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a lady builds 12 cm length , 16 cm width , and 6 cm height box using 3 cubic cm cubes . what is the minimum number of cubes required to build the box ? | n0 = 12.0
n1 = 16.0
n2 = 6.0
n3 = 3.0
t0 = n0 * n1
t1 = n2 * t0
answer = t1 / n3
print(answer) | 384 | train | mathqa_geometry.json |
the area of a parallelogram is 162 sq m and its altitude is twice the corresponding base . then the length of the base is ? | import math
n0 = 162.0
t0 = n0 / 2.0
answer = math.sqrt(max(0, t0))
print(answer) | 9 | train | mathqa_geometry.json |
if n is the smallest integer such that 432 times n is the square of an integer , what is the value of n ? | n0 = 432.0
t0 = n0 / 2.0
t1 = t0 / 2.0
t2 = t1 / 2.0
t3 = t2 / 2.0
t4 = t3 / 3.0
answer = t4 / 3.0
print(answer) | 3 | train | mathqa_geometry.json |
the cube root of what integer power of 2 is closest to 50 ? | n0 = 2.0
n1 = 50.0
t0 = 4.0 + 4.0
t1 = n1 / n0
answer = t1 - t0
print(answer) | 17 | train | mathqa_geometry.json |
in triangle pqr , the angle q = 90 degree , pq = 2 cm , qr = 8 cm . x is a variable point on pq . the line through x parallel to qr , intersects pr at y and the line through y , parallel to pq , intersects qr at z . find the least possible length of xz | n0 = 90.0
n1 = 2.0
n2 = 8.0
t0 = n1 * n2
answer = t0 / 10.0
print(answer) | 1.6 | train | mathqa_geometry.json |
if the sides of a triangle are 28 cm , 24 cm and 15 cm , what is its area ? | n0 = 28.0
n1 = 24.0
n2 = 15.0
t0 = n1 * n2
answer = t0 / 2.0
print(answer) | 180 | train | mathqa_geometry.json |
carol and jordan draw rectangles of equal area . if carol ' s rectangle measures 8 inches by 15 inches and jordan ' s rectangle is 4 inches long , how wide is jordan ' s rectangle , in inches ? | n0 = 8.0
n1 = 15.0
n2 = 4.0
t0 = n0 * n1 # area of rectangle
answer = t0 / n2
print(answer) | 30 | train | mathqa_geometry.json |
the perimeter of a triangle is 32 cm and the inradius of the triangle is 2.5 cm . what is the area of the triangle ? | n0 = 32.0
n1 = 2.5
answer = n0 * n1 / 2
print(answer) | 40 | train | mathqa_geometry.json |
the perimeter of a triangle is 35 cm and the inradius of the triangle is 4.5 cm . what is the area of the triangle ? | n0 = 35.0
n1 = 4.5
answer = n0 * n1 / 2
print(answer) | 78.75 | train | mathqa_geometry.json |
a larger cube has 216 cubic inch as a volume and in the cube there are 216 smaller cubes such that their volume is 1 cubic inch . what is the difference between the surface areas ’ sum of the 216 smaller cubes and the surface area of the larger cube , in square inch ? | n0 = 216.0
n1 = 216.0
n2 = 1.0
n3 = 216.0
t0 = n2**(1 / 3)
t1 = n0**(1 / 3)
t2 = 6 * t0**2 # surface of a cube
t3 = 6 * t1**2 # surface of a cube
t4 = n0 * t2
answer = t4 - t3
print(answer) | 1080 | train | mathqa_geometry.json |
approximately how many cubic feet of water are needed to fill a circular swimming pool that is 80 feet across and 10 feet deep ? | import math
n0 = 80.0
n1 = 10.0
t0 = n0 / 2.0
answer = math.pi * t0**2 * n1
print(answer) | 50265.482457436694 | train | mathqa_geometry.json |
if the area of a circle decreases by 36 % , then the radius of a circle decreases by | import math
n0 = 36.0
t0 = 100.0 - n0
t1 = t0 / 100.0
t2 = math.sqrt(max(0, t1))
t3 = 1.0 - t2
answer = t3 * 100.0
print(answer) | 19.999999999999996 | train | mathqa_geometry.json |
find the area of a triangle whose sides are 41 cm , 28 cm , 15 cm . also , find the length of the altitude corresponding to the largest side of the triangle . | import math
n0 = 41.0
n1 = 28.0
n2 = 15.0
t0 = (lambda s, a, b, c: math.sqrt(max(0, s * (s - a) * (s - b) * (s - c))))((n0 + n1 + n2) / 2, n0, n1, n2) # Heron's formula
