solution_code_ko
stringlengths 27
5.97k
| answer_ko
stringlengths 1
11
| answer_en
stringlengths 1
20
| solution_abst_ko
stringlengths 1
256
| solution_code_en
stringlengths 27
5.97k
| solution_abst_en
stringlengths 1
287
| question_en
stringlengths 20
555
| question_ko
stringlengths 11
282
| category
stringclasses 5
values |
|---|---|---|---|---|---|---|---|---|
var_a = 5
var_b = 2
var_c = var_a ** var_b
var_d = 4
var_e = var_c / var_d
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
6.25
|
6.25
|
5 2 [OP_POW] 4 [OP_DIV]
|
var_a = 5
var_b = 2
var_c = var_a ** var_b
var_d = 4
var_e = var_c / var_d
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
5 2 [OP_POW] 4 [OP_DIV]
|
The square and the rectangle have the same area. If one side of the square is 5 centimeters (cm) and one side of the rectangle is 4 centimeters (cm), what is the length of the other side of the rectangle in centimeters (cm)?
|
λ μ μ¬κ°νκ³Ό μ§μ¬κ°νμ λμ΄λ κ°μ΅λλ€. μ μ¬κ°νμ ν λ³μ κΈΈμ΄κ° 5μΌν°λ―Έν°(γ), μ§μ¬κ°νμ ν λ³μ κΈΈμ΄κ° 4μΌν°λ―Έν°(γ)λΌκ³ ν λ, μ§μ¬κ°νμ λ€λ₯Έ ν λ³μ κΈΈμ΄λ λͺ μΌν°λ―Έν°(γ)μ
λκΉ?
|
Geometry
|
var_a = 16
list_a = []
num_sqrt = int(math.sqrt(var_a))
for i in range(1, num_sqrt+1):
if var_a % i == 0:
list_a.append(i)
list_a.append(int(var_a/i))
list_a = sorted(set(list_a))
var_b = len(list_a)
var_c = 2
var_d = var_b // var_c
print(int(var_d))
|
2
|
2
|
16 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN] 2 [OP_FDIV]
|
var_a = 16
list_a = []
num_sqrt = int(math.sqrt(var_a))
for i in range(1, num_sqrt+1):
if var_a % i == 0:
list_a.append(i)
list_a.append(int(var_a/i))
list_a = sorted(set(list_a))
var_b = len(list_a)
var_c = 2
var_d = var_b // var_c
print(int(var_d))
|
16 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN] 2 [OP_FDIV]
|
If you multiply the age of the Seongju by the age of Seongju's younger brother, you get 16. How many possible numbers are there for the age of Seongju? (However, Seongju and his younger brother are not twins.)
|
μ±μ£Όμ λμ΄μ μ±μ£Ό λμμ λμ΄λ₯Ό κ³±νμλλ 16μ΄ λμμ λ, μ±μ£Όμ λμ΄λ‘ κ°λ₯ν μλ λͺ κ°μ
λκΉ? (λ¨, μ±μ£Όμ λμμ μλ₯μ΄κ° μλλλ€.)
|
Correspondence
|
var_a = '57A-B14=364'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('Γ','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('Γ·','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c))
|
8
|
8
|
57A-B14=364 A [OP_DIGIT_UNK_SOLVER]
|
var_a = '57A-B14=364'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('Γ','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('Γ·','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c))
|
57A-B14=364 A [OP_DIGIT_UNK_SOLVER]
|
If 57A-B14=364, what number should go in A?
|
57A-B14=364μΌ λ, Aμ λ€μ΄κ°μΌ νλ μ«μλ 무μμΈκ°μ?
|
Correspondence
|
var_a = 946
var_b = 2
var_c = var_a / var_b
var_d = 14
var_e = var_c - var_d
var_f = 3
var_g = var_e / var_f
var_h = 3
var_i = var_g / var_h
var_j = 14
var_k = var_i + var_j
var_l = 2
var_m = var_k * var_l
print(int(var_m))
|
130
|
130
|
946 2 [OP_DIV] 14 [OP_SUB] 3 [OP_DIV] 3 [OP_DIV] 14 [OP_ADD] 2 [OP_MUL]
|
var_a = 946
var_b = 2
var_c = var_a / var_b
var_d = 14
var_e = var_c - var_d
var_f = 3
var_g = var_e / var_f
var_h = 3
var_i = var_g / var_h
var_j = 14
var_k = var_i + var_j
var_l = 2
var_m = var_k * var_l
print(int(var_m))
|
946 2 [OP_DIV] 14 [OP_SUB] 3 [OP_DIV] 3 [OP_DIV] 14 [OP_ADD] 2 [OP_MUL]
|
I had to divide a number by 3, add 14, then multiply by 2, but I made a mistake by multiplying by 3, adding 14, then multiplying by 2 and got 946. How much is the original calculation?
|
μ΄λ€ μλ₯Ό 3μΌλ‘ λλκ³ 14λ₯Ό λν λ€ 2λ₯Ό κ³±ν΄μΌ νλλ° μ λͺ»νμ¬ 3μ κ³±νκ³ 14λ₯Ό λν λ€ 2λ₯Ό κ³±νμ¬ 946μ΄ λμμ΅λλ€. μλλλ‘ κ³μ°νλ©΄ μΌλ§μ
λκΉ?
|
Correspondence
|
var_a = 12
var_b = '3ΓA-A=10'
var_c = 'A'
ans_dict = dict()
var_b = var_b.replace('Γ','*')
var_b = var_b.replace('x','*')
var_b = var_b.replace('Γ·','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_b):
if v in variable_candi:
ans_dict[v] = 0
candidate_num = [i for i in range(51)]
candi = list(itertools.product(candidate_num, repeat=len(ans_dict)))
for c in candi:
temp = var_b
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
if term_list[i] == '':
new_eq += str(term_list[i])+op_list[i]
else:
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:
new_eq=new_eq.replace('==','=')
new_eq=new_eq.replace('>','')
new_eq=new_eq.replace('<','')
new_eq=new_eq.split('=')
for i in range(len(new_eq)-1):
eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))
if not eval_result:
break
else:
eval_result = eval(new_eq)
except:
eval_result = False
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_d = ans_dict[var_c]
var_e = var_a - var_d
var_f = 6
var_g = var_e + var_f
print(int(var_g))
|
13
|
13
|
12 3ΓA-A=10 A [OP_NUM_UNK_SOLVER] [OP_SUB] 6 [OP_ADD]
|
var_a = 12
var_b = '3ΓA-A=10'
var_c = 'A'
ans_dict = dict()
var_b = var_b.replace('Γ','*')
var_b = var_b.replace('x','*')
var_b = var_b.replace('Γ·','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_b):
if v in variable_candi:
ans_dict[v] = 0
candidate_num = [i for i in range(51)]
candi = list(itertools.product(candidate_num, repeat=len(ans_dict)))
for c in candi:
temp = var_b
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
if term_list[i] == '':
new_eq += str(term_list[i])+op_list[i]
else:
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:
new_eq=new_eq.replace('==','=')
new_eq=new_eq.replace('>','')
new_eq=new_eq.replace('<','')
new_eq=new_eq.split('=')
for i in range(len(new_eq)-1):
eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))
if not eval_result:
break
else:
eval_result = eval(new_eq)
except:
eval_result = False
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_d = ans_dict[var_c]
var_e = var_a - var_d
var_f = 6
var_g = var_e + var_f
print(int(var_g))
|
12 3ΓA-A=10 A [OP_NUM_UNK_SOLVER] [OP_SUB] 6 [OP_ADD]
|
There are different numbers A, B, and C. 3ΓA-A=10, B+A=12, C-B=6. Get C.
|
μλ‘ λ€λ₯Έ μ A, B, Cκ° μμ΅λλ€. 3ΓA-A=10, B+A=12, C-B=6μ
λλ€. Cλ₯Ό ꡬνμμ€.
|
Correspondence
|
var_a = 2
print(int(var_a))
|
2
|
2
|
2
|
var_a = 2
print(int(var_a))
|
2
|
How many times bigger is the diameter of a circle compared to its radius?
|
ν μμμ μ§λ¦μ λ°μ§λ¦μ λͺ λ°° μ
λκΉ?
|
Geometry
|
var_a = 25
var_b = 1
var_c = var_a + var_b
print(int(var_c))
|
26
|
26
|
25 1 [OP_ADD]
|
var_a = 25
var_b = 1
var_c = var_a + var_b
print(int(var_c))
|
25 1 [OP_ADD]
|
Taehyung, who participated in the running match, shook hands with everyone else once, and he shook hands a total of 25 times. How many people participated in the running test at this time?
|
λ¬λ¦¬κΈ° μν©μ μ°Έκ°ν ννμ΄κ° λ€λ₯Έ λͺ¨λ μ¬λλ€κ³Ό μ
μλ₯Ό νλ²μ© νλλ μ΄ 25λ² μ
μλ₯Ό νμ΅λλ€. μ΄λ λ¬λ¦¬κΈ° μνμ μ°Έκ°ν μ¬λμ λͺ¨λ λͺλͺ
μ
λκΉ?
|
Possibility
|
var_a = 127000
var_b = 5000
var_c = var_a / var_b
var_d = 1
var_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))
var_f = 127000
var_g = 8000
var_h = var_f / var_g
var_i = 1
var_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1))
var_k = var_e - var_j
print(int(var_k))
|
10
|
10
|
127000 5000 [OP_DIV] 1 [OP_CEIL] 127000 8000 [OP_DIV] 1 [OP_CEIL] [OP_SUB]
|
var_a = 127000
var_b = 5000
var_c = var_a / var_b
var_d = 1
var_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))
var_f = 127000
var_g = 8000
var_h = var_f / var_g
var_i = 1
var_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1))
var_k = var_e - var_j
print(int(var_k))
|
127000 5000 [OP_DIV] 1 [OP_CEIL] 127000 8000 [OP_DIV] 1 [OP_CEIL] [OP_SUB]
|
127,000 toys were made at the factory in Ulsan. How many more trucks do you need to transport these toys to Seoul by trucks with a capacity of 5000 toys than by trucks with a capacity of 8000 toys?
|
μΈμ°μ μλ 곡μ₯μμ 127000κ°μ μ₯λκ°μ΄ λ§λ€μ΄μ‘μ΅λλ€. μ΄ μ₯λκ°λ€μ μμΈκΉμ§ μ΄λ°νλ €κ³ ν λ 5000κ°κΉμ§ μ€μ μ μλ νΈλμΌλ‘ μ΄λ°νλ €λ©΄ 8000κ°κΉμ§ μ€μ μ μλ νΈλμΌλ‘ μ΄λ°ν λλ³΄λ€ λͺ λκ° λ νμν©λκΉ?
|
Comparison
|
var_a = 1
var_b = 100
list_a = []
if var_a%2==0:
for i in range(var_a+1, var_b+1, 2):
list_a.append(i)
else:
for i in range(var_a, var_b+1, 2):
list_a.append(i)
var_c = 1
list_b=list_a.copy()
list_b.sort()
var_d = list_b[-var_c]
var_e = 1
list_c=list_a.copy()
list_c.sort()
var_f = list_c[var_e-1]
var_g = var_d - var_f
print(int(var_g))
|
98
|
98
|
1 100 [OP_LIST_ODD] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]
|
var_a = 1
var_b = 100
list_a = []
if var_a%2==0:
for i in range(var_a+1, var_b+1, 2):
list_a.append(i)
else:
for i in range(var_a, var_b+1, 2):
list_a.append(i)
var_c = 1
list_b=list_a.copy()
list_b.sort()
var_d = list_b[-var_c]
var_e = 1
list_c=list_a.copy()
list_c.sort()
var_f = list_c[var_e-1]
var_g = var_d - var_f
print(int(var_g))
|
1 100 [OP_LIST_ODD] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]
|
Find the difference between the largest and smallest odd numbers from 1 to 100.
|
1λΆν° 100κΉμ§μ νμ μ€ κ°μ₯ ν° μμ κ°μ₯ μμ μμ μ°¨λ₯Ό ꡬνμμ€.
|
Arithmetic calculation
|
var_a = 36
var_b = 70
var_c = 7
var_d = var_b / var_c
var_e = var_a - var_d
print(int(var_e))
|
26
|
26
|
36 70 7 [OP_DIV] [OP_SUB]
|
var_a = 36
var_b = 70
var_c = 7
var_d = var_b / var_c
var_e = var_a - var_d
print(int(var_e))
|
36 70 7 [OP_DIV] [OP_SUB]
|
I made the mistake of multiplying 7 by a number, which was supposed to be the subtraction of 36 and a number, so I got 70. Find the correctly calculated answer.
|
36μ μ΄λ€ μλ₯Ό λΉΌμΌ ν κ²μ μλͺ»νμ¬ 7μ μ΄λ€ μλ₯Ό κ³±νλλ 70μ΄ λμμ΅λλ€. λ°λ₯΄κ² κ³μ°νλ©΄ μΌλ§μΈμ§ ꡬνμμ€.
|
Correspondence
|
var_a = 'μ€κΈ°'
var_b = 'μ κ΅'
var_c = 'μ λ'
var_d = 'μ μ '
var_e = 'νν'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 7
var_g = 6
var_h = 9
var_i = 8
var_j = 10
list_b= []
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
var_k = 1
list_c=list_b.copy()
list_c.sort()
var_l = list_c[-var_k]
var_m = list_b.index(var_l)+1
var_n = list_a[var_m-1]
print(var_n)
|
νν
|
Taehyung
|
[OP_LIST_SOL] μ€κΈ° μ κ΅ μ λ μ μ νν [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 10 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
|
var_a = 'Yoongi'
var_b = 'Jungkook'
var_c = 'Yuna'
var_d = 'Yoojung'
var_e = 'Taehyung'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 7
var_g = 6
var_h = 9
var_i = 8
var_j = 10
list_b= []
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
var_k = 1
list_c=list_b.copy()
list_c.sort()
var_l = list_c[-var_k]
var_m = list_b.index(var_l)+1
var_n = list_a[var_m-1]
print(var_n)
|
[OP_LIST_SOL] Yoongi Jungkook Yuna Yoojung Taehyung [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 10 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
|
Yoongi collected 7 points, Jungkook 6 points, Yuna 9 points, Yoojung 8 points, and Taehyung 10 points. Who collected the largest number?
