2 ( the factor of 2 for the two possibilities ba and ab ) . the probability of choosing two dogs of type a which are not littermates is 6 / 9 * 4 / 8 = 1 / 3 ( choose one a , then another a which is n ' t the previous one ' s littermate ) . the required probability is 1 / 2 + 1 / 3 = 5 / 6 . find the probability for the complementary event : choose aa or bb . probability of choosing two dogs of type a who are littermates is 6 / 9 * 1 / 8 = 1 / 12 . probability of choosing two dogs of type b ( who necessarily are littermates ) is 3 / 9 * 2 / 8 q = 1 / 12 . again , we obtain 1 - ( 1 / 12 + 1 / 12 ) = 5 / 6 . answer : c" | other |
math_qa__VYvylEmbTrFMswlL | A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 20.25, the number of the member is the group is: Options.
A) 57
B) 67
C) 45
D) 47
E) 97 | <gadget id="calculator">20.25 * 100</gadget>
<output>2_025</output>
<gadget id="calculator">2_025 ** (1/2)</gadget>
<output>45</output>
<result>C</result> | C | 45 | A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 20.25, the number of the member is the group is: | {
"A": "57",
"B": "67",
"C": "45",
"D": "47",
"E": "97"
} | sqrt(multiply(20.25, const_100)) | multiply(n0,const_100)|sqrt(#0)| | "money collected = ( 20.25 x 100 ) paise = 2025 paise numbers of members = 2025 squareroot = 45 answer c" | general |
math_qa__qfUGmka9AU3yxDlx | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 12 sec. What is the length of the platform?
Pick
A) 187 m B) 350 m C) 267 m D) 287 m E) 675 m | <gadget id="calculator">300 / 12</gadget>
<output>25</output>
<gadget id="calculator">25 * 39</gadget>
<output>975</output>
<gadget id="calculator">975 - 300</gadget>
<output>675</output>
<result>E</result> | E | 675 | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 12 sec. What is the length of the platform? | {
"A": "187 m",
"B": "350 m",
"C": "267 m",
"D": "287 m",
"E": "675 m"
} | subtract(multiply(speed(300, 12), 39), 300) | speed(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = 300 / 12 = 25 m / sec . let the length of the platform be x meters . then , ( x + 300 ) / 39 = 25 = > x = 675 m . answer : e" | physics |
math_qa__eoVa8N9N1uTsjaFE | Mr. Karan borrowed a certain amount at 6% per annum simple interest for 9 years. After 9 years, he returned Rs. 8510/-. Find out the amount that he borrowed. Choose one: A) s . 5266 B) s . 5269 C) s . 5228 D) s . 5218 E) s . 5526 | <gadget id="calculator">6 * 9</gadget>
<output>54</output>
<gadget id="calculator">54 / 100</gadget>
<output>27/50 = around 0.54</output>
<gadget id="calculator">1 + (27/50)</gadget>
<output>77/50 = around 1.54</output>
<gadget id="calculator">8_510 / (77/50)</gadget>
<output>425_500/77 = around 5_525.974026</output>
<result>E</result> | E | 5,526 | Mr. Karan borrowed a certain amount at 6% per annum simple interest for 9 years. After 9 years, he returned Rs. 8510/-. Find out the amount that he borrowed. | {
"A": "s . 5266",
"B": "s . 5269",
"C": "s . 5228",
"D": "s . 5218",
"E": "s . 5526"
} | divide(8510, add(const_1, divide(multiply(6, 9), const_100))) | multiply(n0,n1)|divide(#0,const_100)|add(#1,const_1)|divide(n3,#2)| | "explanation : let us assume mr . karan borrowed amount is rs . a . ( the principal ) by formula of simple interest , s . i . = prt / 100 where p = the principal , r = rate of interest as a % , t = time in years s . i . = ( p * 6 * 9 ) / 100 = 54 p / 100 amount = principal + s . i . 8510 = p + ( 54 p / 100 ) 8510 = ( 100 p + 54 p ) / 100 8510 = 154 p / 100 p = ( 8510 * 100 ) / 154 = rs . 5525.974 answer : e" | gain |
math_qa__NXw8A8U07sqsOzdE | If the sum of two numbers is 24 and the sum of their squares is 400, then the product of the numbers is Select.
A) 40 B) 44 C) 80 D) 88 E) 48 | <gadget id="calculator">24 ** 2</gadget>
<output>576</output>
<gadget id="calculator">576 - 400</gadget>
<output>176</output>
<gadget id="calculator">176 / 2</gadget>
<output>88</output>
<result>D</result> | D | 88 | If the sum of two numbers is 24 and the sum of their squares is 400, then the product of the numbers is | {
"A": "40",
"B": "44",
"C": "80",
"D": "88",
"E": "48"
} | divide(subtract(power(24, const_2), 400), const_2) | power(n0,const_2)|subtract(#0,n1)|divide(#1,const_2)| | "according to the given conditions x + y = 24 and x ^ 2 + y ^ 2 = 400 now ( x + y ) ^ 2 = x ^ 2 + y ^ 2 + 2 xy so 24 ^ 2 = 400 + 2 xy so xy = 176 / 2 = 88 answer : d" | general |
math_qa__gynotZN8kZRfwV6Z | If the area of a square with sides of length 6 centimeters is equal to the area of a rectangle with a width of 4 centimeters, what is the length of the rectangle, in centimeters? Choose the correct answer:
A) 4
B) 8
C) 12
D) 9
E) 18 | <gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">36 / 4</gadget>
<output>9</output>
<result>D</result> | D | 9 | If the area of a square with sides of length 6 centimeters is equal to the area of a rectangle with a width of 4 centimeters, what is the length of the rectangle, in centimeters? | {
"A": "4",
"B": "8",
"C": "12",
"D": "9",
"E": "18"
} | divide(power(6, const_2), 4) | power(n0,const_2)|divide(#0,n1)| | "let length of rectangle = l 6 ^ 2 = l * 4 = > l = 36 / 4 = 9 answer d" | geometry |
math_qa__MBV6rH6Ia2R1DvuW | the sum of 3 consecutive multiples of 3 is 117 . what is the largest number ? Choose the correct choice from the following choices.