t1 = t0 * 2.0
answer = t1 / n0
print(answer) | 6.146341463414634 | train | mathqa_geometry.json |
36 people { a 1 , a 2 … a 36 } meet and shake hands in a circular fashion . in other words , there are totally 36 handshakes involving the pairs , { a 1 , a 2 } , { a 2 , a 3 } , … , { a 35 , a 36 } , { a 36 , a 1 } . then size of the smallest set of people such that the rest have shaken hands with at least one person in the set is | n0 = 36.0
n1 = 1.0
n2 = 2.0
n3 = 36.0
n4 = 36.0
n5 = 1.0
n6 = 2.0
n7 = 2.0
n8 = 3.0
n9 = 35.0
n10 = 36.0
n11 = 36.0
n12 = 1.0
answer = n0 / 3.0
print(answer) | 12 | train | mathqa_geometry.json |
the diagonals of a rhombus are 25 cm and 30 cm . find its area ? | n0 = 25.0
n1 = 30.0
answer = n0 * n1 / 2
print(answer) | 375 | train | mathqa_geometry.json |
how many internal diagonals does a hexagon ( 6 sided polygon ) have ? | n0 = 6.0
t0 = n0 - 3.0
t1 = n0 * t0
answer = t1 / 2.0
print(answer) | 9 | train | mathqa_geometry.json |
the length of a rectangular landscape is 4 times its breadth . there is a playground in it whose area is 1200 square mtr & which is 1 / 3 rd of the total landscape . what is the length of the landscape ? | n0 = 4.0
n1 = 1200.0
n2 = 1.0
n3 = 3.0
t0 = n0 * n3
answer = t0 * 10.0
print(answer) | 120 | train | mathqa_geometry.json |
two isosceles triangles have equal vertical angles and their areas are in the ratio 16 : 36 . find the ratio of their corresponding heights . | import math
n0 = 16.0
n1 = 36.0
t0 = math.sqrt(max(0, n0))
t1 = math.sqrt(max(0, n1))
answer = t0 / t1
print(answer) | 0.6666666666666666 | train | mathqa_geometry.json |
the size of a television screen is given as the length of the screen ' s diagonal . if the screens were flat , then the area of a square 18 - inch screen would be how many square inches greater than the area of a square 16 - inch screen ? | n0 = 18.0
n1 = 16.0
t0 = n0**min(2.0, 5)
t1 = n1**min(2.0, 5)
t2 = t0 - t1
answer = t2 / 2.0
print(answer) | 34 | train | mathqa_geometry.json |
when magnified 1000 times by an electron microscope , the image of a certain circular piece of tissue has a diameter of 0.3 centimeter . the actual diameter of the tissue , in centimeters , is | n0 = 1000.0
n1 = 0.3
answer = n1 / n0
print(answer) | 0.0003 | train | mathqa_geometry.json |
a circular garden is surrounded by a fence of negligible width along the boundary . if the length of the fence is 1 / 5 of th area of the garden . what is the radius of the circular garden ? | import math
n0 = 1.0
n1 = 5.0
t0 = n1**min(2.0, 5)
t1 = math.sqrt(max(0, t0))
answer = t1 * 2.0
print(answer) | 10 | train | mathqa_geometry.json |
if the length of the longest chord of a certain circle is 22 , what is the radius of that certain circle ? | n0 = 22.0
answer = n0 / 2.0
print(answer) | 11 | train | mathqa_geometry.json |
an isosceles triangle those sides are 13 cm , 13 cm , 10 cm long inscribed in a circle . find the radius of the circle | import math
n0 = 13.0
n1 = 13.0
n2 = 10.0
t0 = n2 / 2.0
t1 = n0**min(2.0, 5)
t2 = t0**min(2.0, 5)
t3 = t1 - t2
t4 = t2 + t3
t5 = math.sqrt(max(0, t3))
t6 = t5 * 2.0
t7 = t4 / t6
answer = t7 + 1.0
print(answer) | 8.041666666666668 | train | mathqa_geometry.json |
a horse is tethered to one corner of a rectangular grassy field 45 m by 25 m with a rope 22 m long . over how much area of the field can it graze ? | n0 = 45.0
n1 = 25.0
n2 = 22.0
t0 = n2**min(2.0, 5)
t1 = t0 * 3.141592653589793
answer = t1 / 4.0
print(answer) | 380.132711084365 | train | mathqa_geometry.json |
an oil cylinder was 3 / 4 th full . when 4 bottles of oil is poured into it , it is 4 / 5 th full . how many bottles of oil can the full cylinder hold ? | n0 = 3.0