|
μ€κΈ°λ 7, μ κ΅μ 6, μ λλ 9, μ μ μ 8, ννμ 10λ§νΌ λͺ¨μμ΅λλ€. λκ° λͺ¨μ μ«μκ° κ°μ₯ ν½λκΉ?
|
Comparison
|
var_a = 9
var_b = 7
var_c = var_a + var_b
var_d = 5
var_e = var_c * var_d
print(int(var_e))
|
80
|
80
|
9 7 [OP_ADD] 5 [OP_MUL]
|
var_a = 9
var_b = 7
var_c = var_a + var_b
var_d = 5
var_e = var_c * var_d
print(int(var_e))
|
9 7 [OP_ADD] 5 [OP_MUL]
|
Yoongi subtracted 7 from a particular number and got 9. Now we want to multiply that particular number by 5. What will be the result then?
|
μ€κΈ°κ° μ΄λ€ μμμ 7μ λΉΌ 9λ₯Ό μ»μμ΅λλ€. μ΄μ μ΄λ€ μμ 3μ κ³±νκ³ μ ν©λλ€. μ΄ κ²°κ³Όκ°μ ꡬνμμ€.
|
Correspondence
|
var_a = 12
var_b = 2
var_c = var_a * var_b
var_d = 17
var_e = var_c + var_d
print(int(var_e))
|
41
|
41
|
12 2 [OP_MUL] 17 [OP_ADD]
|
var_a = 12
var_b = 2
var_c = var_a * var_b
var_d = 17
var_e = var_c + var_d
print(int(var_e))
|
12 2 [OP_MUL] 17 [OP_ADD]
|
You want to find the perimeter of an isosceles triangle. If the length of each side of an isosceles triangle is 12 centimeters (cm) and the length of the other side is 17 centimeters (cm), what is the perimeter in centimeters (cm)?
|
μ΄λ±λ³μΌκ°νμ λλ μ κΈΈμ΄λ₯Ό ꡬνκ³ μΆμ΅λλ€. μ΄λ±λ³μΌκ°νμ μλ³μ κΈΈμ΄λ 12 μΌν°λ―Έν°(γ)μ΄λ©° λ€λ₯Έ λ³μ κΈΈμ΄λ 17 μΌν°λ―Έν°(γ)μΌ λ, λλ λ λͺ μΌν°λ―Έν°(γ)μΌκΉμ?
|
Geometry
|
var_a = 161
var_b = 7
var_c = var_a / var_b
print(int(var_c))
|
23
|
23
|
161 7 [OP_DIV]
|
var_a = 161
var_b = 7
var_c = var_a / var_b
print(int(var_c))
|
161 7 [OP_DIV]
|
I'm trying to make 161 ribbons in one week. How many ribbons do I need to make on average per day?
|
μΌμ£ΌμΌλμ 리본 161κ°λ₯Ό λ§λ€λ €κ³ ν©λλ€. ν루μ νκ· λͺ κ°μ 리본μ λ§λ€μ΄μΌ ν©λκΉ?
|
Arithmetic calculation
|
var_a = 1
var_b = 4
var_c = 5
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = len(list_a)
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 1
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
print(int(var_f))
|
541
|
541
|
[OP_LIST_SOL] 1 4 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]
|
var_a = 1
var_b = 4
var_c = 5
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = len(list_a)
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 1
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
print(int(var_f))
|
[OP_LIST_SOL] 1 4 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]
|
Find the largest number that can be formed by using 1, 4, and 5 all once.
|
1, 4, 5μ ν λ²μ© λͺ¨λ μ¬μ©νμ¬ λ§λ€ μ μλ κ°μ₯ ν° μλ₯Ό ꡬνμμ€.
|
Possibility
|
var_a = 15
var_b = 2
var_c = var_a ** var_b
var_d = 9
var_e = 2
var_f = var_d ** var_e
var_g = var_c - var_f
var_h = 0.5
var_i = var_g ** var_h
var_j = 9
var_k = var_i * var_j
var_l = 2
var_m = var_k / var_l
print(int(var_m))
|
54
|
54
|
15 2 [OP_POW] 9 2 [OP_POW] [OP_SUB] 1/2 [OP_POW] 9 [OP_MUL] 2 [OP_DIV]
|
var_a = 15
var_b = 2
var_c = var_a ** var_b
var_d = 9
var_e = 2
var_f = var_d ** var_e
var_g = var_c - var_f
var_h = 0.5
var_i = var_g ** var_h
var_j = 9
var_k = var_i * var_j
var_l = 2
var_m = var_k / var_l
print(int(var_m))
|
15 2 [OP_POW] 9 2 [OP_POW] [OP_SUB] 1/2 [OP_POW] 9 [OP_MUL] 2 [OP_DIV]
|
What is the area of a triangle whose hypotenuse is 15 centimeters (cm) and the base is 9 centimeters (cm)?
|
λΉλ³μ κΈΈμ΄κ° 15μΌν°λ―Έν°(γ), λ°λ³μ κΈΈμ΄κ° 9μΌν°λ―Έν°(γ)μΈ μΌκ°νμ λμ΄λ?
|
Geometry
|
var_a = '62A94'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 62500
list_b = []
for i in list_a:
if i >= var_b:
list_b.append(i)
var_c = '62A94'
var_d = 'A'
var_c = str(var_c)
var_d = str(var_d)
unk_idx = var_c.index(var_d)
list_c = []
for elem in list_b:
elem = str(elem)
list_c.append(int(elem[unk_idx]))
list_c = list(set(list_c))
list_c = [float(i) for i in list_c]
var_e = sum(list_c)
print(int(var_e))
|
35
|
35
|
62A94 [OP_GEN_POSSIBLE_LIST] 62500 [OP_LIST_MORE_EQUAL] 62A94 A [OP_LIST_FIND_UNK] [OP_LIST_SUM]
|
var_a = '62A94'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 62500
list_b = []
for i in list_a:
if i >= var_b:
list_b.append(i)
var_c = '62A94'
var_d = 'A'
var_c = str(var_c)
var_d = str(var_d)
unk_idx = var_c.index(var_d)
list_c = []
for elem in list_b:
elem = str(elem)
list_c.append(int(elem[unk_idx]))
list_c = list(set(list_c))
list_c = [float(i) for i in list_c]
var_e = sum(list_c)
print(int(var_e))
|
62A94 [OP_GEN_POSSIBLE_LIST] 62500 [OP_LIST_MORE_EQUAL] 62A94 A [OP_LIST_FIND_UNK] [OP_LIST_SUM]
|
A can be 0 to 9. Given the five-digit number 62A94, which, when rounded to the thousands place, is 63000, find the sum of the numbers that can fit in A.
|
0λΆν° 9κΉμ§ Aμ λ€μ΄κ° μ μμ΅λλ€. λ°±μ μ리μμ λ°μ¬λ¦Όνλ©΄ 63000μ΄ λλ λ€μ― μ리 μ 62A94κ° μμ λ Aμ λ€μ΄κ° μ μλ μλ€μ ν©μ ꡬνμμ€.
|
Correspondence
|
var_a = 1
var_b = 365
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 100
var_e = '[OP_LIS_MORE_EQUAL]'
var_f = len(list_a)
print(int(var_f))
|
365
|
365
|
1 365 1 [OP_LIST_ARANGE] 100 [OP_LIS_MORE_EQUAL] [OP_LIST_LEN]
|
var_a = 1
var_b = 365
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 100
var_e = '[OP_LIS_MORE_EQUAL]'
var_f = len(list_a)
print(int(var_f))
|
1 365 1 [OP_LIST_ARANGE] 100 [OP_LIS_MORE_EQUAL] [OP_LIST_LEN]
|
How many three-digit numbers are there in the numbers from 1 to 365?
|
1λΆν° 365κΉμ§μ μ μ€μμ μΈ μ리 μλ λͺ¨λ λͺ κ°μΈμ§ ꡬνμμ€.
|
Arithmetic calculation
|
var_a = 9
var_b = 4
var_c = 2
var_d = 5
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 1
list_c=list_b.copy()
list_c.sort()
var_g = list_c[-var_f]
var_h = 1
list_d=list_b.copy()
list_d.sort()
var_i = list_d[var_h-1]
var_j = var_g - var_i
print(int(var_j))
|
71
|
71
|
[OP_LIST_SOL] 9 4 2 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]
|
var_a = 9
var_b = 4
var_c = 2
var_d = 5
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 1
list_c=list_b.copy()
list_c.sort()
var_g = list_c[-var_f]
var_h = 1
list_d=list_b.copy()
list_d.sort()
var_i = list_d[var_h-1]
var_j = var_g - var_i
print(int(var_j))
|
[OP_LIST_SOL] 9 4 2 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]
|
Find the value of subtracting the smallest two-digit number from the largest two-digit number that can be formed by drawing two different numbers from 9, 4, 2, and 5.
|
9, 4, 2, 5 μ€μμ μλ‘ λ€λ₯Έ μ«μ 2κ°λ₯Ό λ½μ λ§λ€ μ μλ λ μ리 μ μ€ κ°μ₯ ν° μμμ κ°μ₯ μμ μλ₯Ό λΊ κ°μ ꡬνμμ€.
|
Possibility
|
var_a = 62
var_b = 1
var_c = 8
var_d = 5
var_e = var_c - var_d
var_f = var_b * var_e
var_g = var_a + var_f
var_h = 10
var_i = 7
var_j = 2
var_k = var_i - var_j
var_l = var_h * var_k
var_m = var_g - var_l
print(int(var_m))
|
15
|
15
|
62 1 8 5 [OP_SUB] [OP_MUL] [OP_ADD] 10 7 2 [OP_SUB] [OP_MUL] [OP_SUB]
|
var_a = 62
var_b = 1
var_c = 8
var_d = 5
var_e = var_c - var_d
var_f = var_b * var_e
var_g = var_a + var_f
var_h = 10
var_i = 7
var_j = 2
var_k = var_i - var_j
var_l = var_h * var_k
var_m = var_g - var_l
print(int(var_m))
|
62 1 8 5 [OP_SUB] [OP_MUL] [OP_ADD] 10 7 2 [OP_SUB] [OP_MUL] [OP_SUB]
|
In two-digit subtraction, 62 was obtained by incorrectly misrepresenting 8 in the ones digit of the number being subtracted as another number and incorrectly misrepresenting 7 in the tens digit of the subtracting number as another number. If the numbers incorrectly misrepresented were 5 and 2, respectively, find the result of the correct calculation.
|
λ μ리 μμ λΊμ
μμ λΉΌμ΄μ§λ μμ μΌμ μ리 μ«μ 8μ λ€λ₯Έ μλ‘ μλͺ» λ³΄κ³ , λΉΌλ μμ μμ μ리 μ«μ 7μ λ€λ₯Έ μλ‘ μλͺ» λ³΄κ³ κ³μ°νμμ λ 62κ° λμμ΅λλ€. μλͺ» λ³Έ μκ° κ°κ° 5μ 2μλ€λ©΄, λ°λ₯΄κ² κ³μ°ν κ²°κ³Όλ₯Ό ꡬνμμ€.
|
Arithmetic calculation
|
var_a = 1
var_b = 2
var_c = 3
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 4
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_b = [float(i) for i in list_b]
var_e = sum(list_b)
print(int(var_e))
|
179982
|
179982
|
[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] 4 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]
|
var_a = 1
var_b = 2
var_c = 3
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 4
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_b = [float(i) for i in list_b]
var_e = sum(list_b)
print(int(var_e))
|
[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] 4 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]
|
What is the sum of four digit numbers made up of only the natural numbers 1, 2, and 3?
|
μμ°μ 1, 2, 3λ§μΌλ‘ μ΄λ£¨μ΄μ§ λ€ μ리 μλ€μ ν©μ μΌλ§μΈκ°?
|
Possibility
|
var_a = 1
var_b = 1
var_c = 0.25
var_d = var_b - var_c
var_e = var_a + var_d
var_f = 2
var_g = var_e * var_f
print('{:.2f}'.format(round(var_g+1e-10,2)))
|
3.50
|
3.5
|
1 1 2/8 [OP_SUB] [OP_ADD] 2 [OP_MUL]
|
var_a = 1
var_b = 1
var_c = 0.25
var_d = var_b - var_c
var_e = var_a + var_d
var_f = 2
var_g = var_e * var_f
print('{:.2f}'.format(round(var_g+1e-10,2)))
|
1 1 2/8 [OP_SUB] [OP_ADD] 2 [OP_MUL]
|
What is the sum of the lengths in meters (m) of the four sides of a rectangle whose longer side is 1 meter (m) and whose longer side is 2/8 meter (m) longer than its shorter side?
|
κΈ΄ λ³μ κΈΈμ΄κ° 1λ―Έν°(m)μ΄κ³ , κΈ΄ λ³μ κΈΈμ΄κ° 짧μ λ³μ κΈΈμ΄λ³΄λ€ 2/8λ―Έν°(m)λ§νΌ κΈ΄ μ§μ¬κ°νμ λ€ λ³μ κΈΈμ΄μ ν©μ λͺ λ―Έν°(m)μΈκ°μ?
|
Geometry
|
var_a = 23
var_b = 37
var_c = var_a * var_b
var_d = 16
var_e = var_c + var_d
print(int(var_e))
|
867
|
867
|
23 37 [OP_MUL] 16 [OP_ADD]
|
var_a = 23
var_b = 37
var_c = var_a * var_b
var_d = 16
var_e = var_c + var_d
print(int(var_e))
|
23 37 [OP_MUL] 16 [OP_ADD]
|
At Junwoo's school, 37 marbles each were distributed to 23 classes, and there are 16 left. How many marbles were distributed to students at Junwoo's school?