A) 45 B) 48 C) 51 D) 42 E) 54 | <gadget id="calculator">117 / 3</gadget>
<output>39</output>
<gadget id="calculator">39 + 3</gadget>
<output>42</output>
<result>D</result> | D | 42 | the sum of 3 consecutive multiples of 3 is 117 . what is the largest number ? | {
"A": "45",
"B": "48",
"C": "51",
"D": "42",
"E": "54"
} | add(divide(117, 3), 3) | divide(n2,n0)|add(n0,#0) | let the numbers be 3 x , 3 x + 3 and 3 x + 6 . then , 3 x + ( 3 x + 3 ) + ( 3 x + 6 ) = 117 9 x = 108 x = 12 largest number = 3 x + 6 = 42 answer : d | general |
math_qa__coSB5ZXhwu42NMys | If the cost price of 81 chocolates is equal to the selling price of 45 chocolates, the gain percent is : Choose the correct option
A) 80 % B) 85 % C) 82 % D) 70 % E) 75 % | <gadget id="calculator">81 - 45</gadget>
<output>36</output>
<gadget id="calculator">45 / 36</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">100 / (5/4)</gadget>
<output>80</output>
<result>A</result> | A | 80 | If the cost price of 81 chocolates is equal to the selling price of 45 chocolates, the gain percent is : | {
"A": "80 %",
"B": "85 %",
"C": "82 %",
"D": "70 %",
"E": "75 %"
} | divide(const_100, divide(45, subtract(81, 45))) | subtract(n0,n1)|divide(n1,#0)|divide(const_100,#1)| | "explanation : solution : let c . p . of each chocolate be re . 1 . then , c . p . of 45 chocolates = rs . 45 ; s . p . of 45 chocolates = rs . 81 . . ' . gain % = 36 * 100 / 45 = 80 % answer : a" | gain |
math_qa__crX1AyLfCNYfcraK | Company Z has 50 employees. If the number of employees having birthdays on Wednesday is more than the number of employees having birthdays on any other day of the week, each of which have same number of birth-days, what is the minimum number of employees having birthdays on Wednesday.
Choose the correct choice:
A) 6 B) 7 C) 8 D) 9 E) 12 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">50 / 7</gadget>
<output>50/7 = around 7.142857</output>
<gadget id="calculator">floor(50/7)</gadget>
<output>7</output>
<gadget id="calculator">7 + 1</gadget>
<output>8</output>
<gadget id="calculator">4 + 8</gadget>
<output>12</output>
<result>E</result> | E | 12 | Company Z has 50 employees. If the number of employees having birthdays on Wednesday is more than the number of employees having birthdays on any other day of the week, each of which have same number of birth-days, what is the minimum number of employees having birthdays on Wednesday. | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "12"
} | add(const_4, add(floor(divide(50, add(const_4, const_3))), const_1)) | add(const_3,const_4)|divide(n0,#0)|floor(#1)|add(#2,const_1)|add(#3,const_4)| | "say the number of people having birthdays on wednesday is x and the number of people having birthdays on each of the other 6 days is y . then x + 6 y = 50 . now , plug options for x . only a and e give an integer value for y . but only for e x > y as needed . answer : e ." | general |
math_qa__RBwXh5clqrNzEqYP | The cost price of an article is 64% of the marked price. Calculate the gain percent after allowing a discount of 18%?
Choose the correct choice from the following choices.
A) 37.5 %
B) 48 %
C) 50.5 %
D) 28.125 %
E) 56 % | <gadget id="calculator">100 - 18</gadget>
<output>82</output>
<gadget id="calculator">82 / 64</gadget>
<output>41/32 = around 1.28125</output>
<gadget id="calculator">(41/32) - 1</gadget>
<output>9/32 = around 0.28125</output>
<gadget id="calculator">(9/32) * 100</gadget>
<output>225/8 = around 28.125</output>
<result>D</result> | D | 28.125 | The cost price of an article is 64% of the marked price. Calculate the gain percent after allowing a discount of 18%? | {
"A": "37.5 %",
"B": "48 %",
"C": "50.5 %",
"D": "28.125 %",
"E": "56 %"
} | multiply(subtract(divide(subtract(const_100, 18), 64), const_1), const_100) | subtract(const_100,n1)|divide(#0,n0)|subtract(#1,const_1)|multiply(#2,const_100)| | "explanation : let marked price = rs . 100 . then , c . p . = rs . 64 , s . p . = rs . 82 gain % = 18 / 64 * 100 = 28.125 % . answer : option d" | gain |
math_qa__wW6cMd0OkobSyuYL | The membership of a committee consists of 3 English teachers, 4 Mathematics teachers, and 2 Social Studies teachers. If 2 committee members are to be selected at random to write the committee’s report, what is the probability that the two members selected will both be maths teachers? Choose the correct choice:
A) 2 / 3 B) 1 / 3 C) 2 / 9 D) 1 / 24 E) 1 / 12 | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 + 2</gadget>
<output>9</output>
<gadget id="calculator">3 / 9</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">2 / 8</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/3) * (1/4)</gadget>
<output>1/12 = around 0.083333</output>
<result>E</result> | E | 0.083333 | The membership of a committee consists of 3 English teachers, 4 Mathematics teachers, and 2 Social Studies teachers. If 2 committee members are to be selected at random to write the committee’s report, what is the probability that the two members selected will both be maths teachers? | {
"A": "2 / 3",
"B": "1 / 3",
"C": "2 / 9",
"D": "1 / 24",
"E": "1 / 12"
} | multiply(divide(3, add(add(3, 4), 2)), divide(2, subtract(add(add(3, 4), 2), const_1))) | add(n0,n1)|add(n2,#0)|divide(n0,#1)|subtract(#1,const_1)|divide(n2,#3)|multiply(#2,#4) | probability of first member an english teacher = 3 / 9 probability of second member an english teacher = 2 / 8 probability of both being english teacher = 3 / 9 x 2 / 8 = 1 / 12 ( e ) | probability |
math_qa__llJtLxOworVXmfhb | In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 75 questions and secures 125 marks, the number of questions he attempts correctly, is :
Answers:
A) 38 B) 40 C) 26 D) 25 E) 11 | <gadget id="calculator">125 + 75</gadget>
<output>200</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">200 / 5</gadget>
<output>40</output>