n1 = 4.0
n2 = 4.0
n3 = 4.0
n4 = 5.0
t0 = n1 / n4
t1 = n0 / n1
t2 = t0 - t1
t3 = t2 / n1
answer = 1.0 / t3
print(answer) | 79.99999999999993 | train | mathqa_geometry.json |
find the sum of divisors of 544 which are perfect squares | import math
n0 = 544.0
t0 = n0 / 2.0
t1 = t0 / 2.0
t2 = t1 / 2.0
t3 = t2 / 2.0
t4 = t3 / 2.0
t5 = n0 / t4
t6 = t5 / 2.0
t7 = math.sqrt(max(0, t6))
t8 = t7 + 1.0
answer = t8 + t6
print(answer) | 21 | train | mathqa_geometry.json |
find the surface area of a 10 cm x 4 cm x 3 cm brick | n0 = 10.0
n1 = 4.0
n2 = 3.0
answer = 2 * (n0 * n1 + n0 * n2 + n1 * n2) # surface of a rectangular prism
print(answer) | 164 | train | mathqa_geometry.json |
a box measuring 35 inches long by 20 inches wide by 10 inches deep is to be filled entirely with identical cubes . no space is to be left unfilled . what is the smallest number of cubes that can accomplish this objective ? | n0 = 35.0
n1 = 20.0
n2 = 10.0
t0 = n2 / 2.0
t1 = n0 * n1
t2 = n2 * t1
t3 = t0**3
answer = t2 / t3
print(answer) | 56 | train | mathqa_geometry.json |
find the area of a parallelogram with base 24 cm and height 16 cm ? | n0 = 24.0
n1 = 16.0
answer = n0 * n1
print(answer) | 384 | train | mathqa_geometry.json |
a cylindrical container of radius 6 cm and height 15 cm is filled with ice - cream . the whole icecream has to be distributed to 10 children in equal cones with hemispherical tops . if the height of the conical portion is four times the radius of its base , find the radius of the ice - cream cone . | import math
n0 = 6.0
n1 = 15.0
n2 = 10.0
t0 = 1.0 / 3.0
t1 = 2.0 / 3.0
t2 = math.pi * n0**2 * n1
t3 = t2 / 10.0
t4 = t0 * 3.141592653589793
t5 = t1 * 3.141592653589793
t6 = t4 * 4.0
t7 = t6 + t5
t8 = t3 / t7
t9 = t8 / 3.0
answer = math.sqrt(max(0, t9))
print(answer) | 3 | train | mathqa_geometry.json |
people were sitting in a circle . 7 th one is direct opposite to 18 th one . . then how many were there in that group ? | n0 = 7.0
n1 = 18.0
t0 = n1 - n0
answer = t0 * 2.0
print(answer) | 22 | train | mathqa_geometry.json |
a certain cube floating in a bucket of water has between 80 and 90 percent of its volume below the surface of the water . if between 6 and 13 cubic centimeters of the cube ' s volume is above the surface of the water , then the length of a side of the cube is approximately | n0 = 80.0
n1 = 90.0
n2 = 6.0
n3 = 13.0
t0 = n3 * 100.0
t1 = 100.0 - n0
t2 = t0 / t1
answer = t2**(1 / 3)
print(answer) | 4.020725758589058 | train | mathqa_geometry.json |
what is the total surface area in square meters of a rectangular solid whose length is 10 meters , width is 9 meters , and depth is 6 meters ? | n0 = 10.0
n1 = 9.0
n2 = 6.0
answer = 2 * (n0 * n1 + n0 * n2 + n1 * n2) # surface of a rectangular prism
print(answer) | 408 | train | mathqa_geometry.json |
f and e are midpoints of ab and ad respectively . if the side of square abcd is 8 , what is the area of triangle cef ? | n0 = 8.0
t0 = n0 / 2.0
t1 = n0**2
t2 = n0 * t0 / 2
t3 = t0 * t0 / 2
t4 = t1 - t2
t5 = t4 - t2
answer = t5 - t3
print(answer) | 24 | train | mathqa_geometry.json |
find the area of a parallelogram with base 60 cm and height 16 cm ? | n0 = 60.0
n1 = 16.0
answer = n0 * n1
print(answer) | 960 | train | mathqa_geometry.json |
in front of you lies a figure made up with 20 x 10 square blocks . will you be able to find out the number of unique squares and rectangles that are being formed inside this figure by combining two or more distinct squares ? | n0 = 20.0
n1 = 10.0
t0 = n0 + 1.0
t1 = n1 + 1.0
t2 = n0 * t0
t3 = n1 * t1
t4 = t2 / 2.0
t5 = t3 / 2.0
answer = t4 * t5
print(answer) | 11550 | train | mathqa_geometry.json |