|
μ€μ°λ€ νκ΅μμ 23κ°μ λ°μ 37κ°μ ꡬμ¬μ λλ μ£Όκ³ 16κ°κ° λ¨μλ€κ³ νλ€. μ€μ°λ€ νκ΅μμ νμλ€μκ² λλ μ€ κ΅¬μ¬μ κ°μλ λͺ¨λ λͺ κ°μΈκ°?
|
Correspondence
|
var_a = 12
var_b = 2
var_c = var_a * var_b
var_d = 17
var_e = var_c + var_d
print(int(var_e))
|
41
|
41
|
12 2 [OP_MUL] 17 [OP_ADD]
|
var_a = 12
var_b = 2
var_c = var_a * var_b
var_d = 17
var_e = var_c + var_d
print(int(var_e))
|
12 2 [OP_MUL] 17 [OP_ADD]
|
In an isosceles triangle, two sides are said to be 12 centimeters (cm) long, and the other side is said to be 17 centimeters (cm) long. At this time, how many centimeters (cm) is the length of the perimeter?
|
μ΄λ±λ³μΌκ°νμμ, μλ³μ κΈΈμ΄λ 12 μΌν°λ―Έν°(γ)μ΄λ©° λ€λ₯Έ λ³μ κΈΈμ΄λ 17 μΌν°λ―Έν°(γ)λΌκ³ ν©λλ€. μ΄ λ, λλ μ κΈΈμ΄λ λͺ μΌν°λ―Έν°(γ)μ
λκΉ?
|
Geometry
|
var_a = '2AB+36=269'
var_b = 'B'
ans_dict = dict()
var_a = var_a.replace('Γ','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('Γ·','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c))
|
3
|
3
|
2AB+36=269 B [OP_DIGIT_UNK_SOLVER]
|
var_a = '2AB+36=269'
var_b = 'B'
ans_dict = dict()
var_a = var_a.replace('Γ','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('Γ·','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c))
|
2AB+36=269 B [OP_DIGIT_UNK_SOLVER]
|
2AB+36=269 is true. How much is B?
|
2AB+36=269μ
λλ€. Bλ μΌλ§μΈκ°μ?
|
Correspondence
|
var_a = 'κ°'
var_b = 'λ°λλ'
var_c = 'μ°ΈμΈ'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 'κ°'
var_e = 'λ°λλ'
var_f = '<'
var_g = 'λ°λλ'
var_h = 'μ°ΈμΈ'
var_i = '<'
list_b= []
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_j = 1
var_k = list_c[var_j-1]
print(var_k)
|
μ°ΈμΈ
|
melon
|
[OP_LIST_SOL] κ° λ°λλ μ°ΈμΈ [OP_LIST_EOL] [OP_LIST_SOL] κ° λ°λλ < λ°λλ μ°ΈμΈ < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]
|
var_a = 'persimmon'
var_b = 'banana'
var_c = 'melon'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 'persimmon'
var_e = 'banana'
var_f = '<'
var_g = 'banana'
var_h = 'melon'
var_i = '<'
list_b= []
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_j = 1
var_k = list_c[var_j-1]
print(var_k)
|
[OP_LIST_SOL] persimmon banana melon [OP_LIST_EOL] [OP_LIST_SOL] persimmon banana < banana melon < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]
|
I am trying to find three words persimmon, banana, and melon in the Korean dictionary. Persimmon comes out before banana, and banana comes out before melon. Find the word that comes out the last in the dictionary.
|
κ΅μ΄μ¬μ μμ κ°, λ°λλ, μ°ΈμΈ 3κ°μ λ¨μ΄λ₯Ό μ°ΎμΌλ €κ³ νλ€. κ°μ΄ λ°λλλ³΄λ€ λ¨Όμ λμ€κ³ λ°λλκ° μ°ΈμΈλ³΄λ€ λ¨Όμ λμ¨λ€. μ¬μ μμ κ°μ₯ λμ€μ λμ€λ λ¨μ΄λ 무μμΈμ§ ꡬνμμ€.
|
Comparison
|
var_a = 0
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_c=[]
for i in list_b:
var_e = 0
i = int(i)
while i//10 > 0:
var_e = var_e + i%10
i = i//10
var_e = var_e + i%10
list_c.append(var_e)
var_f = 9
list_d = []
for i in list_c:
if i >= var_f:
list_d.append(i)
var_g = 9
list_e = []
for i in list_d:
if i <= var_g:
list_e.append(i)
var_h = len(list_e)
print(int(var_h))
|
34
|
34
|
0 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 9 [OP_LIST_MORE_EQUAL] 9 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]
|
var_a = 0
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_c=[]
for i in list_b:
var_e = 0
i = int(i)
while i//10 > 0:
var_e = var_e + i%10
i = i//10
var_e = var_e + i%10
list_c.append(var_e)
var_f = 9
list_d = []
for i in list_c:
if i >= var_f:
list_d.append(i)
var_g = 9
list_e = []
for i in list_d:
if i <= var_g:
list_e.append(i)
var_h = len(list_e)
print(int(var_h))
|
0 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 9 [OP_LIST_MORE_EQUAL] 9 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]
|
How many 3-digit numbers are there where each digit is different and the sum of the digits is 9?
|
μΈ μ리 μ μ€ κ° μ리μ μκ° λͺ¨λ λ€λ₯΄κ³ κ° μ리μμ ν©μ΄ 9μΈ μλ λͺ¨λ λͺ κ°μ
λκΉ?
|
Correspondence
|
var_a = 3
var_b = 0.5
var_c = var_a ** var_b
var_d = 2
var_e = 2
var_f = var_d ** var_e
var_g = var_c * var_f
print('{:.2f}'.format(round(var_g+1e-10,2)))
|
6.93
|
6.93
|
3 1/2 [OP_POW] 2 2 [OP_POW] [OP_MUL]
|
var_a = 3
var_b = 0.5
var_c = var_a ** var_b
var_d = 2
var_e = 2
var_f = var_d ** var_e
var_g = var_c * var_f
print('{:.2f}'.format(round(var_g+1e-10,2)))
|
3 1/2 [OP_POW] 2 2 [OP_POW] [OP_MUL]
|
What is the surface area of a regular tetrahedron with a side of 2 centimeters (cm)?
|
νλ³μ κΈΈμ΄κ° 2μΌν°λ―Έν°(γ)μΈ μ μ¬λ©΄μ²΄μ κ²λμ΄λ?
|
Geometry
|
var_a = 12
var_b = 14
var_c = 15
var_d = 20
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = []
var_e = int(var_e)
for i in list_a:
i = int(i)
if i % var_e == 0:
list_b.append(i)
list_c = list(set(list_a) - set(list_b))
var_f = 18
list_d = []
for i in list_c:
if i < var_f:
list_d.append(i)
var_g = 1
var_h = list_d[var_g-1]
print(int(var_h))
|
14
|
14
|
[OP_LIST_SOL] 12 14 15 20 [OP_LIST_EOL] 3 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 18 [OP_LIST_LESS] 1 [OP_LIST_GET]
|
var_a = 12
var_b = 14
var_c = 15
var_d = 20
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = []
var_e = int(var_e)
for i in list_a:
i = int(i)
if i % var_e == 0:
list_b.append(i)
list_c = list(set(list_a) - set(list_b))
var_f = 18
list_d = []
for i in list_c:
if i < var_f:
list_d.append(i)
var_g = 1
var_h = list_d[var_g-1]
print(int(var_h))
|
[OP_LIST_SOL] 12 14 15 20 [OP_LIST_EOL] 3 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 18 [OP_LIST_LESS] 1 [OP_LIST_GET]
|
There is a number that is less than 18 but not a multiple of 3. Which number is it out of 12, 14, 15, or 20?
|
μ΄λ€ μλ 18λ³΄λ€ μμ§λ§ 3μ λ°°μκ° μλλλ€. 12, 14, 15, 20 μ€μμ μ΄λ€ μλ₯Ό ꡬνμμ€.
|
Correspondence
|
var_a = 1
var_b = 6
var_c = 8
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = len(list_a)
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 3
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
print(int(var_f))
|
681
|
681
|
[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 3 [OP_LIST_MAX]
|
var_a = 1
var_b = 6
var_c = 8
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = len(list_a)
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 3
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
print(int(var_f))
|
[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 3 [OP_LIST_MAX]
|
Sangwoo draws 3 out of 9 cards numbered 1 through 9 and wants to use all of them to create the third largest three-digit number. When he drew 1, 6, and 8, what number should Sangwoo make?
|
μμ°λ 1λΆν° 9κΉμ§ μ ν 9μ₯μ μΉ΄λ μ€ 3μ₯μ λ½κ³ , κ·Έ μ«μλ€μ λͺ¨λ μ¨μ μΈ λ²μ§Έλ‘ ν° μΈ μ리μλ₯Ό λ§λ€κ³ μ νλ€. μμ°κ° 1, 6, 8μ λ½μμ λ λ§λ€μ΄μΌ νλ μλ?
|
Arithmetic calculation
|
var_a = 14
var_b = 2
var_c = var_a / var_b
print(int(var_c))
|
7
|
7
|
14 2 [OP_DIV]
|
var_a = 14
var_b = 2
var_c = var_a / var_b
print(int(var_c))
|
14 2 [OP_DIV]
|
How many centimeters (cm) must the compass be spread out to draw a circle with a diameter of 14 centimeters (cm)?
|
μ»΄νΌμ€λ₯Ό λͺ μΌν°λ―Έν°(γ) λ²λ €μΌ μ§λ¦μ΄ 14 μΌν°λ―Έν°(γ)μΈ μμ 그릴 μ μμκΉμ?
|
Geometry
|
var_a = 63
var_b = 0
var_c = 7
var_d = 1
var_e = var_c - var_d
var_f = 1
list_a = [i for i in range(var_b, var_e + 1, var_f)]
list_a = [float(i) for i in list_a]
var_g = sum(list_a)
var_h = var_a - var_g
var_i = 7
var_j = var_h / var_i
print(int(var_j))
|
6
|
6
|
63 0 7 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 7 [OP_DIV]
|
var_a = 63
var_b = 0
var_c = 7
var_d = 1
var_e = var_c - var_d
var_f = 1
list_a = [i for i in range(var_b, var_e + 1, var_f)]
list_a = [float(i) for i in list_a]
var_g = sum(list_a)
var_h = var_a - var_g
var_i = 7
var_j = var_h / var_i
print(int(var_j))
|
63 0 7 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 7 [OP_DIV]
|
The sum of 7 consecutive natural numbers is 63 Find the first number
|
μ°μνλ 7κ°μ μμ°μμ ν©μ΄ 63μ
λλ€ μ²«λ²μ§Έ μλ₯Ό ꡬνμμ€
|
Arithmetic calculation
|
var_a = 12
var_b = 6
var_c = var_a + var_b
var_d = 7
var_e = 4
var_f = var_d - var_e
var_g = var_c / var_f
print(int(var_g))
|
6
|
6
|
12 6 [OP_ADD] 7 4 [OP_SUB] [OP_DIV]
|
var_a = 12
var_b = 6
var_c = var_a + var_b
var_d = 7
var_e = 4
var_f = var_d - var_e
var_g = var_c / var_f
print(int(var_g))
|
12 6 [OP_ADD] 7 4 [OP_SUB] [OP_DIV]
|
7 times a certain number is equal to 4 times the certain number plus 12 plus 6. Find the certain number.
|
μ΄λ€ μμ 7λ°°λ μ΄λ€ μμ 4λ°°μ 12λ₯Ό λνκ³ 6μ λν κ°κ³Ό κ°λ€. μ΄λ€ μλ₯Ό ꡬνμμ€.
|
Arithmetic calculation
|
var_a = 36
var_b = 2
var_c = var_a * var_b
var_d = 8
var_e = var_c / var_d
print(int(var_e))
|
9
|
9
|
36 2 [OP_MUL] 8 [OP_DIV]
|
var_a = 36
var_b = 2
var_c = var_a * var_b
var_d = 8
var_e = var_c / var_d
print(int(var_e))
|
36 2 [OP_MUL] 8 [OP_DIV]
|
The area of a triangle with a side length of 8 centimeters (cm) is 36 square centimeters (cm2). Find the distance in centimeters (cm) from a side of length 8 centimeters (cm) to the vertex opposite the side.
|
ν λ³μ κΈΈμ΄κ° 8μΌν°λ―Έν°(γ)μΈ μΌκ°νμ λμ΄λ 36μ κ³±μΌν°λ―Έν°(γ )λΌκ³ ν©λλ€. κΈΈμ΄κ° 8μΌν°λ―Έν°(γ)μΈ λ³κ³Ό μ΄ λ³κ³Ό λ§μ£Όλ³΄λ κΌμ§μ κΉμ§μ 거리λ λͺ μΌν°λ―Έν°(γ)μΌμ§ ꡬνμμ€.
|
Geometry
|
var_a = 171
var_b = 9
var_c = var_a / var_b
print(int(var_c))
|
19
|
19
|
171 9 [OP_DIV]
|
var_a = 171
var_b = 9
var_c = var_a / var_b
print(int(var_c))
|
171 9 [OP_DIV]
|
The perimeter of a regular nonagon is 171 centimeters (cm). Find the length of one side of this figure.
|
ν μ ꡬκ°νμ λλ λ 171μΌν°λ―Έν°(γ)μ
λλ€. μ΄ λνμ ν λ³ κΈΈμ΄λ₯Ό ꡬνμμ€.