<result>B</result> | B | 40 | In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 75 questions and secures 125 marks, the number of questions he attempts correctly, is : | {
"A": "38",
"B": "40",
"C": "26",
"D": "25",
"E": "11"
} | divide(add(125, 75), add(4, 1)) | add(n2,n3)|add(n0,n1)|divide(#0,#1)| | "explanation : let the number of correct answers be x . then numbers of incorrect answers will be 75 – x we get 4 x – ( 75 – x ) × 1 = 125 on solving the equation we get x = 40 answer : b" | physics |
math_qa__aHyCtXuoYnadhOpO | The value of x.320 ÷ 2 ÷ 3 = X
Choose the correct choice from the following choices
A) 53.33 B) 46.33 C) 15.36 D) 15.45 E) 15.48 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">5 * 10</gadget>
<output>50</output>
<gadget id="calculator">3 + 50</gadget>
<output>53</output>
<gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">30 + 3</gadget>
<output>33</output>
<gadget id="calculator">33 / 100</gadget>
<output>33/100 = around 0.33</output>
<gadget id="calculator">53 + (33/100)</gadget>
<output>5_333/100 = around 53.33</output>
<result>A</result> | A | 53.33 | The value of x.320 ÷ 2 ÷ 3 = X | {
"A": "53.33",
"B": "46.33",
"C": "15.36",
"D": "15.45",
"E": "15.48"
} | add(add(const_3, multiply(add(const_1, const_4), const_10)), divide(add(multiply(3, const_10), const_3), const_100)) | add(const_1,const_4)|multiply(n2,const_10)|add(#1,const_3)|multiply(#0,const_10)|add(#3,const_3)|divide(#2,const_100)|add(#4,#5) | 320 ã · 2 ã · 3 = 320 ã — 1 / 2 ã — 1 / 3 = 160 / 3 = 53.33 correct answer : a | general |
math_qa__fnKW3dJ9WIenXjzA | Two employees X and Y are paid a total of Rs. 580 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week? Choose the correct choice from the following answers
A) s . 263 B) s . 283 C) s . 293 D) s . 300 E) s . 383 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">580 * 10</gadget>
<output>5_800</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="calculator">5_800 / 22</gadget>
<output>2_900/11 = around 263.636364</output>
<result>A</result> | A | 263 | Two employees X and Y are paid a total of Rs. 580 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week? | {
"A": "s . 263",
"B": "s . 283",
"C": "s . 293",
"D": "s . 300",
"E": "s . 383"
} | divide(multiply(580, multiply(add(const_1, const_4), const_2)), multiply(add(multiply(add(const_1, const_4), const_2), const_1), const_2)) | add(const_1,const_4)|multiply(#0,const_2)|add(#1,const_1)|multiply(n0,#1)|multiply(#2,const_2)|divide(#3,#4)| | "let the amount paid to x per week = x and the amount paid to y per week = y then x + y = 580 but x = 120 % of y = 120 y / 100 = 12 y / 10 ∴ 12 y / 10 + y = 580 ⇒ y [ 12 / 10 + 1 ] = 580 ⇒ 22 y / 10 = 580 ⇒ 22 y = 5800 ⇒ y = 5800 / 22 = rs . 263 a )" | general |
math_qa__yNwai10Ow1ms6j7N | Two trains of length 120 m and 300 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet?
Choose the correct option
A) 21 sec B) 32 sec C) 82 sec D) 20 sec E) 89 sec | <gadget id="calculator">120 + 300</gadget>
<output>420</output>
<gadget id="calculator">42 + 30</gadget>
<output>72</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">420 / 20</gadget>
<output>21</output>
<result>A</result> | A | 21 | Two trains of length 120 m and 300 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet? | {
"A": "21 sec",
"B": "32 sec",
"C": "82 sec",
"D": "20 sec",
"E": "89 sec"
} | divide(add(120, 300), multiply(add(42, 30), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2) | relative speed = ( 42 + 30 ) * 5 / 18 = 4 * 5 = 20 mps . distance covered in passing each other = 120 + 300 = 420 m . the time required = d / s = 420 / 20 = 21 sec . answer : a | physics |
math_qa__0cuFCF7adt03t1Jj | Two trains of length 100 m and 220 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet? Choose the correct choice from the following answers: A) 18 sec B) 70 sec C) 21 sec D) 20 sec E) 16 sec | <gadget id="calculator">100 + 220</gadget>
<output>320</output>
<gadget id="calculator">42 + 30</gadget>
<output>72</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">320 / 20</gadget>
<output>16</output>
<result>E</result> | E | 16 | Two trains of length 100 m and 220 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet? | {
"A": "18 sec",
"B": "70 sec",
"C": "21 sec",
"D": "20 sec",
"E": "16 sec"
} | divide(add(100, 220), multiply(add(42, 30), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = ( 42 + 30 ) * 5 / 18 = 4 * 5 = 20 mps . distance covered in passing each other = 100 + 220 = 320 m . the time required = d / s = 320 / 20 = 16 sec . answer : e" | physics |
math_qa__xrC9Wzawg3OOAYKp | What positive number, when squared, is equal to the cube of the positive square root of 18? Choose one:
A) 64 B) 32 C) 8 D) 4 E) 9 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">18 ** (1/2)</gadget>
<output>3*sqrt(2) = around 4.242641</output>
<gadget id="calculator">(3*sqrt(2)) ** 3</gadget>
<output>54*sqrt(2) = around 76.367532</output>
<gadget id="calculator">(54*sqrt(2)) ** (1/2)</gadget>
<output>3*2**(3/4)*sqrt(3) = around 8.738852</output>
<result>E</result> | E | 9 | What positive number, when squared, is equal to the cube of the positive square root of 18? | {
"A": "64",
"B": "32",
"C": "8",
"D": "4",
"E": "9"
} | sqrt(power(power(18, divide(const_1, const_2)), const_3)) | divide(const_1,const_2)|power(n0,#0)|power(#1,const_3)|sqrt(#2)| | "let the positive number be x x ^ 2 = ( ( 18 ) ^ ( 1 / 2 ) ) ^ 3 = > x ^ 2 = 4 ^ 3 = 81 = > x = 9 answer e" | geometry |
math_qa__VFKhyVGTgs8ifFQM | 210 college students were asked in a survey if they preferred Windows or Mac brand computers. 60 Students claimed that they preferred Mac to Windows brand computers. One third as many of the students who preferred Mac to Windows, equally preferred both brands. 90 of the students had no preference. How many of the students in the survey preferred Windows to Mac brand computers? Choose the correct choice.