the sides of the triangle are in the ratio 1 / 2 : 1 / 3 : 1 / 4 and its perimeter is 104 cm . the length of the longest side is ? | n0 = 1.0
n1 = 2.0
n2 = 1.0
n3 = 3.0
n4 = 1.0
n5 = 4.0
n6 = 104.0
t0 = n0 / n5
t1 = n0 / n3
t2 = n0 / n1
t3 = t0 + t1
t4 = t3 + t2
t5 = n6 / t4
answer = t5 * t2
print(answer) | 48 | train | mathqa_geometry.json |
find the area of a parallelogram with base 32 cm and height 18 cm ? | n0 = 32.0
n1 = 18.0
answer = n0 * n1
print(answer) | 576 | train | mathqa_geometry.json |
if the sum of a number and its square is 132 , what is the number ? | import math
n0 = 132.0
t0 = math.sqrt(max(0, n0))
answer = math.floor(t0)
print(answer) | 11 | train | mathqa_geometry.json |
what should be added to 4440 so that it may become a perfect square ? | n0 = 4440.0
t0 = 10.0 + 10.0
t1 = 3.0 + 4.0
t2 = t0 + t0
t3 = t2 + t0
t4 = t3 + t1
t5 = t4 * t4
answer = t5 - n0
print(answer) | 49 | train | mathqa_geometry.json |
a cubical block of metal weighs 5 pounds . how much will another cube of the same metal weigh if its sides are twice as long ? | n0 = 5.0
t0 = 2.0 * 4.0
answer = n0 * t0
print(answer) | 40 | train | mathqa_geometry.json |
the area of a square garden is q square feet and the perimeter is p feet . if q = 2 p + 20 , what is the perimeter of the garden in feet ? | n0 = 2.0
n1 = 20.0
answer = n1 * 2.0
print(answer) | 40 | train | mathqa_geometry.json |
a volume of 11780 l water is in a container of sphere . how many hemisphere of volume 4 l each will be required to transfer all the water into the small hemispheres ? | n0 = 11780.0
n1 = 4.0
answer = n0 / n1
print(answer) | 2945 | train | mathqa_geometry.json |
when magnified 1,000 times by an electron microscope , the image of a certain circular piece of tissue has a diameter of 0.2 centimeter . the actual diameter of the tissue , in centimeters , is | n0 = 1000.0
n1 = 0.2
answer = n1 / n0
print(answer) | 0.0002 | train | mathqa_geometry.json |
in measuring the sides of a rectangle , one side is taken 16 % in excess and other 5 % in deficit . find the error percentage in the area calculated from these measurements . | n0 = 16.0
n1 = 5.0
t0 = n0 * n1
t1 = n0 - n1
t2 = t0 / 100.0
answer = t1 - t2
print(answer) | 10.2 | train | mathqa_geometry.json |
a making a cube with dimension 5 * 5 * 5 using 1 * 1 * 1 cubes . what is the number of cubes needed to make hollow cube looking of the same shape . | n0 = 5.0
n1 = 5.0
n2 = 5.0
n3 = 1.0
n4 = 1.0
n5 = 1.0
t0 = n0 * n0
t1 = n0 - 2.0
t2 = n0 * t0
t3 = t1 * t1
t4 = t3 * 3.0
answer = t2 - t4
print(answer) | 98 | train | mathqa_geometry.json |
find the area of a parallelogram with base 18 cm and height 16 cm ? | n0 = 18.0
n1 = 16.0
answer = n0 * n1
print(answer) | 288 | train | mathqa_geometry.json |
a football field is 9600 square yards . if 800 pounds of fertilizer are spread evenly across the entire field , how many pounds of fertilizer were spread over an area of the field totaling 3600 square yards ? | n0 = 9600.0
n1 = 800.0
n2 = 3600.0
t0 = n1 / n0
answer = n2 * t0
print(answer) | 300 | train | mathqa_geometry.json |
the breath of a rectangular landscape is 8 times its length . there is a playground in it whose area is 3200 square mtr & which is 1 / 9 rd of the total landscape . what is the breath of the landscape ? | import math
n0 = 8.0
n1 = 3200.0
n2 = 1.0
n3 = 9.0
t0 = n1 * n3
t1 = t0 / n0
t2 = math.sqrt(max(0, t1))
answer = n0 * t2
print(answer) | 480 | train | mathqa_geometry.json |
the area of a square field is 1225 km 2 . how long will it take for a horse to run around at the speed of 20 km / h ? | import math
n0 = 1225.0
n1 = 2.0
n2 = 20.0
t0 = math.sqrt(max(0, n0))
t1 = t0 * 4.0
answer = t1 / n2
print(answer) | 7 | train | mathqa_geometry.json |