|
Geometry
|
var_a = 12
var_b = 11
var_c = var_a + var_b
var_d = 1
var_e = var_c - var_d
var_f = 18
var_g = 8
var_h = var_f + var_g
var_i = 1
var_j = var_h - var_i
var_k = var_e * var_j
print(int(var_k))
|
550
|
550
|
12 11 [OP_ADD] 1 [OP_SUB] 18 8 [OP_ADD] 1 [OP_SUB] [OP_MUL]
|
var_a = 12
var_b = 11
var_c = var_a + var_b
var_d = 1
var_e = var_c - var_d
var_f = 18
var_g = 8
var_h = var_f + var_g
var_i = 1
var_j = var_h - var_i
var_k = var_e * var_j
print(int(var_k))
|
12 11 [OP_ADD] 1 [OP_SUB] 18 8 [OP_ADD] 1 [OP_SUB] [OP_MUL]
|
Among the students sitting on the playground, Yujeong is 12th from the right, 11th from the left, 18th from the back, and 8th from the front. If the number of students in each row is the same, how many students are sitting on the playground?
|
μ΄λμ₯μ μμμλ νμλ€ μ€ μ μ μ΄λ μ€λ₯Έμͺ½μμ 12λ²μ§Έ, μΌμͺ½μμ 11λ²μ§Έ, λ€μμ 18λ²μ§Έ, μμμ 8λ²μ§Έ μ€μ μμμμ΅λλ€. κ° μ€μ νμ μκ° κ°μ λ, μ΄λμ₯μ μμμλ νμμ λͺ¨λ λͺ λͺ
μ
λκΉ
|
Comparison
|
var_a = 2500
var_b = 120
var_c = 5
var_d = var_b * var_c
var_e = 350
var_f = 3
var_g = var_e * var_f
var_h = var_d + var_g
var_i = var_a - var_h
print(int(var_i))
|
850
|
850
|
2500 120 5 [OP_MUL] 350 3 [OP_MUL] [OP_ADD] [OP_SUB]
|
var_a = 2500
var_b = 120
var_c = 5
var_d = var_b * var_c
var_e = 350
var_f = 3
var_g = var_e * var_f
var_h = var_d + var_g
var_i = var_a - var_h
print(int(var_i))
|
2500 120 5 [OP_MUL] 350 3 [OP_MUL] [OP_ADD] [OP_SUB]
|
Yeri bought 5 candies that cost 120 won each and 3 chocolates that cost 350 won each and handed over 2500 won at the store. How much should Yeri get in change?
|
μ리λ κ°κ²μμ 120 μμ§λ¦¬ μ¬ν 5 κ°μ 350 μμ§λ¦¬ μ΄μ½λ¦Ώμ 3 κ° μ¬κ³ 2500 μμ λμ΅λλ€. μ리λ κ±°μ€λ¦λμΌλ‘ μΌλ§λ₯Ό λ°μμΌ ν©λκΉ?
|
Arithmetic calculation
|
var_a = 24
var_b = 4
var_c = var_a / var_b
var_d = 4
var_e = var_c - var_d
var_f = abs(var_e)
print(int(var_f))
|
2
|
2
|
24 4 [OP_DIV] 4 [OP_SUB] [OP_ABS]
|
var_a = 24
var_b = 4
var_c = var_a / var_b
var_d = 4
var_e = var_c - var_d
var_f = abs(var_e)
print(int(var_f))
|
24 4 [OP_DIV] 4 [OP_SUB] [OP_ABS]
|
If the base of a parallelogram that has an area of 24 square centimeters (cm2) is 4 centimeters (cm), find the difference between the height and the length of the base.
|
λμ΄κ° 24μ κ³±μΌν°λ―Έν°(γ )μΈ ννμ¬λ³νμ λ°λ³μ΄ 4μΌν°λ―Έν°(γ)μΌ λ, λμ΄μ λ°λ³μ κΈΈμ΄μ μ°¨λ₯Ό ꡬνμμ€.
|
Geometry
|
var_a = 1
var_b = 100
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e=""
for i in list_b:
i = str(i)
var_e = var_e + i
list_c = []
var_e = int(var_e)
while var_e//10 > 0:
list_c.append(var_e%10)
var_e = var_e//10
list_c.append(var_e%10)
list_c = list_c[::-1]
var_f = 3
var_g = 0
var_f = int(var_f)
for i in list_c:
i = int(i)
if i == var_f:
var_g = var_g + 1
print(int(var_g))
|
8
|
8
|
1 100 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST2NUM] [OP_NUM2LIST] 3 [OP_LIST_FIND_NUM]
|
var_a = 1
var_b = 100
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e=""
for i in list_b:
i = str(i)
var_e = var_e + i
list_c = []
var_e = int(var_e)
while var_e//10 > 0:
list_c.append(var_e%10)
var_e = var_e//10
list_c.append(var_e%10)
list_c = list_c[::-1]
var_f = 3
var_g = 0
var_f = int(var_f)
for i in list_c:
i = int(i)
if i == var_f:
var_g = var_g + 1
print(int(var_g))
|
1 100 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST2NUM] [OP_NUM2LIST] 3 [OP_LIST_FIND_NUM]
|
How many times does 3 appear in a list of natural numbers less than or equal to 100 that are multiples of 3?
|
100 μ΄νμ 3μ λ°°μμΈ μμ°μλ₯Ό λμ΄νμ λ 3μ λͺ λ² λ±μ₯ν©λκΉ?
|
Arithmetic calculation
|
var_a = 8
var_b = 8
var_c = var_a * var_b
var_d = 6
var_e = var_c * var_d
print(int(var_e))
|
384
|
384
|
8 8 [OP_MUL] 6 [OP_MUL]
|
var_a = 8
var_b = 8
var_c = var_a * var_b
var_d = 6
var_e = var_c * var_d
print(int(var_e))
|
8 8 [OP_MUL] 6 [OP_MUL]
|
At each vertex of a particular cube (A), a cube shape with one edge 2 centimeters (cm) long was cut out. If the length of one edge of cube (A) is 8 centimeters (cm), what is the surface area of the remaining portion of the initial cube?
|
μ΄λ€ μ μ‘면체 (κ°)μ κ° κΌμ§μ μμ ν λͺ¨μ리μ κΈΈμ΄κ° 2μΌν°λ―Έν°(γ)μΈ μ μ‘면체 λͺ¨μμ μλΌλλ€. (κ°) μ μ‘면체μ ν λͺ¨μ리μ κΈΈμ΄κ° 8μΌν°λ―Έν°(γ)λΌλ©΄, μλΌλ΄κ³ λ¨μ λΆλΆμ λΆλΆμ κ²λμ΄λ μΌλ§μ
λκΉ?
|
Geometry
|
var_a = 12
var_b = 2
var_c = var_a / var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e))
|
3
|
3
|
12 2 [OP_DIV] 2 [OP_DIV]
|
var_a = 12
var_b = 2
var_c = var_a / var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e))
|
12 2 [OP_DIV] 2 [OP_DIV]
|
If you cut a piece of string that is 12 centimeters (cm) in half, choose one of the cut pieces and cut it in half again, find the length in centimeters (cm) of the current shortest piece of string.
|
κΈΈμ΄κ° 12μΌν°λ―Έν°(γ)μΈ λμ μ λ°μΌλ‘ μλ₯΄κ³ , μλ¦° λ μ€ νλλ₯Ό κ³¨λΌ λ€μ μ λ°μΌλ‘ μλλ€λ©΄, νμ¬ κ°μ₯ 짧μ λμ κΈΈμ΄λ λͺ μΌν°λ―Έν°(γ)μΈμ§ ꡬνμμ€.
|
Geometry
|
var_a = 0.8
var_b = 0.5
var_c = 0.9
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 0.4
list_b = []
for i in list_a:
if i >= var_d:
list_b.append(i)
var_e = len(list_b)
print(int(var_e))
|
3
|
3
|
[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]
|
var_a = 0.8
var_b = 0.5
var_c = 0.9
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 0.4
list_b = []
for i in list_a:
if i >= var_d:
list_b.append(i)
var_e = len(list_b)
print(int(var_e))
|
[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]
|
How many numbers among 0.8, 1/2, and 0.9 are greater than or equal to 0.4?
|
0.8, 1/2, 0.9 μ€μμ 0.4λ³΄λ€ ν¬κ±°λ κ°μ μλ λͺ κ°μ
λκΉ?
|
Comparison
|
var_a = 300
var_b = 8
var_c = 100
var_d = var_b / var_c
var_e = var_a * var_d
var_f = 100
var_g = 5
var_h = var_f / var_g
var_i = var_e * var_h
var_j = 300
var_k = var_i - var_j
print(int(var_k))
|
180
|
180
|
300 8 100 [OP_DIV] [OP_MUL] 100 5 [OP_DIV] [OP_MUL] 300 [OP_SUB]
|
var_a = 300
var_b = 8
var_c = 100
var_d = var_b / var_c
var_e = var_a * var_d
var_f = 100
var_g = 5
var_h = var_f / var_g
var_i = var_e * var_h
var_j = 300
var_k = var_i - var_j
print(int(var_k))
|
300 8 100 [OP_DIV] [OP_MUL] 100 5 [OP_DIV] [OP_MUL] 300 [OP_SUB]
|
When water was poured into 300 grams (g) of 8% sugar water, it became 5% sugar water. How many grams (g) of water did you pour in?
|
8%μ μ€νλ¬Ό 300κ·Έλ¨(g)μ λ¬Όμ λΆμλλ 5%μ μ€νλ¬Όμ΄ λμμ΅λλ€. λ¬Όμ λͺ κ·Έλ¨(g) λΆμμ΅λκΉ?
|
Arithmetic calculation
|
var_a = 2
var_b = 4
var_c = var_a * var_b
var_d = 3
var_e = var_c * var_d
var_f = 4
var_g = var_e - var_f
var_h = 3
var_i = 2
var_j = var_h + var_i
var_k = var_g / var_j
var_l = 2
var_m = var_k + var_l
print(int(var_m))
|
6
|
6
|
2 4 [OP_MUL] 3 [OP_MUL] 4 [OP_SUB] 3 2 [OP_ADD] [OP_DIV] 2 [OP_ADD]
|
var_a = 2
var_b = 4
var_c = var_a * var_b
var_d = 3
var_e = var_c * var_d
var_f = 4
var_g = var_e - var_f
var_h = 3
var_i = 2
var_j = var_h + var_i
var_k = var_g / var_j
var_l = 2
var_m = var_k + var_l
print(int(var_m))
|
2 4 [OP_MUL] 3 [OP_MUL] 4 [OP_SUB] 3 2 [OP_ADD] [OP_DIV] 2 [OP_ADD]
|
When I went to the bank from my house, I walked a straight line at 2 kilometers (km) per hour, and when I went home from the bank, I walked 2 kilometers (km) further at 3 kilometers (km) per hour. If it took 4 hours in total, how far is it from the bank to the house?
|
μ§μμ μνκΉμ§ κ° λλ μ§μ 거리λ₯Ό μμ 2ν¬λ‘λ―Έν°(γ)λ‘, μνμμ μ§μΌλ‘ μ¬λλ 2ν¬λ‘λ―Έν°(γ) λ λ¨Ό κΈΈμ μμ 3ν¬λ‘λ―Έν°(γ)λ‘ κ±Έμ΄μλ€. μ΄ κ±Έλ¦°μκ°μ΄ 4μκ°μ΄λΌλ©΄ μνμμ μ§μΌλ‘ μ€λ 거리λ μΌλ§μ
λκΉ?
|
Arithmetic calculation
|
var_a = 45
var_b = 15
var_c = var_a - var_b
var_d = 5
var_e = var_c + var_d
print(int(var_e))
|
35
|
35
|
45 15 [OP_SUB] 5 [OP_ADD]
|
var_a = 45
var_b = 15
var_c = var_a - var_b
var_d = 5
var_e = var_c + var_d
print(int(var_e))
|
45 15 [OP_SUB] 5 [OP_ADD]
|
Yoongi, Eunji, and Yuna have several books. If Yoongi gives 5 books to Eunji, Eunji gives 10 books to Yuna, and Yuna gives 15 books to Yoongi, all three of them will have 45 books each. How many books did Yoongi have at first?
|
μ€κΈ°, μμ§, μ λ μΈ μ¬λμ΄ μ±
μ μ¬λ¬ κΆ κ°μ§κ³ μμ΅λλ€. μ€κΈ°κ° μμ§μκ² 5κΆ μ£Όκ³ , μμ§κ° μ λμκ² 10κΆ μ£Όκ³ , μ λκ° μ€κΈ°μκ² 15κΆ μ£Όλ©΄, μΈ μ¬λμ λͺ¨λ μ±
μ 45κΆμ© κ°μ§κ² λ©λλ€. μ²μμ μ€κΈ°κ° κ°μ§κ³ μλ μ±
μ λͺ κΆμ
λκΉ?
|
Arithmetic calculation
|
var_a = 215
var_b = 215
var_c = 76
var_d = var_b + var_c
var_e = var_a + var_d
var_f = 215
var_g = 76
var_h = var_f + var_g
var_i = 53
var_j = var_h - var_i
var_k = var_e + var_j
var_l = 3
var_m = var_k / var_l
print(int(var_m))
|
248
|
248
|
215 215 76 [OP_ADD] [OP_ADD] 215 76 [OP_ADD] 53 [OP_SUB] [OP_ADD] 3 [OP_DIV]
|
var_a = 215
var_b = 215
var_c = 76
var_d = var_b + var_c
var_e = var_a + var_d
var_f = 215
var_g = 76
var_h = var_f + var_g
var_i = 53
var_j = var_h - var_i
var_k = var_e + var_j
var_l = 3
var_m = var_k / var_l
print(int(var_m))
|
215 215 76 [OP_ADD] [OP_ADD] 215 76 [OP_ADD] 53 [OP_SUB] [OP_ADD] 3 [OP_DIV]
|
They drank 215 liters (l) of water on the first day, 76 liters (l) more on the second day than on the first day, and 53 liters (l) less on the last day than on the second day. How many liters (l) of water did you drink on average?