A) 25
B) 40
C) 50
D) 60
E) 75 | <gadget id="calculator">210 - 90</gadget>
<output>120</output>
<gadget id="calculator">120 - 60</gadget>
<output>60</output>
<gadget id="calculator">60 / 3</gadget>
<output>20</output>
<gadget id="calculator">60 - 20</gadget>
<output>40</output>
<result>B</result> | B | 40 | 210 college students were asked in a survey if they preferred Windows or Mac brand computers. 60 Students claimed that they preferred Mac to Windows brand computers. One third as many of the students who preferred Mac to Windows, equally preferred both brands. 90 of the students had no preference. How many of the students in the survey preferred Windows to Mac brand computers? | {
"A": "25",
"B": "40",
"C": "50",
"D": "60",
"E": "75"
} | subtract(subtract(subtract(210, 90), 60), divide(subtract(subtract(210, 90), 60), const_3)) | subtract(n0,n2)|subtract(#0,n1)|divide(#1,const_3)|subtract(#1,#2) | 120 = 60 ( mac ) + x ( window ) + 20 ( both ) = > x = 40 answer : b | other |
math_qa__tNDpyVQFCD5p96N1 | If a truck is traveling at a constant rate of 36 kilometers per hour, how many seconds will it take the truck to travel a distance of 600 meters? (1 kilometer = 1000 meters) Choose the correct answer
A) 18 B) 24 C) 60 D) 36 E) 48 | <gadget id="calculator">600 / 1_000</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) / 36</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(1/60) * 3_600</gadget>
<output>60</output>
<result>C</result> | C | 60 | If a truck is traveling at a constant rate of 36 kilometers per hour, how many seconds will it take the truck to travel a distance of 600 meters? (1 kilometer = 1000 meters) | {
"A": "18",
"B": "24",
"C": "60",
"D": "36",
"E": "48"
} | multiply(divide(divide(600, 1000), 36), const_3600) | divide(n1,n3)|divide(#0,n0)|multiply(#1,const_3600)| | "speed = 36 km / hr = > 36,000 m / hr in one minute = > 36000 / 60 = 600 meters in one sec = > 600 / 60 = 10 meters time = total distance need to be covered / avg . speed = > 600 / 10 = 60 and hence the answer : c" | physics |
math_qa__VEKRHWNELCgcMTWS | Solve This
6 + 7 = 12
8 + 9 = 16
5 + 6 = 10
7 + 8 = 14
Then, 3 + 3 = ??
Choose the correct choice from the following answers
A) 11 B) 12 C) 5 D) 14 E) 18 | <gadget id="calculator">12 - 6</gadget>
<output>6</output>
<gadget id="calculator">7 - 6</gadget>
<output>1</output>
<gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<result>C</result> | C | 5 | Solve This
6 + 7 = 12
8 + 9 = 16
5 + 6 = 10
7 + 8 = 14
Then, 3 + 3 = ?? | {
"A": "11",
"B": "12",
"C": "5",
"D": "14",
"E": "18"
} | add(3, subtract(3, subtract(7, subtract(12, 6)))) | subtract(n2,n0)|subtract(n1,#0)|subtract(n12,#1)|add(n12,#2) | 5 answer : c | general |
math_qa__CLYOF3LCFjitIeKm | John and Jane went out for a dinner and they ordered the same dish. Both used a 10% discount coupon. John paid a 15% tip over the original price of the dish, while Jane paid the tip over the discounted price for the coupon. If John paid $1.26 more than Jane, what was the original price of the dish? Pick:
A) 24 B) 34.8 C) 37.8 D) 42 E) 84 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * (3/20)</gadget>
<output>27/200 = around 0.135</output>
<gadget id="calculator">(3/20) - (27/200)</gadget>
<output>3/200 = around 0.015</output>
<gadget id="calculator">1.26 / (3/200)</gadget>
<output>84</output>
<result>E</result> | E | 84 | John and Jane went out for a dinner and they ordered the same dish. Both used a 10% discount coupon. John paid a 15% tip over the original price of the dish, while Jane paid the tip over the discounted price for the coupon. If John paid $1.26 more than Jane, what was the original price of the dish? | {
"A": "24",
"B": "34.8",
"C": "37.8",
"D": "42",
"E": "84"
} | divide(1.26, subtract(divide(15, const_100), multiply(subtract(const_1, divide(10, const_100)), divide(15, const_100)))) | divide(n1,const_100)|divide(n0,const_100)|subtract(const_1,#1)|multiply(#0,#2)|subtract(#0,#3)|divide(n2,#4) | the difference between the amounts john paid and jane paid is the deference between 15 % of p and 15 % of 0.9 p : 0.15 p - 0.15 * 0.9 p = 1.26 - - > 15 p - 13.5 p = 126 - - > p = 84 . answer : e . | gain |
math_qa__97sfzQtynuaF3qzX | If 3/p=8 & 3/q=18 then p-q=? Choose the correct choice from the following options
A) 5 / 24 B) 6 / 24 C) 7 / 24 D) 8 / 24 E) 9 / 24 | <gadget id="calculator">3 / 8</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">3 / 18</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(3/8) - (1/6)</gadget>
<output>5/24 = around 0.208333</output>
<result>A</result> | A | 0.208333 | If 3/p=8 & 3/q=18 then p-q=? | {
"A": "5 / 24",
"B": "6 / 24",
"C": "7 / 24",
"D": "8 / 24",
"E": "9 / 24"
} | subtract(divide(3, 8), divide(3, 18)) | divide(n0,n1)|divide(n0,n3)|subtract(#0,#1)| | "p = 3 / 8 , q = 3 / 18 = > q = 1 / 6 therefore p - q = ( 3 / 8 ) - ( 1 / 6 ) = 5 / 24 answer : a" | general |
math_qa__Wo5mv30B3SLyL0fK | A certain university will select 1 of 7 candidates eligible to fill a position in the mathematics department and 2 of 7 candidates eligible to fill 2 identical positions in the computer science department. If none of the candidates is eligible for a position in both departments, how many different sets of 3 candidates are there to fill the 3 positions? Select the correct option
A) 42 B) 70 C) 147 D) 165 E) 315 | <gadget id="calculator">7 * 3</gadget>
<output>21</output>
<gadget id="calculator">21 * 7</gadget>
<output>147</output>
<result>C</result> | C | 147 | A certain university will select 1 of 7 candidates eligible to fill a position in the mathematics department and 2 of 7 candidates eligible to fill 2 identical positions in the computer science department. If none of the candidates is eligible for a position in both departments, how many different sets of 3 candidates are there to fill the 3 positions? | {
"A": "42",
"B": "70",
"C": "147",
"D": "165",
"E": "315"
} | multiply(multiply(7, 3), 7) | multiply(n3,n5)|multiply(n1,#0)| | "ans : 147 7 c 1 * 7 c 2 answer c )" | other |
math_qa__Xji3ZP8lejU9Y83C | Mohit sold an article for $18000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article? Choices:
A) 16000 B) 25000 C) 15000 D) 18000 E) 17000 | <gadget id="calculator">18_000 * 10</gadget>
<output>180_000</output>
<gadget id="calculator">180_000 / 100</gadget>
<output>1_800</output>
<gadget id="calculator">18_000 - 1_800</gadget>
<output>16_200</output>
<gadget id="calculator">100 + 8</gadget>
<output>108</output>
<gadget id="calculator">16_200 / 108</gadget>
<output>150</output>