it has been raining at the rate of 5 centimeters per hour . if the rain filled a cylindrical drum with a depth of 15 centimeters , and area 300 square centimeters , how long did it take to fill the drum completely ? | n0 = 5.0
n1 = 15.0
n2 = 300.0
answer = n1 / n0
print(answer) | 3 | train | mathqa_geometry.json |
the diameter of a cylindrical tin is 10 cm and height is 5 cm . find the volume of the cylinder ? | import math
n0 = 10.0
n1 = 5.0
t0 = n0 / 2.0
t1 = math.pi * t0**2 * n1
answer = t1 / 3.141592653589793
print(answer) | 125.00000000000001 | train | mathqa_geometry.json |
the diameter of a cylindrical tin is 14 cm and height is 2 cm . find the volume of the cylinder ? | import math
n0 = 14.0
n1 = 2.0
t0 = n0 / 2.0
t1 = math.pi * t0**2 * n1
answer = t1 / 3.141592653589793
print(answer) | 98 | train | mathqa_geometry.json |
what is the area of a square field whose diagonal of length 16 m ? | n0 = 16.0
t0 = n0**2
answer = t0 / 2.0
print(answer) | 128 | train | mathqa_geometry.json |
find the circumference and area of radius 13 cm . | import math
n0 = 13.0
answer = math.pi * n0**2
print(answer) | 530.929158456675 | train | mathqa_geometry.json |
a metallic sheet is of rectangular shape with dimensions 48 m x 36 m . from each of its corners , a square is cut off so as to make an open box . if the length of the square is 7 m , the volume of the box ( in m 3 ) is : | n0 = 48.0
n1 = 36.0
n2 = 7.0
n3 = 3.0
t0 = n2 * 2.0
t1 = n0 - t0
t2 = n1 - t0
answer = n2 * t1 * t2
print(answer) | 5236 | train | mathqa_geometry.json |
the diagonal of a rhombus are 40 m and 30 m . its area is : | n0 = 40.0
n1 = 30.0
answer = n0 * n1 / 2
print(answer) | 600 | train | mathqa_geometry.json |
a snooker tournament charges $ 40.00 for vip seats and $ 15.00 for general admission ( “ regular ” seats ) . on a certain night , a total of 320 tickets were sold , for a total cost of $ 7,500 . how many fewer tickets were sold that night for vip seats than for general admission seats ? | n0 = 40.0
n1 = 15.0
n2 = 320.0
n3 = 7500.0
t0 = 3.0 + 4.0
t1 = 2.0 + 3.0
t2 = n1 * n2
t3 = t0 * 1000.0
t4 = t1 * 100.0
t5 = t1 * t1
t6 = t3 + t4
t7 = t6 - t2
t8 = t7 / t5
answer = n2 - t8
print(answer) | 212 | train | mathqa_geometry.json |
the area of a rectangle is 360 sq . m . if its length is increased by 10 m and its width is decreased by 6 m , then its area does not change . find the perimeter of the original rectangle . | n0 = 360.0
n1 = 10.0
n2 = 6.0
t0 = n2 * 3.0
t1 = n0 / t0
answer = 2 * (t1 + t0) # perimetere of rectangle
print(answer) | 76 | train | mathqa_geometry.json |
in measuring the sides of a rectangle , one side is taken 7 % in excess , and the other 6 % in deficit . find the error percent in the area calculated from these measurements . | n0 = 7.0
n1 = 6.0
t0 = n0 * n1
t1 = n0 - n1
t2 = t0 / 100.0
answer = t1 - t2
print(answer) | 0.5800000000000001 | train | mathqa_geometry.json |
how many squares are there between 2011 to 2300 ? ? ? ? | import math
n0 = 2011.0
n1 = 2300.0
t0 = math.sqrt(max(0, n1))
t1 = math.sqrt(max(0, n0))
t2 = math.floor(t0)
t3 = math.floor(t1)
answer = t2 - t3
print(answer) | 3 | train | mathqa_geometry.json |
the perimeter of a triangle is 20 cm and the inradius of the triangle is 3 cm . what is the area of the triangle ? | n0 = 20.0
n1 = 3.0
answer = n0 * n1 / 2
print(answer) | 30 | train | mathqa_geometry.json |
if a cube has a volume of 125 , what is the surface area of one side ? | n0 = 125.0
t0 = n0**(1 / 3)
answer = t0**2
print(answer) | 24.99999999999999 | train | mathqa_geometry.json |
right triangle pqr is the base of the prism in the figure above . if pq = pr = â ˆ š 5 and the height of the prism is 10 , what is the volume of the prism ? | import math