|
첫째λ μ 215리ν°(L)μ λ¬Όμ, λμ§Έλ μλ 첫째λ λ³΄λ€ 76리ν°(L) λ λ§μ λ¬Όμ, λ§μ§λ§ λ μλ λμ§Έλ λ³΄λ€ 53리ν°(L) λ μ μ λ¬Όμ λ¨Ήμμ΅λλ€. νκ· λͺ 리ν°(L)μ λ¬Όμ λ¨Ήμλμ?
|
Arithmetic calculation
|
var_a = 40
var_b = 4
var_c = var_a * var_b
print(int(var_c))
|
160
|
160
|
40 4 [OP_MUL]
|
var_a = 40
var_b = 4
var_c = var_a * var_b
print(int(var_c))
|
40 4 [OP_MUL]
|
A horse is running along a square-shaped track. If the length of one side of this track is 40 meters (m), how many meters (m) does the horse take in one turn?
|
λ§μ΄ μ μ¬κ°ν λͺ¨μμ νΈλμ λ°λΌ λ°κ³ μμ΅λλ€. μ΄ νΈλμ ν λ³μ κΈΈμ΄κ° 40λ―Έν°(m)μΌ λ, λ§μ΄ ν λ°ν΄ λ΄ κ±Έμ΄λ λͺ λ―Έν°(m)μ
λκΉ?
|
Geometry
|
var_a = 7
var_b = 7
var_c = 3
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g))
|
14
|
14
|
7 7 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]
|
var_a = 7
var_b = 7
var_c = 3
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g))
|
7 7 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]
|
How many diagonals can you draw in a heptagon?
|
μΉ κ°νμ΄ μμ λ 그릴 μ μλ λͺ¨λ λκ°μ μ κ°μλ?
|
Geometry
|
var_a = 3
var_b = 2
var_c = var_a * var_b
var_d = 3
var_e = 3
var_f = var_d * var_e
var_g = var_c + var_f
print(int(var_g))
|
15
|
15
|
3 2 [OP_MUL] 3 3 [OP_MUL] [OP_ADD]
|
var_a = 3
var_b = 2
var_c = var_a * var_b
var_d = 3
var_e = 3
var_f = var_d * var_e
var_g = var_c + var_f
print(int(var_g))
|
3 2 [OP_MUL] 3 3 [OP_MUL] [OP_ADD]
|
Add the number of edges of the triangular pyramid to the number of edges of the triangular prism.
|
μΌκ°λΏμ λͺ¨μ리μ κ°μμ μΌκ° κΈ°λ₯μ λͺ¨μ리μ κ°μλ₯Ό λνμμ€.
|
Geometry
|
var_a = 217
var_b = 2
var_c = var_a // var_b
var_d = 217
var_e = 2
var_f = var_d // var_e
var_g = 1
var_h = var_f + var_g
var_i = var_c * var_h
print(int(var_i))
|
11772
|
11772
|
217 2 [OP_FDIV] 217 2 [OP_FDIV] 1 [OP_ADD] [OP_MUL]
|
var_a = 217
var_b = 2
var_c = var_a // var_b
var_d = 217
var_e = 2
var_f = var_d // var_e
var_g = 1
var_h = var_f + var_g
var_i = var_c * var_h
print(int(var_i))
|
217 2 [OP_FDIV] 217 2 [OP_FDIV] 1 [OP_ADD] [OP_MUL]
|
When the book was opened, the sum of the pages on both sides was 217. What is the product of both of these page numbers?
|
μ±
μ νΌμ³€μ λ μ μͺ½μ μͺ½μ ν©μ΄ 217μ΄μμ΅λλ€. κ° μͺ½μμ κ³±μ μΌλ§μ
λκΉ?
|
Arithmetic calculation
|
var_a = 100
var_b = 22
var_c = var_a + var_b
var_d = 20
var_e = var_c - var_d
var_f = 3
var_g = var_e / var_f
print(int(var_g))
|
34
|
34
|
100 22 [OP_ADD] 20 [OP_SUB] 3 [OP_DIV]
|
var_a = 100
var_b = 22
var_c = var_a + var_b
var_d = 20
var_e = var_c - var_d
var_f = 3
var_g = var_e / var_f
print(int(var_g))
|
100 22 [OP_ADD] 20 [OP_SUB] 3 [OP_DIV]
|
Roses are 22 more than lilies and 20 fewer than tulips. If there are 100 flowers of all three types, how many roses are there?
|
μ₯λ―Έλ λ°±ν©λ³΄λ€ 22μ‘μ΄ λ§κ³ , ν€λ¦½λ³΄λ€ 20μ‘μ΄ μ μ΅λλ€. μΈ μ’
λ₯μ κ½μ΄ λͺ¨λ ν©ν΄μ 100μ‘μ΄ μμλ, μ₯λ―Έλ λͺ μ‘μ΄ μλμ§ κ΅¬νμμ€.
|
Arithmetic calculation
|
var_a = 2
print(int(var_a))
|
2
|
2
|
2
|
var_a = 2
print(int(var_a))
|
2
|
If you put 4 yellow balls in a box containing 3 red, 2 blue and 5 yellow balls, how many blue balls are there?
|
μ΄λ€ μμ λ°μ§λ¦μ 2μΌν°λ―Έν°(γ)λΌκ³ ν©λλ€. μ΄ μμ λ€λ₯Έ λ°μ§λ¦μ λͺ μΌν°λ―Έν°(γ)μ
λκΉ?
|
Geometry
|
var_a = 1.6
var_b = 0.8
var_c = var_a - var_b
var_d = 0.3
var_e = var_c - var_d
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
0.50
|
0.5
|
1.6 0.8 [OP_SUB] 0.3 [OP_SUB]
|
var_a = 1.6
var_b = 0.8
var_c = var_a - var_b
var_d = 0.3
var_e = var_c - var_d
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
1.6 0.8 [OP_SUB] 0.3 [OP_SUB]
|
Kahi has a 1.6 meter (m) ribbon tape. If she used 0.8 meters (m) of ribbon to make a ribbon and 0.3 meters (m) to wrap a gift, how many meters (m) of ribbon tape is left?
|
κ°ν¬μκ² λ¦¬λ³Έ ν
μ΄νκ° 1.6λ―Έν°(m) μμ΅λλ€. 리본μ λ§λλ λ°μ 0.8λ―Έν°(m)λ₯Ό μ¬μ©νκ³ μ λ¬Όμ ν¬μ₯νλ λ°μ 0.3λ―Έν°(m)λ₯Ό μ¬μ©νλ€λ©΄, λ¨μ 리본 ν
μ΄νλ λͺ λ―Έν°(m)μ
λκΉ?
|
Arithmetic calculation
|
var_a = 10
var_b = 3
var_c = var_a - var_b
print(int(var_c))
|
7
|
7
|
10 3 [OP_SUB]
|
var_a = 10
var_b = 3
var_c = var_a - var_b
print(int(var_c))
|
10 3 [OP_SUB]
|
Hyeonsu went to the mart and picked up candy, and the number coincided with the number of diagonals that could be drawn from one vertex of a regular decagon. How many candies did Hyeonsu pick up?
|
νμκ° λ§νΈμ κ°μ μ¬νμ μ§μλλ° κ·Έ μκ° λ§μΉ¨ μ μκ°νμ ν κΌμ§μ μμ κ·Έμ μ μλ λκ°μ μ κ°μμ κ°μλ€. νμκ° μ§μ μ¬νμ λͺ κ°μΈκ°?
|
Geometry
|
var_a = 6
var_b = 2
var_c = var_a ** var_b
var_d = 8
var_e = 2
var_f = var_d ** var_e
var_g = var_c + var_f
var_h = 0.5
var_i = var_g ** var_h
print(int(var_i))
|
10
|
10
|
6 2 [OP_POW] 8 2 [OP_POW] [OP_ADD] 1/2 [OP_POW]
|
var_a = 6
var_b = 2
var_c = var_a ** var_b
var_d = 8
var_e = 2
var_f = var_d ** var_e
var_g = var_c + var_f
var_h = 0.5
var_i = var_g ** var_h
print(int(var_i))
|
6 2 [OP_POW] 8 2 [OP_POW] [OP_ADD] 1/2 [OP_POW]
|
You want to know the length of the hypotenuse of a right triangle. If the two non-hypotenuse sides have lengths of 6 and 8 respectively, what is the length of the hypotenuse?
|
μ§κ°μΌκ°νμ λΉλ³μ κΈΈμ΄λ₯Ό μκ³ μΆμ΅λλ€. λΉλ³μ΄ μλ λ λ³μ΄ κ°κ° 6κ³Ό 8μ κΈΈμ΄λ₯Ό κ°λλ€λ©΄ λΉλ³μ κΈΈμ΄λ μΌλ§μΌκΉμ?
|
Geometry
|
var_a = 1300
var_b = 12
var_c = var_a * var_b
var_d = 15000
var_e = var_c - var_d
var_f = 1300
var_g = 1000
var_h = var_f - var_g
var_i = var_e / var_h
print(int(var_i))
|
2
|
2
|
1300 12 [OP_MUL] 15000 [OP_SUB] 1300 1000 [OP_SUB] [OP_DIV]
|
var_a = 1300
var_b = 12
var_c = var_a * var_b
var_d = 15000
var_e = var_c - var_d
var_f = 1300
var_g = 1000
var_h = var_f - var_g
var_i = var_e / var_h
print(int(var_i))
|
1300 12 [OP_MUL] 15000 [OP_SUB] 1300 1000 [OP_SUB] [OP_DIV]
|
You bought 12 pencils and pens in total. The pencils cost 1000 won each and the pens cost 1300 won each. You payed 15,000 won for them with no change. Find how many pencils you purchased.
|
ν μ루μ 1000μμ§λ¦¬ μ°νκ³Ό ν μ루μ 1300μμ§λ¦¬ λ³Όνμ ν©νμ¬ 12μ루λ₯Ό μ¬κ³ 15000μμ μ§λΆνμλλ κ±°μ€λ¦λ μμ΄ λ± λ§μλ€. μ°νμ λͺ μ루λ₯Ό μλμ§ κ΅¬νμμ€.
|
Arithmetic calculation
|
var_a = 10.4
var_b = 0.8
var_c = var_a / var_b
var_d = 1
var_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))
print(int(var_e))
|
13
|
13
|
10.4 0.8 [OP_DIV] 1 [OP_CEIL]
|
var_a = 10.4
var_b = 0.8
var_c = var_a / var_b
var_d = 1
var_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))
print(int(var_e))
|
10.4 0.8 [OP_DIV] 1 [OP_CEIL]
|
You have 10.4 kilograms (kg) of dough. Taehyung wants to subdivide this dough into bags by 0.8 kilograms (kg) and store them. Find out how many envelopes he needs at this time.
|
λ°μ£½ 10.4ν¬λ‘κ·Έλ¨(γ)μ΄ μμ΅λλ€. ννμ΄λ μ΄ λ°μ£½μ 0.8ν¬λ‘κ·Έλ¨(γ)μ© λ΄ν¬μ μλΆνμ¬ λ³΄κ΄νλ €κ³ ν©λλ€. μ΄ λ νμν λ΄ν¬λ λͺ κ°μΈμ§ ꡬνμΈμ.
|
Arithmetic calculation
|
var_a = 100
var_b = 1
var_c = 15
var_d = 60
var_e = var_c / var_d
var_f = var_b + var_e
var_g = var_a / var_f
print(int(var_g))
|
80
|
80
|
100 1 15 60 [OP_DIV] [OP_ADD] [OP_DIV]
|
var_a = 100
var_b = 1
var_c = 15
var_d = 60
var_e = var_c / var_d
var_f = var_b + var_e
var_g = var_a / var_f
print(int(var_g))
|
100 1 15 60 [OP_DIV] [OP_ADD] [OP_DIV]
|
The distance from Jeonghyeok's house to my grandmother's house is 100 kilometers (km), and it took 1 hour and 15 minutes to arrive by bus. What is the average distance traveled in 1 hour?
|
μ νμ΄λ€ μ§μμ ν λ¨Έλ λκΉμ§μ 거리λ 100ν¬λ‘λ―Έν°(γ)μ΄κ³ , λ²μ€λ₯Ό νκ³ 1μκ° 15λΆμ΄ κ±Έλ € λμ°©νμ΅λλ€. 1μκ° λμ κ° νκ· κ±°λ¦¬λ μΌλ§μ
λκΉ?
|
Arithmetic calculation
|
var_a = 4
print(int(var_a))
|
4
|
4
|
4
|
var_a = 4
print(int(var_a))
|
4
|
Jungkook has 5 red balls, 4 blue balls, and 3 yellow balls. When Yoongi gives Jungkook 1 yellow ball, how many blue balls does Jungkook have?
|
μ¬λ©΄μ²΄μμ λ©΄μ μλ₯Ό ꡬνμμ€.
|
Geometry
|
var_a = 24
var_b = 6
var_c = var_a * var_b
var_d = 8
var_e = var_c / var_d
print(int(var_e))
|
18
|
18
|
24 6 [OP_MUL] 8 [OP_DIV]
|
var_a = 24
var_b = 6
var_c = var_a * var_b
var_d = 8
var_e = var_c / var_d
print(int(var_e))
|
24 6 [OP_MUL] 8 [OP_DIV]
|
There are 24 apples in the supermarket. There are 6 times as many tangerines as there are apples, and 8 persimmons. How many times the number of tangerines is the number of persimmons?
|
λ§νΈμ μ¬κ³Όκ° 24κ° μμ΅λλ€. μ¬κ³Ό μμ 6λ°° λ§νΌ κ·€μ΄ μκ³ , κ°μ 8κ° μμ΅λλ€. κ·€μ μλ κ°μ μμ λͺ λ°°μ
λκΉ?