<gadget id="calculator">150 * 100</gadget>
<output>15_000</output>
<result>C</result> | C | 15,000 | Mohit sold an article for $18000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article? | {
"A": "16000",
"B": "25000",
"C": "15000",
"D": "18000",
"E": "17000"
} | multiply(divide(subtract(18000, divide(multiply(18000, 10), const_100)), add(const_100, 8)), const_100) | add(n2,const_100)|multiply(n0,n1)|divide(#1,const_100)|subtract(n0,#2)|divide(#3,#0)|multiply(#4,const_100)| | "c 15000 let the cp be $ x . had he offered 10 % discount , profit = 8 % profit = 8 / 100 x and hence his sp = x + 8 / 100 x = $ 1.08 x = 18000 - 10 / 100 ( 18000 ) = 18000 - 1800 = $ 16200 = > 1.08 x = 16200 = > x = 15000" | gain |
math_qa__09DgSEJMlTFYp7Vh | A is twice as fast as B. If B alone can do a piece of work in 30 days, in what time can A and B together complete the work? Choose the most appropriate option:
A) 13 B) 10 C) 16 D) 50 E) 23 | <gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/30) * 2</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/30) + (1/15)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / (1/10)</gadget>
<output>10</output>
<result>B</result> | B | 10 | A is twice as fast as B. If B alone can do a piece of work in 30 days, in what time can A and B together complete the work? | {
"A": "13",
"B": "10",
"C": "16",
"D": "50",
"E": "23"
} | inverse(add(divide(const_1, 30), multiply(divide(const_1, 30), const_2))) | divide(const_1,n0)|multiply(#0,const_2)|add(#0,#1)|inverse(#2)| | "option b explanation : a can do the work in 30 / 2 i . e . , 15 days . a and b ' s one day ' s work = 1 / 15 + 1 / 30 = ( 2 + 1 ) / 30 = 1 / 10 so a and b together can do the work in 10 days ." | physics |
math_qa__tJsgsRdhpfCqlsnK | A bag contains 3 blue and 5 white marbles. One by one, marbles are drawn out randomly until only two are left in the bag. What is the probability C that out of the two, one is white and one is blue? Choices:
A) 15 / 56 B) 41 / 56 C) 13 / 28 D) 15 / 28 E) 5 / 14 | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">3 + 5</gadget>
<output>8</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">8 * 7</gadget>
<output>56</output>
<gadget id="calculator">56 / 2</gadget>
<output>28</output>
<gadget id="calculator">15 / 28</gadget>
<output>15/28 = around 0.535714</output>
<result>D</result> | D | 0.535714 | A bag contains 3 blue and 5 white marbles. One by one, marbles are drawn out randomly until only two are left in the bag. What is the probability C that out of the two, one is white and one is blue? | {
"A": "15 / 56",
"B": "41 / 56",
"C": "13 / 28",
"D": "15 / 28",
"E": "5 / 14"
} | divide(multiply(3, 5), divide(multiply(add(3, 5), add(5, const_2)), const_2)) | add(n0,n1)|add(n1,const_2)|multiply(n0,n1)|multiply(#0,#1)|divide(#3,const_2)|divide(#2,#4)| | "the required probability c = probability of choosing 6 balls out of the total 8 in such a way that we remove 4 out of 5 white and 2 out of 3 blue balls . ways to select 6 out of total 8 = 8 c 6 ways to select 4 out of 5 white balls = 5 c 4 ways to select 2 out of 3 blue balls = 3 c 2 thus the required probability = ( 5 c 4 * 3 c 2 ) / 8 c 6 = 15 / 28 . d is thus the correct answer ." | probability |
math_qa__sfZ9kpcFxO5N3za1 | The total cost of a vacation was divided among 4 people. If the total cost of the vacation had been divided equally among 5 people, the cost per person would have been $50 less. What was the total cost cost of the vacation? Choose the most appropriate option
A) $ 200
B) $ 300
C) $ 400
D) $ 500
E) $ 1000 | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">5 - 4</gadget>
<output>1</output>
<gadget id="calculator">50 / 1</gadget>
<output>50</output>
<gadget id="calculator">20 * 50</gadget>
<output>1_000</output>
<result>E</result> | E | 1,000 | The total cost of a vacation was divided among 4 people. If the total cost of the vacation had been divided equally among 5 people, the cost per person would have been $50 less. What was the total cost cost of the vacation? | {
"A": "$ 200",
"B": "$ 300",
"C": "$ 400",
"D": "$ 500",
"E": "$ 1000"
} | multiply(multiply(5, 4), divide(50, subtract(5, 4))) | multiply(n0,n1)|subtract(n1,n0)|divide(n2,#1)|multiply(#2,#0)| | "c for cost . p price per person . c = 4 * p c = 5 * p - 250 substituting the value of p from the first equation onto the second we get p = 250 . plugging in the value of p in the first equation , we get c = 1000 . which leads us to answer choice e" | general |
math_qa__VehsgfxbnIHBDGQ3 | By mixing two brands of coffee and selling the mixture at the rate of $177 per kg. a shopkeeper makes a profit of 18%. If to every 2 kg of one brand costing $200 per kg, 3 kg of the other brand is added, then how much per kg does the other brand cost? Choose the correct answer.
A) $ 110.66 B) $ 132.66 C) $ 116.66 D) $ 126.66 E) $ 118.66 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 177</gadget>
<output>885</output>
<gadget id="calculator">2 * 200</gadget>
<output>400</output>
<gadget id="calculator">18 / 100</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">1 + (9/50)</gadget>
<output>59/50 = around 1.18</output>
<gadget id="calculator">400 * (59/50)</gadget>
<output>472</output>
<gadget id="calculator">885 - 472</gadget>
<output>413</output>
<gadget id="calculator">3 * (59/50)</gadget>
<output>177/50 = around 3.54</output>
<gadget id="calculator">413 / (177/50)</gadget>
<output>350/3 = around 116.666667</output>
<result>C</result> | C | 116.66 | By mixing two brands of coffee and selling the mixture at the rate of $177 per kg. a shopkeeper makes a profit of 18%. If to every 2 kg of one brand costing $200 per kg, 3 kg of the other brand is added, then how much per kg does the other brand cost? | {
"A": "$ 110.66",
"B": "$ 132.66",
"C": "$ 116.66",
"D": "$ 126.66",
"E": "$ 118.66"
} | divide(subtract(multiply(add(2, 3), 177), multiply(multiply(2, 200), add(const_1, divide(18, const_100)))), multiply(3, add(const_1, divide(18, const_100)))) | add(n2,n4)|divide(n1,const_100)|multiply(n2,n3)|add(#1,const_1)|multiply(n0,#0)|multiply(#3,#2)|multiply(n4,#3)|subtract(#4,#5)|divide(#7,#6) | c $ 116.66 let the cost of the brand be $ x per kg . c . p . of 5 kg = ( 2 * 200 + 3 * x ) = $ ( 400 + 3 x ) s . p of 5 kg = $ ( 5 * 177 ) = $ 885 [ 885 - ( 400 + 3 x ) ] / ( 400 + 3 x ) * 100 = 18 24250 - 150 x = 3600 + 27 x 177 x = 20650 = > x = 116 2 / 3 so , cost of the other brand = $ 116.66 . | gain |
math_qa__jxMMTWn340UrxX4q | Johnny makes $6.75 per hour at his work. If he works 10 hours, how much money will he earn?