n0 = 5.0
n1 = 10.0
t0 = math.sqrt(max(0, n0))
t1 = t0 * t0 / 2
answer = n1 * t1
print(answer) | 25.000000000000004 | train | mathqa_geometry.json |
what is the ratio between perimeters of two squares one having 2.5 times the diagonal then the other ? | n0 = 2.5
t0 = n0 / n0
answer = n0 / t0
print(answer) | 2.5 | train | mathqa_geometry.json |
all the faces of a cube are painted with blue colour . then it is cut into 125 small equal cubes . how many small cubes will be formed having only one face coloured ? | n0 = 125.0
t0 = 1.0 / 3.0
t1 = n0**min(t0, 5)
t2 = t1 - 2.0
t3 = t2**min(2.0, 5)
t4 = t3 * 60.0
answer = t4 / 10.0
print(answer) | 53.999999999999964 | train | mathqa_geometry.json |
a rectangular courty 3.78 metres long and 5.25 metres wide is to be paved exactly with square tiles , all of the same size . what is the largest size of the tile which could be used for the purpose ? | n0 = 3.78
n1 = 5.25
t0 = n0 * 100.0
t1 = t0 / 3.0
t2 = t1 / 3.0
t3 = t2 / 3.0
t4 = t3 / 2.0
answer = t4 * 3.0
print(answer) | 21 | train | mathqa_geometry.json |
the diagonal of a rhombus are 80 m and 120 m . its area is : | n0 = 80.0
n1 = 120.0
answer = n0 * n1 / 2
print(answer) | 4800 | train | mathqa_geometry.json |
an equilateral triangle t 2 is formed by joining the mid points of the sides of another equilateral triangle t 1 . a third equilateral triangle t 3 is formed by joining the mid - points of t 2 and this process is continued indefinitely . if each side of t 1 is 45 cm , find the sum of the perimeters of all the triangles . | n0 = 2.0
n1 = 1.0
n2 = 3.0
n3 = 2.0
n4 = 1.0
n5 = 45.0
t0 = n5 + n5 + n5 # perimeter of a triangle
answer = t0 + t0
print(answer) | 270 | train | mathqa_geometry.json |
find the perimeter and area of a square of side 19 cm . | n0 = 19.0
answer = n0**2
print(answer) | 361 | train | mathqa_geometry.json |
there are 7 non - collinear points . how many triangles can be drawn by joining these points ? | n0 = 7.0
t0 = 1.0 + 4.0
answer = n0 * t0
print(answer) | 35 | train | mathqa_geometry.json |
the area of an equilateral triangle is subtracted from its base , and the perimeter is then added to this total , the result is 4 . what is the height of the equilateral triangle if its base is 2 ? | n0 = 4.0
n1 = 2.0
t0 = n1 * 3.0
t1 = n1 - n0
answer = t0 + t1
print(answer) | 4 | train | mathqa_geometry.json |
find the area of a parallelogram with base 34 cm and height 18 cm ? | n0 = 34.0
n1 = 18.0
answer = n0 * n1
print(answer) | 612 | train | mathqa_geometry.json |
in the rectangular coordinate system , points ( 8 , 0 ) and ( – 8 , 0 ) both lie on circle c . what is the maximum possible value of the radius of c ? | import math
n0 = 8.0
n1 = 0.0
n2 = 8.0
n3 = 0.0
t0 = n0**min(2.0, 5)
answer = math.sqrt(max(0, t0))
print(answer) | 8 | train | mathqa_geometry.json |
a lady builds 10 cm length , 18 cm width , and 4 cm height box using 12 cubic cm cubes . what is the minimum number of cubes required to build the box ? | n0 = 10.0
n1 = 18.0
n2 = 4.0
n3 = 12.0
t0 = n0 * n1
t1 = n2 * t0
answer = t1 / n3
print(answer) | 60 | train | mathqa_geometry.json |
the diagonal of the floor of a rectangular closet is 7 feet . the shorter side of the closet is 4 feet . what is the area of the closet in square feet ? | import math
n0 = 7.0
n1 = 4.0
t0 = 2.0 * 4.0
t1 = n0 * 2.0
t2 = t0 + 1.0
t3 = t1 + 1.0
t4 = t2 / 2.0
t5 = t3 / 2.0
t6 = t5**min(2.0, 5)
t7 = t4**min(2.0, 5)
t8 = t6 - t7
t9 = math.sqrt(max(0, t8))
answer = t4 * t9 # area of rectangle
print(answer) | 27 | train | mathqa_geometry.json |
the diagonal of a rectangle is cm and its area is 20 sq . cm . the perimeter of the rectangle must be : | import math
n0 = 20.0