|
Arithmetic calculation
|
var_a = 20
var_b = 23
var_c = 26
var_d = 29
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 24
list_b = []
for i in list_a:
if i > var_e:
list_b.append(i)
var_f = 28
list_c = []
for i in list_b:
if i < var_f:
list_c.append(i)
var_g = 1
var_h = list_c[var_g-1]
print(int(var_h))
|
26
|
26
|
[OP_LIST_SOL] 20 23 26 29 [OP_LIST_EOL] 24 [OP_LIST_MORE] 28 [OP_LIST_LESS] 1 [OP_LIST_GET]
|
var_a = 20
var_b = 23
var_c = 26
var_d = 29
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 24
list_b = []
for i in list_a:
if i > var_e:
list_b.append(i)
var_f = 28
list_c = []
for i in list_b:
if i < var_f:
list_c.append(i)
var_g = 1
var_h = list_c[var_g-1]
print(int(var_h))
|
[OP_LIST_SOL] 20 23 26 29 [OP_LIST_EOL] 24 [OP_LIST_MORE] 28 [OP_LIST_LESS] 1 [OP_LIST_GET]
|
Find the number between 24 and 28 among 20, 23, 26, and 29.
|
20, 23, 26, 29 μ€μμ 24μ 28 μ¬μ΄μ μλ₯Ό ꡬνμμ€.
|
Correspondence
|
var_a = 20
var_b = 20
var_c = 3
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g))
|
170
|
170
|
20 20 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]
|
var_a = 20
var_b = 20
var_c = 3
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g))
|
20 20 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]
|
A point P inside the polygon. When each vertex were connected with P, 20 triangles were created. How many diagonals does this polygon have?
|
λ€κ°νμ λ΄λΆμ ν μ Pμ κ°κ°μ κΌμ§μ μ μ°κ²°νμλλ 20κ°μ μΌκ°νμ΄ μκ²Όλ€. μ΄ λ€κ°νμ λκ°μ μ κ°μλ?
|
Geometry
|
var_a = 10
var_b = 2
var_c = var_a / var_b
var_d = 2
var_e = var_c - var_d
var_f = 2
var_g = var_e ** var_f
var_h = 6
var_i = var_g * var_h
print(int(var_i))
|
54
|
54
|
10 2 [OP_DIV] 2 [OP_SUB] 2 [OP_POW] 6 [OP_MUL]
|
var_a = 10
var_b = 2
var_c = var_a / var_b
var_d = 2
var_e = var_c - var_d
var_f = 2
var_g = var_e ** var_f
var_h = 6
var_i = var_g * var_h
print(int(var_i))
|
10 2 [OP_DIV] 2 [OP_SUB] 2 [OP_POW] 6 [OP_MUL]
|
Cube with an edge length of 2 centimeters (cm) was stacked to make a large cube with an edge length of 10 centimeters (cm). If all sides of the large cube are painted orange, how many cubes have only one side painted orange?
|
ν λͺ¨μ리μ κΈΈμ΄κ° 2μΌν°λ―Έν°(γ)μΈ μ μ‘면체λ₯Ό μμ ν λͺ¨μ리μ κΈΈμ΄κ° 10μΌν°λ―Έν°(γ)μΈ ν° μ μ‘면체λ₯Ό λ§λ€μμ΅λλ€. ν° μ μ‘면체μ λͺ¨λ λ©΄μ μ£Όν©μ λ¬Όκ°μ μΉ νλ€κ³ ν λ, 1κ°μ λ©΄μλ§ μ£Όν©μμ΄ μΉ ν΄μ§ μ μ‘면체λ λͺ κ°μ
λκΉ?
|
Geometry
|
var_a = 5000
var_b = 20
var_c = var_a - var_b
var_d = 10000
var_e = var_c / var_d
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
0.50
|
0.5
|
5000 20 [OP_SUB] 10000 [OP_DIV]
|
var_a = 5000
var_b = 20
var_c = var_a - var_b
var_d = 10000
var_e = var_c / var_d
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
5000 20 [OP_SUB] 10000 [OP_DIV]
|
If a pencil sold at a store is 20 won cheaper than 5,000 won, find the price of the pencil in units of 10,000 won.
|
μ΄λ κ°κ²μμ νλ μ°νμ΄ 5μ²μλ³΄λ€ 2μμ μ λ, μ°νμ κ°κ²©μ λ§μ λ¨μλ‘ κ΅¬νμμ€.
|
Arithmetic calculation
|
var_a = 26
var_b = 4
var_c = var_a % var_b
print(int(var_c))
|
2
|
2
|
26 4 [OP_MOD]
|
var_a = 26
var_b = 4
var_c = var_a % var_b
print(int(var_c))
|
26 4 [OP_MOD]
|
When 26 is divided by 4, the quotient is A and the remainder is B. What is B in this case?
|
26μ 4λ‘ λλ΄μ λ λͺ«μ΄ A, λλ¨Έμ§κ° B μμ΅λλ€. μ΄ λ Bλ 무μμΈκ°μ?
|
Correspondence
|
var_a = 0.8
var_b = 0.5
var_c = 0.6
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 0.1
list_b = []
for i in list_a:
if i >= var_d:
list_b.append(i)
list_b = [float(i) for i in list_b]
var_e = sum(list_b)
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
1.9
|
1.9
|
[OP_LIST_SOL] 0.8 1/2 0.6 [OP_LIST_EOL] 0.1 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]
|
var_a = 0.8
var_b = 0.5
var_c = 0.6
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 0.1
list_b = []
for i in list_a:
if i >= var_d:
list_b.append(i)
list_b = [float(i) for i in list_b]
var_e = sum(list_b)
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
[OP_LIST_SOL] 0.8 1/2 0.6 [OP_LIST_EOL] 0.1 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]
|
There are a total of three numbers: 0.8, 1/2, and 0.6. What is the sum of all numbers greater than or equal to 0.1?
|
μ΄ 3κ°μ μ«μ 0.8, 1/2, 0.6μ΄ μμ΅λλ€. μ΄ μ€ 0.1λ³΄λ€ ν¬κ±°λ κ°μ μλ₯Ό λͺ¨λ λνλ©΄ μΌλ§μΈκ°μ?
|
Comparison
|
var_a = 52
var_b = 37
var_c = var_a - var_b
print(int(var_c))
|
15
|
15
|
52 37 [OP_SUB]
|
var_a = 52
var_b = 37
var_c = var_a - var_b
print(int(var_c))
|
52 37 [OP_SUB]
|
There are 37 loaves of bread, and I brought bottles of milk to eat with the bread. There are 52 loaves of bread and bottles of milk in total. How many bottles of milk are there?
|
λΉ΅μ΄ 37κ°κ° μλλ° λΉ΅κ³Ό ν¨κ» λ¨ΉκΈ° μν΄ μ°μ λ₯Ό κ°μ Έμλ€. λΉ΅κ³Ό μ°μ κ° λͺ¨λ ν©μ³ 52κ°κ° μμ΅λλ€. μ°μ λ λͺ λ³ μμ΅λκΉ?
|
Correspondence
|
var_a = 1.4
var_b = 0.9
var_c = 1.2
var_d = 0.5
var_e = 1.3
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1.1
list_b = []
for i in list_a:
if i >= var_f:
list_b.append(i)
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[var_g-1]
print('{:.2f}'.format(round(var_h+1e-10,2)))
|
1.20
|
1.2
|
[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]
|
var_a = 1.4
var_b = 0.9
var_c = 1.2
var_d = 0.5
var_e = 1.3
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1.1
list_b = []
for i in list_a:
if i >= var_f:
list_b.append(i)
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[var_g-1]
print('{:.2f}'.format(round(var_h+1e-10,2)))
|
[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]
|
Among 1.4, 9/10, 1.2, 0.5, and 13/10, if you list all the numbers greater than or equal to 1.1, what is the smallest or equal number among them?
|
1.4, 9/10, 1.2, 0.5, 13/10μμ 1.1λ³΄λ€ ν¬κ±°λ κ°μ μ«μλ₯Ό λμ΄νλ€, κ°μ₯ μκ±°λ κ°μ μ«μλ₯Ό ꡬνλ©΄ μΌλ§μ
λκΉ?
|
Comparison
|
var_a = 20
var_b = 12
var_c = var_a * var_b
var_d = 20
var_e = 2
var_f = var_d * var_e
var_g = 2
var_h = var_f * var_g
var_i = var_c + var_h
var_j = 12
var_k = 2
var_l = var_j * var_k
var_m = 2
var_n = var_l * var_m
var_o = var_i + var_n
print(int(var_o))
|
368
|
368
|
20 12 [OP_MUL] 20 2 [OP_MUL] 2 [OP_MUL] [OP_ADD] 12 2 [OP_MUL] 2 [OP_MUL] [OP_ADD]
|
var_a = 20
var_b = 12
var_c = var_a * var_b
var_d = 20
var_e = 2
var_f = var_d * var_e
var_g = 2
var_h = var_f * var_g
var_i = var_c + var_h
var_j = 12
var_k = 2
var_l = var_j * var_k
var_m = 2
var_n = var_l * var_m
var_o = var_i + var_n
print(int(var_o))
|
20 12 [OP_MUL] 20 2 [OP_MUL] 2 [OP_MUL] [OP_ADD] 12 2 [OP_MUL] 2 [OP_MUL] [OP_ADD]
|
The cuboid-shaped swimming pool is 20 meters (m) long, 12 meters (m) wide, and 2 meters (m) deep. If you want to paint all of the side walls and floor of the pool, how many square meters (m2) of the area needs to be painted?
|
μ§μ‘면체 λͺ¨μμ μμμ₯μ κ°λ‘λ 20λ―Έν°(m), μΈλ‘λ 12λ―Έν°(m), κΉμ΄λ 2λ―Έν°(m)μ
λλ€. μμμ₯μ μμͺ½ λ²½ λͺ¨λμ λ°λ₯μ νμΈνΈλ‘ μΉ νλ €κ³ ν©λλ€. μΉ ν λΆλΆμ λμ΄λ λͺ¨λ λͺ γ‘μ
λκΉ?
|
Geometry
|
var_a = 180
var_b = 2
var_c = 30
var_d = 60
var_e = var_c / var_d
var_f = var_b + var_e
var_g = var_a / var_f
print(int(var_g))
|
72
|
72
|
180 2 30 60 [OP_DIV] [OP_ADD] [OP_DIV]
|
var_a = 180
var_b = 2
var_c = 30
var_d = 60
var_e = var_c / var_d
var_f = var_b + var_e
var_g = var_a / var_f
print(int(var_g))
|
180 2 30 60 [OP_DIV] [OP_ADD] [OP_DIV]
|
Seonghyeon wants to go to his grandfather's house, which is 180 kilometers (km) away. If it takes 2 hours and 30 minutes to travel by car, how many kilometers (km) does the car travel in 1 hour?
|
μ±νμ΄λ 180ν¬λ‘λ―Έν°(γ) λ¨μ΄μ§ ν μλ²μ§ λμ κ°λ €κ³ ν©λλ€. μλμ°¨λ₯Ό νκ³ κ°λ λ° κ±Έλ¦° μκ°μ΄ 2μκ° 30λΆμ΄λΌλ©΄ μλμ°¨λ 1μκ°μ λͺ ν¬λ‘λ―Έν°(γ)μ© κ° μ
μ
λκΉ?
|
Arithmetic calculation
|
var_a = 2
var_b = 5
var_c = var_a + var_b
var_d = 3
var_e = var_c + var_d
print(int(var_e))
|
10
|
10
|
2 5 [OP_ADD] 3 [OP_ADD]
|
var_a = 2
var_b = 5
var_c = var_a + var_b
var_d = 3
var_e = var_c + var_d
print(int(var_e))
|
2 5 [OP_ADD] 3 [OP_ADD]
|
Subtracting 5 from a certain number gives 2. What number do you get when you add 3 to it?
|
5λ₯Ό μ΄λ€ μμμ λΉΌλ©΄ 2κ° λμ¨λ€. μ΄λ€ μμ 3μ λνλ©΄ μΌλ§κ° λλκ°?
|
Correspondence
|
var_a = 4
var_b = 1
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
for i, elem in enumerate(range(var_b)):
var_c = var_c / (i+1)
var_d = 3
var_e = 1
var_f = 1
var_d = int(var_d)
var_e = int(var_e)
for i, elem in enumerate(range(var_e)):
var_f = var_f * (var_d-i)
for i, elem in enumerate(range(var_e)):
var_f = var_f / (i+1)
var_g = var_c * var_f
print(int(var_g))
|
12
|
12
|
4 1 [OP_COMB] 3 1 [OP_COMB] [OP_MUL]
|
var_a = 4
var_b = 1
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
for i, elem in enumerate(range(var_b)):
var_c = var_c / (i+1)
var_d = 3
var_e = 1
var_f = 1
var_d = int(var_d)
var_e = int(var_e)
for i, elem in enumerate(range(var_e)):
var_f = var_f * (var_d-i)
for i, elem in enumerate(range(var_e)):
var_f = var_f / (i+1)
var_g = var_c * var_f
print(int(var_g))
|
4 1 [OP_COMB] 3 1 [OP_COMB] [OP_MUL]
|
A convenience store has four kinds of sandwiches, and three kinds of triangular gimbap. In how many ways can you choose one sandwich and one gimbap?
|
μ΄λ νΈμμ μ μλμμΉ 4μ’
λ₯, μΌκ°κΉλ°₯ 3μ’
λ₯κ° μλ€. μλμμΉμ μΌκ°κΉλ°₯μ κ°κ° 1κ°μ© μ ννλ κ²½μ°μ μλ?