Choose the correct answer: A) $ 67.50 B) $ 54 C) $ 28.50 D) $ 12.50 E) $ 9.60 | <gadget id="calculator">6.75 * 10</gadget>
<output>67.5</output>
<result>A</result> | A | 67.5 | Johnny makes $6.75 per hour at his work. If he works 10 hours, how much money will he earn? | {
"A": "$ 67.50",
"B": "$ 54",
"C": "$ 28.50",
"D": "$ 12.50",
"E": "$ 9.60"
} | multiply(6.75, 10) | multiply(n0,n1)| | 6.75 * 10 = 67.50 . answer is a . | physics |
math_qa__qqzYuRnhPDC87Kf3 | A take twice as much time as B or thrice as much time to finish a piece of work. Working together, they can finish the work in 4 days. B can do the work alone in? Choose the correct choice.
A) 19 B) 12 C) 11 D) 24 E) 114 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 4</gadget>
<output>24</output>
<result>D</result> | D | 24 | A take twice as much time as B or thrice as much time to finish a piece of work. Working together, they can finish the work in 4 days. B can do the work alone in? | {
"A": "19",
"B": "12",
"C": "11",
"D": "24",
"E": "114"
} | multiply(add(add(const_1, const_2), const_3), 4) | add(const_1,const_2)|add(#0,const_3)|multiply(n0,#1)| | "suppose a , b and c take x , x / 2 and x / 3 respectively to finish the work . then , ( 1 / x + 2 / x + 3 / x ) = 1 / 4 6 / x = 1 / 4 = > x = 24 so , b takes 12 hours to finish the work . answer : d" | physics |
math_qa__KN6H9VzjQvDl0y5G | A man purchased 3 blankets @ Rs.100 each, 3 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets? Choose the correct answer
A) 750
B) 277
C) 878
D) 450
E) 272 | <gadget id="calculator">10 * 150</gadget>
<output>1_500</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">3 * 150</gadget>
<output>450</output>
<gadget id="calculator">300 + 450</gadget>
<output>750</output>
<gadget id="calculator">1_500 - 750</gadget>
<output>750</output>
<result>A</result> | A | 750 | A man purchased 3 blankets @ Rs.100 each, 3 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets? | {
"A": "750",
"B": "277",
"C": "878",
"D": "450",
"E": "272"
} | subtract(multiply(const_10, 150), add(multiply(3, 100), multiply(3, 150))) | multiply(n3,const_10)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|subtract(#0,#3)| | "10 * 150 = 1500 3 * 100 + 3 * 150 = 750 1500 – 750 = 750 answer : a" | general |
math_qa__6TCO45QZXgltAwX7 | An amount at compound interest sums to Rs.17640/- in 2 years and to Rs.18522/- in 3 years at the same rate of interest. Find the rate percentage? Choose the most appropriate option:
A) 5 %
B) 6 %
C) 7 %
D) 8 %
E) 9 % | <gadget id="calculator">18_522 - 17_640</gadget>
<output>882</output>
<gadget id="calculator">882 / 17_640</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 100</gadget>
<output>5</output>
<result>A</result> | A | 5 | An amount at compound interest sums to Rs.17640/- in 2 years and to Rs.18522/- in 3 years at the same rate of interest. Find the rate percentage? | {
"A": "5 %",
"B": "6 %",
"C": "7 %",
"D": "8 %",
"E": "9 %"
} | multiply(divide(subtract(18522, 17640), 17640), const_100) | subtract(n2,n0)|divide(#0,n0)|multiply(#1,const_100)| | "the difference of two successive amounts must be the simple interest in 1 year on the lower amount of money . s . i = 18522 / - - 17640 / - = rs . 882 / - rate of interest = ( 882 / 17640 ) × ( 100 / 1 ) = > 8820 / 1764 = 5 % principal = amount / ( 1 + r / 100 ) n = 17640 / ( 1 + 5 / 100 ) 2 = 17640 / ( 21 / 20 × 21 / 20 ) = 17640 / ( 1.05 × 1.05 ) = 17640 / 1.1025 = 16000 thus the principal is rs . 16000 / - and the rate of interest is 5 % a" | general |
math_qa__S4tKVIL4fpQP8mHy | Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 49 hours respectively. The ratio of their speeds is? Choose the most appropriate option
A) 4 : 7 B) 7 : 3 C) 4 : 9 D) 4 : 4 E) 4 : 2 | <gadget id="calculator">49 ** (1/2)</gadget>
<output>7</output>
<gadget id="calculator">9 ** (1/2)</gadget>
<output>3</output>
<gadget id="calculator">7 / 3</gadget>
<output>7/3 = around 2.333333</output>
<result>B</result> | B | 2.333333 | Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 49 hours respectively. The ratio of their speeds is? | {
"A": "4 : 7",
"B": "7 : 3",
"C": "4 : 9",
"D": "4 : 4",
"E": "4 : 2"
} | divide(sqrt(49), sqrt(9)) | sqrt(n1)|sqrt(n0)|divide(#0,#1)| | "let us name the trains a and b . then , ( a ' s speed ) : ( b ' s speed ) = â ˆ š b : â ˆ š a = â ˆ š 49 : â ˆ š 9 = 7 : 3 . answer : b" | physics |
math_qa__JOC2vmTtvPEUuezi | At what price must an article costing Rs.47.50 be marked in order that after deducting 10% from the list price. It may be sold at a profit of 25% on the cost price? Select.