t0 = n0 + n0
t1 = t0 + 1.0
t2 = t0 + t1
t3 = math.sqrt(max(0, t2))
answer = t3 * 2.0
print(answer) | 18 | train | mathqa_geometry.json |
what is the ratio between perimeters of two squares one having 4 times the diagonal then the other ? | n0 = 4.0
t0 = n0 / n0
answer = n0 / t0
print(answer) | 4 | train | mathqa_geometry.json |
calculate the area of a triangle , if the sides are 13 cm , 12 cm and 5 cm , what is its area ? | n0 = 13.0
n1 = 12.0
n2 = 5.0
t0 = n1 / 2.0
answer = n2 * t0
print(answer) | 30 | train | mathqa_geometry.json |
in a certain circle there are 9 points . what is the number of the triangles connecting 4 points of the 9 points ? | import math
n0 = 9.0
n1 = 4.0
n2 = 9.0
t0 = 10.0 / 2.0
t1 = math.factorial(min(15, int(n0)))
t2 = math.factorial(min(15, int(n1)))
t3 = math.factorial(min(15, int(t0)))
t4 = t3 * t2
answer = t1 / t4
print(answer) | 126 | train | mathqa_geometry.json |
if the height of a cone is increased by 100 % then its volume is increased by ? | n0 = 100.0
answer = n0 * 1.0 # area of rectangle
print(answer) | 100 | train | mathqa_geometry.json |
34 . the side surface of a cylinder is rolled with a rectangle . if the height of a cylinder is 16 feet and the perimeter of the circular base . is 12 feet , what is the diagonal of the rectangle ? | import math
n0 = 34.0
n1 = 16.0
n2 = 12.0
t0 = n1 * n1
t1 = n2 * n2
t2 = t0 + t1
answer = math.sqrt(max(0, t2))
print(answer) | 20 | train | mathqa_geometry.json |
a rectangular pig farm has a fence along three sides and a wall along the fourth side . the fenced side opposite the wall is twice the length of each of the other two fenced sides . if the area of the rectangular region is 1250 square feet , what is the total length of the fence , in feet ? | import math
n0 = 1250.0
t0 = n0 / 2.0
t1 = math.sqrt(max(0, t0))
t2 = t1 * 2.0
answer = 2 * (t2 + t1) # perimetere of rectangle
print(answer) | 150 | train | mathqa_geometry.json |
by combining number of small cubes , a larger cube is produced . the ratio between volume of larger cube and small cube is 1000 : 8 then how many small cubes are required to produce a larger cube ? | n0 = 1000.0
n1 = 8.0
answer = n0 / n1
print(answer) | 125 | train | mathqa_geometry.json |
abcd is a square where ab = â ˆ š 6000 . let x be a point on ab and y be a point on cd such that ax = cy . compute the area of trapezoid axyd . | n0 = 6000.0
answer = n0 / 2.0
print(answer) | 3000 | train | mathqa_geometry.json |
the length of a rectangle is one - sixth of the radius of a circle . the radius of the circle is equal to the side of the square , whose area is 1296 sq . units . what is the area ( in sq . units ) of the rectangle if the rectangle if the breadth is 10 units ? | import math
n0 = 1296.0
n1 = 10.0
t0 = math.sqrt(max(0, n0))
answer = n1 * t0
print(answer) | 360 | train | mathqa_geometry.json |
if the area of a square with sides of length 4 centimeters is equal to the area of a rectangle with a width of 4 centimeters , what is the length of the rectangle , in centimeters ? | n0 = 4.0
n1 = 4.0
t0 = n0**min(2.0, 5)
answer = t0 / n1
print(answer) | 4 | train | mathqa_geometry.json |
three walls have wallpaper covering a combined area of 300 square meters . by overlapping the wallpaper to cover a wall with an area of 180 square meters , the area that is covered by exactly two layers of wallpaper is 30 square meters . what is the area that is covered with three layers of wallpaper ? | n0 = 300.0
n1 = 180.0
n2 = 30.0
t0 = n0 - n1
t1 = t0 - n2
answer = t1 / 2.0
print(answer) | 45 | train | mathqa_geometry.json |
the two sides of a triangle are 32 and 68 . the area is 960 sq . cm . find the third side of triangle ? | import math