|
Possibility
|
var_a = 350
var_b = 5
var_c = 2
var_d = var_b * var_c
var_e = var_a - var_d
var_f = 260
var_g = 5
var_h = 2
var_i = var_g * var_h
var_j = var_f - var_i
var_k = var_e * var_j
var_l = 165
var_m = 5
var_n = 2
var_o = var_m * var_n
var_p = var_l - var_o
var_q = var_k * var_p
var_r = 1600
var_s = var_q * var_r
print(int(var_s))
|
21080000000
|
21080000000
|
350 5 2 [OP_MUL] [OP_SUB] 260 5 2 [OP_MUL] [OP_SUB] [OP_MUL] 165 5 2 [OP_MUL] [OP_SUB] [OP_MUL] 1600 [OP_MUL]
|
var_a = 350
var_b = 5
var_c = 2
var_d = var_b * var_c
var_e = var_a - var_d
var_f = 260
var_g = 5
var_h = 2
var_i = var_g * var_h
var_j = var_f - var_i
var_k = var_e * var_j
var_l = 165
var_m = 5
var_n = 2
var_o = var_m * var_n
var_p = var_l - var_o
var_q = var_k * var_p
var_r = 1600
var_s = var_q * var_r
print(int(var_s))
|
350 5 2 [OP_MUL] [OP_SUB] 260 5 2 [OP_MUL] [OP_SUB] [OP_MUL] 165 5 2 [OP_MUL] [OP_SUB] [OP_MUL] 1600 [OP_MUL]
|
Inside a rectangular parallelepiped with dimensions of 350 cm (cm), 260 cm (cm), and 165 cm (cm), there is another rectangular parallelepiped spaced apart by 5 cm (cm) in width, length, and height. We want to fill the cuboid inside it with building blocks with a volume of 1 cubic centimeter (cm3). If one building block costs 1600 won, how much will need?
|
κ°λ‘, μΈλ‘, λμ΄κ° κ°κ° 350μΌν°λ―Έν°(γ), 260μΌν°λ―Έν°(γ), 165μΌν°λ―Έν°(γ)μΈ μ§μ‘면체 μμ κ°λ‘, μΈλ‘, λμ΄ λͺ¨λ 5μΌν°λ―Έν°(γ)μ© λμ΄μ Έ μλ λ λ€λ₯Έ μ§μ‘λ©΄μ²΄κ° μλ€. μ΄ μμ μλ μ§μ‘면체λ₯Ό λΆνΌκ° 1μΈμ κ³±μΌν°λ―Έν°(γ€)μΈ μκΈ°λλ¬΄λ‘ κ°λ μ±μ°λ €κ³ νλ€. μκΈ°λ무 νλκ° 1600μμ΄λΌλ©΄, μΌλ§κ° νμν μ§ κ΅¬νμμ€.
|
Geometry
|
var_a = 17
var_b = 10
var_c = var_a / var_b
var_d = 0.01
var_e = var_c * var_d
var_f = 3
var_g = var_e * var_f
print('{:.2f}'.format(round(var_g+1e-10,2)))
|
0.05
|
0.05
|
17 10 [OP_DIV] 1/100 [OP_MUL] 3 [OP_MUL]
|
var_a = 17
var_b = 10
var_c = var_a / var_b
var_d = 0.01
var_e = var_c * var_d
var_f = 3
var_g = var_e * var_f
print('{:.2f}'.format(round(var_g+1e-10,2)))
|
17 10 [OP_DIV] 1/100 [OP_MUL] 3 [OP_MUL]
|
10 times a certain number is 17. What is the result of a certain number multiplied by 1/100 and than multiplied by 3?
|
μ΄λ€ μμ 10λ°°λ 17μ
λλ€, μ΄λ€ μμ 1/100λ°°μ 3μ κ³±ν κ°μ μΌλ§μ
λκΉ?
|
Correspondence
|
var_a = 'A888<5001'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('Γ','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('Γ·','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = []
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k].append(int(c[i]))
list_a = list(set(ans_dict[var_b]))
var_c = len(list_a)
print(int(var_c))
|
4
|
4
|
A888<5001 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]
|
var_a = 'A888<5001'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('Γ','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('Γ·','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = []
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k].append(int(c[i]))
list_a = list(set(ans_dict[var_b]))
var_c = len(list_a)
print(int(var_c))
|
A888<5001 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]
|
What is the number of possible A which is from 1 to 9 to make A888<5001?
|
1λΆν° 9κΉμ§μ μ A μ€ A888<5001μ΄ λκ² νλ Aλ λͺ¨λ λͺ κ°μ
λκΉ?
|
Correspondence
|
var_a = 35
var_b = 16
var_c = 8
var_d = var_b - var_c
var_e = var_a + var_d
print(int(var_e))
|
43
|
43
|
35 16 8 [OP_SUB] [OP_ADD]
|
var_a = 35
var_b = 16
var_c = 8
var_d = var_b - var_c
var_e = var_a + var_d
print(int(var_e))
|
35 16 8 [OP_SUB] [OP_ADD]
|
Eunji is 16 years old this year. Eunji's mother was 35 when Eunji was 8 years old. How old is the mother this year?
|
μμ§λ μ¬ν΄ 16μ΄μ
λλ€. μμ§μ μ΄λ¨Έλλ μμ§κ° 8μ΄μ΄μμ λ 35μΈμμ΅λλ€. μ¬ν΄ μ΄λ¨Έλμ λμ΄λ λͺμ
λκΉ?
|
Arithmetic calculation
|
var_a = 48
var_b = 2
var_c = var_a / var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e))
|
25
|
25
|
48 2 [OP_DIV] 1 [OP_ADD]
|
var_a = 48
var_b = 2
var_c = var_a / var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e))
|
48 2 [OP_DIV] 1 [OP_ADD]
|
If the sum of two consecutive odd numbers is 48, find the larger of the two odd numbers.
|
μ°μνλ λ νμμ ν©μ΄ 48μΌ λ λ νμ μ€ ν° μλ₯Ό ꡬνμμ€.
|
Arithmetic calculation
|
var_a = 2
var_b = 1
var_c = 6
var_d = 1
list_a = [i for i in range(var_b, var_c + 1, var_d)]
var_e = 3
list_b = []
var_e = int(var_e)
for i in list_a:
i = int(i)
if i % var_e == 0:
list_b.append(i)
var_f = len(list_b)
var_g = var_a * var_f
print(int(var_g))
|
4
|
4
|
2 1 6 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_MUL]
|
var_a = 2
var_b = 1
var_c = 6
var_d = 1
list_a = [i for i in range(var_b, var_c + 1, var_d)]
var_e = 3
list_b = []
var_e = int(var_e)
for i in list_a:
i = int(i)
if i % var_e == 0:
list_b.append(i)
var_f = len(list_b)
var_g = var_a * var_f
print(int(var_g))
|
2 1 6 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_MUL]
|
Given that 2 coins and 1 dice are tossed at the same time, what is the number of cases that two coins come out on different sides and the dice divided by 3 gives a remainder of 1?
|
λμ 2κ°μ μ£Όμ¬μ 1κ°λ₯Ό λμμ λμ§ λ, λ λμ μ μλ‘ λ€λ₯Έ λ©΄μ΄ λμ€κ³ μ£Όμ¬μμ λμ 3μΌλ‘ λλ λλ¨Έμ§κ° 1μΈ κ²½μ°μ μλ?
|
Possibility
|
var_a = 3
var_b = 5
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_c))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_d = len(list_b)
print(int(var_d))
|
2
|
2
|
[OP_LIST_SOL] 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]
|
var_a = 3
var_b = 5
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_c))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_d = len(list_b)
print(int(var_d))
|
[OP_LIST_SOL] 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]
|
I'm trying to make a two-digit number, but I only want to use 3 and 5 once. How many different two-digit numbers can you make?
|
λ μ리 μλ₯Ό λ§λλ €κ³ νλλ° 3,5λ₯Ό ν λ²μ©λ§ μ¬μ©νλ €κ³ ν©λλ€. μ΄λ λ§λ€ μ μλ μλ‘ λ€λ₯Έ λ μ리 μλ λͺ¨λ λͺκ°μ§ μ
λκΉ?
|
Possibility
|
var_a = 480
var_b = 1000
var_c = var_a / var_b
var_d = 360
var_e = 1000
var_f = var_d / var_e
var_g = var_c + var_f
var_h = 2
var_i = var_g * var_h
var_j = 2
var_k = round(float(var_i)+1e-10, var_j)
print('{:.2f}'.format(round(var_k+1e-10,2)))
|
1.68
|
1.68
|
480 1000 [OP_DIV] 360 1000 [OP_DIV] [OP_ADD] 2 [OP_MUL] 2 [OP_ROUND]
|
var_a = 480
var_b = 1000
var_c = var_a / var_b
var_d = 360
var_e = 1000
var_f = var_d / var_e
var_g = var_c + var_f
var_h = 2
var_i = var_g * var_h
var_j = 2
var_k = round(float(var_i)+1e-10, var_j)
print('{:.2f}'.format(round(var_k+1e-10,2)))
|
480 1000 [OP_DIV] 360 1000 [OP_DIV] [OP_ADD] 2 [OP_MUL] 2 [OP_ROUND]
|
There is a rectangular shaped playground with a width of 480 meters (m) and a length of 360 meters (m). Find how many kilometers (km) it is if you go around the edge of the field once.
|
κ°λ‘κ° 480λ―Έν°(m), μΈλ‘κ° 360λ―Έν°(m)μΈ μ§μ¬κ°ν λͺ¨μμ μ΄λμ₯μ΄ μλ€. μ΄λμ₯μ κ°μ₯μ리λ₯Ό λ°λΌ νλ°ν΄ λλ€λ©΄ λͺ ν¬λ‘λ―Έν°(γ)μΈμ§ ꡬνμμ€.
|
Geometry
|
var_a = 2754
var_b = 1938
var_c = var_a + var_b
var_d = 1095
var_e = var_c - var_d
var_f = 3021
var_g = var_e - var_f
print(int(var_g))
|
576
|
576
|
2754 1938 [OP_ADD] 1095 [OP_SUB] 3021 [OP_SUB]
|
var_a = 2754
var_b = 1938
var_c = var_a + var_b
var_d = 1095
var_e = var_c - var_d
var_f = 3021
var_g = var_e - var_f
print(int(var_g))
|
2754 1938 [OP_ADD] 1095 [OP_SUB] 3021 [OP_SUB]
|
There were 2754 baseballs and 1938 ping pong balls in the shop. Among them, 1095 baseballs and a few ping-pong balls were sold, and a total of 3021 balls were left. How many ping-pong balls were sold?
|
λ§νΈμ μΌκ΅¬κ³΅μ΄ 2754κ°, νκ΅¬κ³΅μ΄ 1938κ° μμμ΅λλ€. κ·Έμ€μμ μΌκ΅¬κ³΅ 1095κ°μ νꡬ곡 λͺ κ°λ₯Ό νμλλ μΌκ΅¬κ³΅κ³Ό νκ΅¬κ³΅μ΄ ν©ν΄μ 3021κ° λ¨μμ΅λλ€. νꡬ곡μ λͺ κ° νμλμ§ κ΅¬νμμ€.
|
Arithmetic calculation
|
var_a = 0.45
var_b = 7
var_c = var_a + var_b
var_d = 7
var_e = var_c * var_d
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
52.15
|
52.15
|
0.45 7 [OP_ADD] 7 [OP_MUL]
|
var_a = 0.45
var_b = 7
var_c = var_a + var_b
var_d = 7
var_e = var_c * var_d
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
0.45 7 [OP_ADD] 7 [OP_MUL]
|
I mistakenly subtracted 7 from this number when I was supposed to multiply it, and I got 0.45. How much is it if I calculate it correctly?
|
μ΄λ€ μμ 7 μ κ³±ν κ²μ μλͺ»νμ¬ λΊλλ 0.45 κ° λμμ΅λλ€. λ°λ₯΄κ² κ³μ°νλ©΄ μΌλ§μΈμ§ ꡬνμμ€.
|
Correspondence
|
var_a = 15
var_b = 20
var_c = var_a * var_b
var_d = 6
var_e = var_c - var_d
print(int(var_e))
|
294
|
294
|
15 20 [OP_MUL] 6 [OP_SUB]
|
var_a = 15
var_b = 20
var_c = var_a * var_b
var_d = 6
var_e = var_c - var_d
print(int(var_e))
|
15 20 [OP_MUL] 6 [OP_SUB]
|
Sanghyun's class donated unread books to the library. There are 20 students in her class and they planned to donate 15 books per student. If the library got 6 books less than they expected, how many books the library got?
|
μνμ΄λ€ λ° νμλ€μ΄ μ 보λ μ±
μ λμκ΄μ κΈ°λΆνλ€. μνμ΄λ€ λ° νμμ 20λͺ
μ΄κ³ νμ λΉ 15κΆμ μ±
μ κΈ°λΆνλ€κ³ νμλ€. κ·Έλ¬λ λμκ΄μμ λ°μ μ±
μ μκ° μμνλ μ±
μλ³΄λ€ 6 κΆμ΄ λΆμ‘±νλ€λ©΄ λμκ΄μμ μ€μ λ‘ λ°μ λμ μλ λͺκΆ μ
λκΉ?
|
Correspondence
|
var_a = 15
var_b = 9
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e))
|
5
|
5
|
15 9 [OP_SUB] 1 [OP_SUB]
|
var_a = 15
var_b = 9
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e))
|
15 9 [OP_SUB] 1 [OP_SUB]
|
There are 19 toys in all, each in a different sizes. If you put these toys in order from the smallest, toy (a) is at 9th and toy (b) is at 15th place. How many toys are there between toy (a) and toy (b)?
|
κ°κ°μ ν¬κΈ°κ° λ€λ₯Έ μ₯λκ°μ΄ λͺ¨λ 19κ° μμ΅λλ€. μ΄ μ₯λκ°μ ν¬κΈ°κ° μμ κ²λΆν° μμλλ‘ λμΌλ©΄ μ₯λκ° (κ°)λ μΌμͺ½μμ 9λ²μ§Έμ μκ³ , μ₯λκ° (λ)λ μΌμͺ½μμ 15λ²μ§Έμ μμ΅λλ€. μ₯λκ° (κ°)μ μ₯λκ° (λ) μ¬μ΄μ μλ μ₯λκ°μ λͺ κ°μ
λκΉ?