A) 65.9 B) 62.3 C) 62.7 D) 62.2 E) 62.9 | <gadget id="calculator">47.5 * 25</gadget>
<output>1_187.5</output>
<gadget id="calculator">1_187.5 / 100</gadget>
<output>11.875</output>
<gadget id="calculator">47.5 + 11.875</gadget>
<output>59.375</output>
<gadget id="calculator">59.375 * 100</gadget>
<output>5_937.5</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">5_937.5 / 90</gadget>
<output>65.972222</output>
<result>A</result> | A | 65.9 | At what price must an article costing Rs.47.50 be marked in order that after deducting 10% from the list price. It may be sold at a profit of 25% on the cost price? | {
"A": "65.9",
"B": "62.3",
"C": "62.7",
"D": "62.2",
"E": "62.9"
} | divide(multiply(add(47.50, divide(multiply(47.50, 25), const_100)), const_100), subtract(const_100, 10)) | multiply(n0,n2)|subtract(const_100,n1)|divide(#0,const_100)|add(n0,#2)|multiply(#3,const_100)|divide(#4,#1)| | "cp = 47.50 sp = 47.50 * ( 125 / 100 ) = 59.375 mp * ( 90 / 100 ) = 59.375 mp = 65.9 answer : a" | gain |
math_qa__o3iPt4O3Cpz7j74O | Two vessels having volumes in the ratio 3:5 are filled with water and milk solutions. The ratio of milk and water in the two vessels are 1:2 and 6:4 respectively. If the contents of both the vessel are empties into a larger vessel, find the ratio of milk and water in the larger vessel.
Choose the most appropriate option:
A) 1 : 1 B) 2 : 1 C) 3 : 1 D) 5 : 1 E) 6 : 1 | <gadget id="calculator">1 ** 3</gadget>
<output>1</output>
<result>A</result> | A | 1 | Two vessels having volumes in the ratio 3:5 are filled with water and milk solutions. The ratio of milk and water in the two vessels are 1:2 and 6:4 respectively. If the contents of both the vessel are empties into a larger vessel, find the ratio of milk and water in the larger vessel. | {
"A": "1 : 1",
"B": "2 : 1",
"C": "3 : 1",
"D": "5 : 1",
"E": "6 : 1"
} | power(1, 3) | power(n2,n0)| | "vessel a = 300 gallons - - > milk = 100 , water = 200 ; vessel b = 500 gallons - - > milk = 300 , water = 200 ; vessel a + b = 800 gallons - - > milk = 400 , water 400 the ratio = 400 / 400 - - > 1 : 1 answer : a" | other |
math_qa__rX3iA0Ah03hLtDXa | The price of a jacket is reduced by 10%. During a special sale the price of the jacket is reduced another 30%. By approximately what percent must the price of the jacket now be increased in order to restore it to its original amount?
Choices.
A) 32.5 B) 58.7 C) 48 D) 65 E) 67.5 | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">90 * (3/10)</gadget>
<output>27</output>
<gadget id="calculator">90 - 27</gadget>
<output>63</output>
<gadget id="calculator">100 - 63</gadget>
<output>37</output>
<gadget id="calculator">37 / 63</gadget>
<output>37/63 = around 0.587302</output>
<gadget id="calculator">100 * (37/63)</gadget>
<output>3_700/63 = around 58.730159</output>
<result>B</result> | B | 58.7 | The price of a jacket is reduced by 10%. During a special sale the price of the jacket is reduced another 30%. By approximately what percent must the price of the jacket now be increased in order to restore it to its original amount? | {
"A": "32.5",
"B": "58.7",
"C": "48",
"D": "65",
"E": "67.5"
} | multiply(const_100, divide(subtract(const_100, subtract(subtract(const_100, 10), multiply(subtract(const_100, 10), divide(30, const_100)))), subtract(subtract(const_100, 10), multiply(subtract(const_100, 10), divide(30, const_100))))) | divide(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|subtract(#1,#2)|subtract(const_100,#3)|divide(#4,#3)|multiply(#5,const_100)| | "1 ) let the price of jacket initially be $ 100 . 2 ) then it is decreased by 10 % , therefore bringing down the price to $ 90 . 3 ) again it is further discounted by 30 % , therefore bringing down the price to $ 63 . 4 ) now 67.5 has to be added byx % in order to equal the original price . 63 + ( x % ) 63 = 100 . solving this eq for x , we get x = 58.7 ans is b" | gain |
math_qa__vKKfyvxuQj9HMZxY | The ratio between the sale price and the cost price of an article is 7:5. What is the ratio between the profit and the cost price of that article? Choose the correct answer.
A) 2 : 8
B) 2 : 1
C) 2 : 2
D) 2 : 4
E) 2 : 5 | <gadget id="calculator">7 - 5</gadget>
<output>2</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<result>E</result> | E | 0.4 | The ratio between the sale price and the cost price of an article is 7:5. What is the ratio between the profit and the cost price of that article? | {
"A": "2 : 8",
"B": "2 : 1",
"C": "2 : 2",
"D": "2 : 4",
"E": "2 : 5"
} | divide(subtract(7, 5), 5) | subtract(n0,n1)|divide(#0,n1)| | "explanation : let c . p . = rs . 5 x and s . p . = rs . 7 x . then , gain = rs . 2 x required ratio = 2 x : 5 x = 2 : 5 answer : e" | other |
math_qa__AS5RVpeknLEZEzYq | Two trains 110 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is? Choose the correct choice from the following answers.
A) 10.9 B) 10.7 C) 10.3 D) 10.8 E) 9.72 | <gadget id="calculator">110 + 160</gadget>
<output>270</output>
<gadget id="calculator">60 + 40</gadget>
<output>100</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">100 * (5/18)</gadget>
<output>250/9 = around 27.777778</output>
<gadget id="calculator">270 / (250/9)</gadget>
<output>243/25 = around 9.72</output>
<result>E</result> | E | 9.72 | Two trains 110 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is? | {
"A": "10.9",
"B": "10.7",
"C": "10.3",
"D": "10.8",
"E": "9.72"
} | divide(add(110, 160), multiply(add(60, 40), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = 60 + 40 = 100 km / hr . = 100 * 5 / 18 = 250 / 9 m / sec . distance covered in crossing each other = 110 + 160 = 270 m . required time = 270 * 9 / 250 = 243 / 25 = 9.72 sec . ' answer : e" | physics |
math_qa__fSJVNrVl9DaCnYoG | thomas ' s age and matt ' s age are in the ratio 3 : 5 . two years ago the ratio of their ages was 5 : 9 . find the ratio of their ages 4 years hence ? Choose the correct choice from the following answers.