n0 = 32.0
n1 = 68.0
n2 = 960.0
t0 = n0 + n1
t1 = n0 * n1
t2 = n2**min(2.0, 5)
t3 = t2 * 4.0
t4 = t0**min(2.0, 5)
t5 = t1**min(2.0, 5)
t6 = t5 - t3
t7 = math.sqrt(max(0, t6))
t8 = t1 + t7
t9 = t8 / 2.0
t10 = t9 * 4.0
t11 = t4 - t10
t12 = math.sqrt(max(0, t11))
t13 = t0 + t12
t14 = t13 / 2.0
t15 = t14 * 2.0
answer = t15 - t0
print(answer) | 60 | train | mathqa_geometry.json |
can n and can в are both right circular cylinders . the radius of can n is twice the radius of can b , while the height of can n is half the height of can b . if it costs $ 4.00 to fill half of can b with a certain brand of gasoline , how much would it cost to completely fill can n with the same brand of gasoline ? | n0 = 4.0
t0 = n0 * 2.0
t1 = 2.0**min(2.0, 5)
t2 = t1 / 2.0
answer = t2 * t0
print(answer) | 16 | train | mathqa_geometry.json |
if the sides of a triangle are 39 cm , 36 cm and 15 cm , what is its area ? | n0 = 39.0
n1 = 36.0
n2 = 15.0
t0 = n1 * n2
answer = t0 / 2.0
print(answer) | 270 | train | mathqa_geometry.json |
if paint costs $ 3.20 per quart , and a quart covers 1200 square feet , how much will it cost to paint the outside of a cube 10 feet on each edge ? | n0 = 3.2
n1 = 1200.0
n2 = 10.0
t0 = n0 / n1
t1 = 6 * n2**2 # surface of a cube
answer = t0 * t1
print(answer) | 1.6000000000000003 | train | mathqa_geometry.json |
the surface of a cube is 96 sq cm . find its volume ? | import math
n0 = 96.0
t0 = 2.0 + 4.0
t1 = n0 / t0
t2 = math.sqrt(max(0, t1))
answer = t2**3
print(answer) | 64 | train | mathqa_geometry.json |
the roof of an apartment building is rectangular and its length is 4 times longer than its width . if the area of the roof is 784 feet squared , what is the difference between the length and the width of the roof ? | import math
n0 = 4.0
n1 = 784.0
t0 = n1 / n0
t1 = math.sqrt(max(0, t0))
t2 = t1 * n0
answer = t2 - t1
print(answer) | 42 | train | mathqa_geometry.json |
the perimeter of a square is 48 m . find the area of the square . | n0 = 48.0
t0 = n0 / 4.0
answer = t0**2
print(answer) | 144 | train | mathqa_geometry.json |
rectangular tile each of size 25 cm by 16 cm must be laid horizontally on a rectangular floor of size 180 cm by 120 cm , such that the tiles do not overlap and they are placed with edges jutting against each other on all edges . a tile can be placed in any orientation so long as its edges are parallel to the edges of floor . no tile should overshoot any edge of the floor . the maximum number of tiles that can be accommodated on the floor is : | n0 = 25.0
n1 = 16.0
n2 = 180.0
n3 = 120.0
t0 = n2 * n3
t1 = n0 * n1
answer = t0 / t1
print(answer) | 54 | train | mathqa_geometry.json |
the length of a rectangular plot is thrice its breadth . if the area of the rectangular plot is 2028 sq m , then what is the breadth of the rectangular plot ? | import math
n0 = 2028.0
t0 = n0 / 3.0
answer = math.sqrt(max(0, t0))
print(answer) | 26 | train | mathqa_geometry.json |
the area of an isosceles trapezoid with sides of length 5 and bases of length 7 and 13 is ? | n0 = 5.0
n1 = 7.0
n2 = 13.0
answer = 4.0 * (n2 + n1) / 2 # quadrilateral area
print(answer) | 40 | train | mathqa_geometry.json |
in a rectangular axis system , what is the area of a parallelogram with the coordinates : ( 4,4 ) , ( 7,4 ) , ( 5,9 ) , ( 8,9 ) ? | n0 = 4.0
n1 = 4.0
n2 = 7.0
n3 = 4.0
n4 = 5.0
n5 = 9.0
n6 = 8.0
n7 = 9.0
answer = 2.0 + 3.0
print(answer) | 5 | train | mathqa_geometry.json |
find the surface area of a 8 cm x 6 cm x 2 cm brick . | n0 = 8.0
n1 = 6.0
n2 = 2.0
answer = 2 * (n0 * n1 + n0 * n2 + n1 * n2) # surface of a rectangular prism
print(answer) | 152 | train | mathqa_geometry.json |
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