A) 1 : 2
B) 2 : 3
C) 3 : 4
D) 4 : 5
E) 5 : 6 | <gadget id="calculator">5 + 3</gadget>
<output>8</output>
<gadget id="calculator">8 * 5</gadget>
<output>40</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<gadget id="calculator">20 * 3</gadget>
<output>60</output>
<gadget id="calculator">60 / 5</gadget>
<output>12</output>
<gadget id="calculator">12 + 4</gadget>
<output>16</output>
<gadget id="calculator">20 + 4</gadget>
<output>24</output>
<gadget id="calculator">16 / 24</gadget>
<output>2/3 = around 0.666667</output>
<result>B</result> | B | 0.666667 | thomas ' s age and matt ' s age are in the ratio 3 : 5 . two years ago the ratio of their ages was 5 : 9 . find the ratio of their ages 4 years hence ? | {
"A": "1 : 2",
"B": "2 : 3",
"C": "3 : 4",
"D": "4 : 5",
"E": "5 : 6"
} | divide(add(divide(multiply(divide(multiply(add(5, 3), 5), const_2), 3), 5), 4), add(divide(multiply(add(5, 3), 5), const_2), 4)) | add(n0,n1)|multiply(n1,#0)|divide(#1,const_2)|add(n4,#2)|multiply(n0,#2)|divide(#4,n1)|add(n4,#5)|divide(#6,#3) | let ages of thomas and matt be x and y respectively . x / y = 3 / 5 = > x = 3 / 5 y ( x - 2 ) / ( y - 2 ) = 5 / 9 = > 9 x - 18 = 5 y - 10 = > 9 x = 5 y + 8 but x = 3 / 5 y 9 * 3 / 5 y = 5 y + 8 27 y = 25 y + 40 = > y = 20 years = > x = 3 * 20 / 5 = > 12 years ratio of their ages four years hence , ( 12 + 4 ) / ( 20 + 4 ) = 16 / 24 . = > 2 : 3 answer : b | other |
math_qa__4iTZxkaZe9DwXpxX | Dan's age after 16 years will be 4 times his age 8 years ago. What is the present age of Dan? Choose the correct choice from the following
A) 12 B) 16 C) 20 D) 24 E) 28 | <gadget id="calculator">8 * 4</gadget>
<output>32</output>
<gadget id="calculator">16 + 32</gadget>
<output>48</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">48 / 3</gadget>
<output>16</output>
<result>B</result> | B | 16 | Dan's age after 16 years will be 4 times his age 8 years ago. What is the present age of Dan? | {
"A": "12",
"B": "16",
"C": "20",
"D": "24",
"E": "28"
} | divide(add(16, multiply(8, 4)), subtract(4, const_1)) | multiply(n1,n2)|subtract(n1,const_1)|add(n0,#0)|divide(#2,#1) | let dan ' s present age be x . x + 16 = 4 ( x - 8 ) 3 x = 48 x = 16 the answer is b . | general |
math_qa__j4bdyUvCGTn5RiEo | A certain cube floating in a bucket of water has between 75 and 85 percent of its volume below the surface of the water. If between 9 and 16 cubic centimeters of the cube's volume is above the surface of the water, then the length of a side of the cube is approximately Answers:
A) 4 B) 5 C) 7 D) 8 E) 9 | <gadget id="calculator">16 * 100</gadget>
<output>1_600</output>
<gadget id="calculator">100 - 75</gadget>
<output>25</output>
<gadget id="calculator">1_600 / 25</gadget>
<output>64</output>
<gadget id="calculator">64 ** (1/3)</gadget>
<output>4</output>
<result>A</result> | A | 4 | A certain cube floating in a bucket of water has between 75 and 85 percent of its volume below the surface of the water. If between 9 and 16 cubic centimeters of the cube's volume is above the surface of the water, then the length of a side of the cube is approximately | {
"A": "4",
"B": "5",
"C": "7",
"D": "8",
"E": "9"
} | cube_edge_by_volume(divide(multiply(16, const_100), subtract(const_100, 75))) | multiply(n3,const_100)|subtract(const_100,n0)|divide(#0,#1)|cube_edge_by_volume(#2) | if sides are 7 , vol = 7 ^ 3 = 343 75 % = 257.25 , 85 % = 291.55 so vol above water , between 85.75 and 51.45 - - > too big if side are 4 , vol = 64 75 % = 48 , 85 % = 54.4 vol above water between 16 and 9.6 so 4 should be the answer . check option c , if sides are 5 , vol = 125 75 % = 93.75 , . 85 % = 106.25 vol above water between 18.75 - 31.25 ( sides are 4 cubic centimeters ) a | geometry |
math_qa__AqpSX0krDUJZ0gem | 5020−(1004÷20.08)=? Choose the correct choice:
A) 4520
B) 4350
C) 4210
D) 4100
E) 4970 | <gadget id="calculator">1_004 / 20.08</gadget>
<output>50</output>
<gadget id="calculator">5_020 - 50</gadget>
<output>4_970</output>
<result>E</result> | E | 4,970 | 5020−(1004÷20.08)=? | {
"A": "4520",
"B": "4350",
"C": "4210",
"D": "4100",
"E": "4970"
} | subtract(5020, divide(1004, 20.08)) | divide(n1,n2)|subtract(n0,#0)| | "explanation : = 5020 − ( 1004 / 2008 × 100 ) = 5020 − 50 = 4970 option e" | general |
math_qa__4AP4irn3mnFwdq0u | It takes 60 identical printing machines 2 hours to print 300 cards. How much more time would it take 50 of these machines to print the same total? Choices
A) 20 min
B) 25 min
C) 26 min
D) 36 min
E) 30 min | <gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">300 / 50</gadget>
<output>6</output>
<gadget id="calculator">30 + 6</gadget>
<output>36</output>
<result>D</result> | D | 36 | It takes 60 identical printing machines 2 hours to print 300 cards. How much more time would it take 50 of these machines to print the same total? | {
"A": "20 min",
"B": "25 min",
"C": "26 min",
"D": "36 min",
"E": "30 min"
} | add(divide(60, 2), divide(300, 50)) | divide(n0,n1)|divide(n2,n3)|add(#0,#1) | 50 % of 60 = 30 % or 0.30 2 hr x 60 min = 120 min 120 min x 0.30 = 36 min it will take 36 min longer to print them with only 50 printers . answer is d | general |
math_qa__x3smylF8ng9MyGub | A 18% stock yielding 12% is quoted at: Choose the correct choice from the following answers: A) s . 83.33 B) s . 110 C) s . 112 D) s . 120 E) s . 150 | <gadget id="calculator">100 / 12</gadget>
<output>25/3 = around 8.333333</output>
<gadget id="calculator">(25/3) * 18</gadget>
<output>150</output>
<result>E</result> | E | 150 | A 18% stock yielding 12% is quoted at: | {
"A": "s . 83.33",
"B": "s . 110",
"C": "s . 112",
"D": "s . 120",
"E": "s . 150"
} | multiply(divide(const_100, 12), 18) | divide(const_100,n1)|multiply(n0,#0)| | "income of rs 12 on investment of rs 100 income of rs 18 on investment of ? = ( 18 * 100 ) / 12 = 150 answer : e" | gain |
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