|
Comparison
|
var_a = 0.2
var_b = 1.1
var_c = var_a + var_b
var_d = 0.1
var_e = var_c + var_d
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
1.40
|
1.4
|
0.2 1.1 [OP_ADD] 1/10 [OP_ADD]
|
var_a = 0.2
var_b = 1.1
var_c = var_a + var_b
var_d = 0.1
var_e = var_c + var_d
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
0.2 1.1 [OP_ADD] 1/10 [OP_ADD]
|
Your older brother is 1/10 meter (m) taller than you, and your younger brother is 0.2 meter (m) shorter than you. If the younger brother is 1.1 meters (m), how tall is the older brother in meters (m)?
|
νμ λλ³΄λ€ 1/10λ―Έν°(m) λ ν¬κ³ , λμμ λλ³΄λ€ 0.2λ―Έν°(m) μμ΅λλ€. λμμ ν€κ° 1.1λ―Έν°(m)λΌλ©΄ νμ ν€λ λͺ λ―Έν°(m)μΈμ§ ꡬνμμ€.
|
Arithmetic calculation
|
var_a = 35
var_b = 70
var_c = 1
var_d = var_b - var_c
var_e = 1
list_a = [i for i in range(var_a, var_d + 1, var_e)]
var_f = 6
var_g = 3
list_b = []
var_f = int(var_f)
var_g = int(var_g)
if var_g < 0:
var_g = var_g + var_f
for i in list_a:
i = int(i)
if i%var_f == var_g:
list_b.append(i)
var_h = 8
var_i = 1
list_c = []
var_h = int(var_h)
var_i = int(var_i)
if var_i < 0:
var_i = var_i + var_h
for i in list_b:
i = int(i)
if i%var_h == var_i:
list_c.append(i)
var_j = 1
var_k = list_c[var_j-1]
print(int(var_k))
|
57
|
57
|
35 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 6 3 [OP_LIST_DIVIDE_AND_REMAIN] 8 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]
|
var_a = 35
var_b = 70
var_c = 1
var_d = var_b - var_c
var_e = 1
list_a = [i for i in range(var_a, var_d + 1, var_e)]
var_f = 6
var_g = 3
list_b = []
var_f = int(var_f)
var_g = int(var_g)
if var_g < 0:
var_g = var_g + var_f
for i in list_a:
i = int(i)
if i%var_f == var_g:
list_b.append(i)
var_h = 8
var_i = 1
list_c = []
var_h = int(var_h)
var_i = int(var_i)
if var_i < 0:
var_i = var_i + var_h
for i in list_b:
i = int(i)
if i%var_h == var_i:
list_c.append(i)
var_j = 1
var_k = list_c[var_j-1]
print(int(var_k))
|
35 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 6 3 [OP_LIST_DIVIDE_AND_REMAIN] 8 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]
|
Subtracting 3 from the number is a multiple of 6, and subtracting 1 from the number is a multiple of 8. Find the number. However, any number is a natural number greater than 35 and less than 70.
|
μ΄λ€ μμμ 3μ λΉΌλ©΄ 6μ λ°°μμ΄κ³ , μ΄λ€ μμμ 1μ λΉΌλ©΄ 8μ λ°°μμ΄λ€. μ΄λ€ μλ₯Ό ꡬνμμ€. λ¨, μ΄λ€ μλ 35λ³΄λ€ ν¬κ³ 70λ³΄λ€ μμ μμ°μμ΄λ€.
|
Correspondence
|
var_a = 3
var_b = 8
var_c = 2
var_d = 7
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 4
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 3
list_c=list_b.copy()
list_c.sort()
var_g = list_c[-var_f]
var_h = 10
var_i = len(list_a)
var_j = 2
var_k = var_i - var_j
var_l = var_h ** var_k
var_m = var_g / var_l
print('{:.2f}'.format(round(var_m+1e-10,2)))
|
83.72
|
83.72
|
[OP_LIST_SOL] 3 8 2 7 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 10 [OP_LIST_POP] [OP_LIST_LEN] 2 [OP_SUB] [OP_POW] [OP_DIV]
|
var_a = 3
var_b = 8
var_c = 2
var_d = 7
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 4
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 3
list_c=list_b.copy()
list_c.sort()
var_g = list_c[-var_f]
var_h = 10
var_i = len(list_a)
var_j = 2
var_k = var_i - var_j
var_l = var_h ** var_k
var_m = var_g / var_l
print('{:.2f}'.format(round(var_m+1e-10,2)))
|
[OP_LIST_SOL] 3 8 2 7 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 10 [OP_LIST_POP] [OP_LIST_LEN] 2 [OP_SUB] [OP_POW] [OP_DIV]
|
There are 4 cards numbered 3, 8, 2, and 7. If each card is used only once when forming a number with two-digit decimal number, what is the third largest number?
|
3, 8, 2, 7μ μ«μκ° μ ν 4 μ₯μ μΉ΄λκ° μλ€. κ° μΉ΄λλ₯Ό λ± ν λ²μ©λ§ μ¬μ©νμ¬ μμμ λ μ리 μλ₯Ό λ§λ€ λ μΈ λ²μ§Έλ‘ ν° μλ 무μμΌκΉμ?
|
Possibility
|
var_a = 0.8
var_b = 0.5
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 0.3
list_b = []
for i in list_a:
if i < var_c:
list_b.append(i)
var_d = len(list_b)
print(int(var_d))
|
0
|
0
|
[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 0.3 [OP_LIST_LESS] [OP_LIST_LEN]
|
var_a = 0.8
var_b = 0.5
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 0.3
list_b = []
for i in list_a:
if i < var_c:
list_b.append(i)
var_d = len(list_b)
print(int(var_d))
|
[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 0.3 [OP_LIST_LESS] [OP_LIST_LEN]
|
Jungkook has a 0.8 number card and Yoongi has a 1/2 number card. How many people have a number card less than 0.3?
|
μ κ΅μ΄λ 0.8, μ€κΈ°λ 1/2μ μ«μμΉ΄λλ₯Ό κ°κ³ μμ΅λλ€. 0.3λ³΄λ€ μμ μ«μμΉ΄λλ₯Ό κ°μ§κ³ μλ μ¬λμ λͺ λͺ
μ
λκΉ?
|
Comparison
|
var_a = 46
var_b = 2
var_c = var_a / var_b
var_d = 7
var_e = var_c - var_d
var_f = 2
var_g = var_e / var_f
var_h = 7
var_i = var_g + var_h
print(int(var_i))
|
15
|
15
|
46 2 [OP_DIV] 7 [OP_SUB] 2 [OP_DIV] 7 [OP_ADD]
|
var_a = 46
var_b = 2
var_c = var_a / var_b
var_d = 7
var_e = var_c - var_d
var_f = 2
var_g = var_e / var_f
var_h = 7
var_i = var_g + var_h
print(int(var_i))
|
46 2 [OP_DIV] 7 [OP_SUB] 2 [OP_DIV] 7 [OP_ADD]
|
There is a rectangular farm. If the circumference of this farm is 46 kilometers (km) and the width is 7 kilometers (km) longer than the length, how many kilometers (km) is the width of this farm?
|
μ§μ¬κ°ν λͺ¨μμ λμ₯μ΄ μμ΅λλ€. μ΄ λμ₯μ λλ μ κΈΈμ΄λ 46ν¬λ‘λ―Έν°(γ)μ΄κ³ , κ°λ‘μ κΈΈμ΄λ μΈλ‘μ κΈΈμ΄λ³΄λ€ 7ν¬λ‘λ―Έν°(γ) λ κΈΈλ€κ³ ν λ, μ΄ λμ₯μ κ°λ‘μ κΈΈμ΄λ λͺ ν¬λ‘λ―Έν°(γ)μ
λκΉ?
|
Geometry
|
var_a = 20
var_b = 6
var_c = var_a - var_b
var_d = 5
var_e = var_c + var_d
print(int(var_e))
|
19
|
19
|
20 6 [OP_SUB] 5 [OP_ADD]
|
var_a = 20
var_b = 6
var_c = var_a - var_b
var_d = 5
var_e = var_c + var_d
print(int(var_e))
|
20 6 [OP_SUB] 5 [OP_ADD]
|
You are comparing the heights of 20 students. Jungkook is shorter than Yoongi, and there are 5 students between Yoongi and Jungkook. There are 6 students who are taller than Jungkook. How many students are shorter than Yoongi?
|
20λͺ
μ νμλ€μ ν€λ₯Ό λΉκ΅νκ³ μμ΅λλ€. μ κ΅μ΄λ μ€κΈ°λ³΄λ€ ν€κ° μκ³ , μ€κΈ°μ μ κ΅μ΄ μ¬μ΄μλ 5λͺ
μ νμμ΄ μμ΅λλ€. μ κ΅μ΄λ³΄λ€ ν€κ° ν° νμμ λͺ¨λ 6λͺ
μ
λλ€. μ€κΈ°λ³΄λ€ μμ νμμ λͺ λͺ
μ
λκΉ?
|
Comparison
|
var_a = 6
var_b = 8
var_c = var_a + var_b
var_d = 2
var_e = var_c // var_d
print(int(var_e))
|
7
|
7
|
6 8 [OP_ADD] 2 [OP_FDIV]
|
var_a = 6
var_b = 8
var_c = var_a + var_b
var_d = 2
var_e = var_c // var_d
print(int(var_e))
|
6 8 [OP_ADD] 2 [OP_FDIV]
|
Yuri ate 6 hamburgers in a hamburger eating contest, and Jisoo ate 8 hamburgers. Changhyun ate more than Yuri and less than Jisu. How many hamburgers did Changhyun eat?
|
μ 리λ νλ²κ±° λ¨ΉκΈ° λνμμ νλ²κ±° 6κ°λ₯Ό λ¨Ήμκ³ , μ§μλ νλ²κ±° 8κ°λ₯Ό λ¨Ήμμ΅λλ€. μ°½νμ΄λ μ 리보λ€λ λ§μ΄ λ¨Ήκ³ μ§μ보λ€λ μ κ² λ¨Ήμμ΅λλ€. μ°½νμ΄κ° λ¨Ήμ νλ²κ±°λ λͺ κ°μ
λκΉ?
|
Comparison
|
var_a = 0.735
var_b = 0.001
var_c = var_a / var_b
var_d = 10
var_e = var_c * var_d
print(int(var_e))
|
7350
|
7350
|
0.735 1/1000 [OP_DIV] 10 [OP_MUL]
|
var_a = 0.735
var_b = 0.001
var_c = var_a / var_b
var_d = 10
var_e = var_c * var_d
print(int(var_e))
|
0.735 1/1000 [OP_DIV] 10 [OP_MUL]
|
If 1/1000 of a certain number is 0.735, what number is 10 times that certain number?
|
μ΄λ€ μμ 1/1000μΈ μκ° 0.735μ΄λ©΄ μ΄λ€ μμ 10λ°°μΈ μλ μΌλ§μ
λκΉ?
|
Correspondence
|
var_a = 3
var_b = 4
var_c = 6
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 450
list_c = []
for i in list_b:
if i > var_e:
list_c.append(i)
var_f = len(list_c)
print(int(var_f))
|
3
|
3
|
[OP_LIST_SOL] 3 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 450 [OP_LIST_MORE] [OP_LIST_LEN]
|
var_a = 3
var_b = 4
var_c = 6
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 450
list_c = []
for i in list_b:
if i > var_e:
list_c.append(i)
var_f = len(list_c)
print(int(var_f))
|
[OP_LIST_SOL] 3 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 450 [OP_LIST_MORE] [OP_LIST_LEN]
|
Seung-hee wants to make a three-digit number by throwing the dice three times and using all the numbers that come out. When 3, 4, and 6 came out after rolling the dice, how many cases are possible to make a number bigger than 450?
|
μΉν¬λ μ£Όμ¬μλ₯Ό μΈ λ² λμ Έ λμ¨ μλ₯Ό λͺ¨λ μ¬μ©νμ¬ μΈ μ리 μλ₯Ό λ§λ€κ³ μ νλ€. μ£Όμ¬μλ₯Ό λμ Έ 3, 4, 6μ΄ λμμ λ, 450λ³΄λ€ ν° μλ₯Ό λ§λλ κ²½μ°λ λͺ¨λ λͺ κ°μ§μΈκ°?
|
Possibility
|
var_a = 7
var_b = 2
var_c = 1
var_d = var_b * var_c
var_e = var_a - var_d
var_f = 1
var_g = var_e + var_f
print(int(var_g))
|
6
|
6
|
7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]
|
var_a = 7
var_b = 2
var_c = 1
var_d = var_b * var_c
var_e = var_a - var_d
var_f = 1
var_g = var_e + var_f
print(int(var_g))
|
7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]
|
I'm going to give 7 identical books to Yoongi and Hoseok. Yoongi and Hoseok will receive at least one book. How many ways can the books be distributed in total?
|
μμ μμ 7κ°μ λκ°μ μ±
μ μ€κΈ°μ νΈμμ΄μκ² λλμ΄μ£Όλ €κ³ ν©λλ€. μ€κΈ°μ νΈμμ΄λ μ μ΄λ 1κ°μ μ±
μ λ°μ΅λλ€. μ±
μ λλμ΄μ£Όλ λ°©λ²μ μ΄ λͺ κ°μ
λκΉ?
|
Possibility
|
var_a = 1
var_b = 100
list_a = []
if var_a%2!=0:
for i in range(var_a+1, var_b+1, 2):
list_a.append(i)
else:
for i in range(var_a, var_b+1, 2):
list_a.append(i)
var_c = 3
list_b = []
var_c = int(var_c)
for i in list_a:
i = int(i)
if i % var_c == 0:
list_b.append(i)
var_d = len(list_b)
print(int(var_d))
|
16
|
16
|
1 100 [OP_LIST_EVEN] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]
|
var_a = 1
var_b = 100
list_a = []
if var_a%2!=0:
for i in range(var_a+1, var_b+1, 2):
list_a.append(i)
else:
for i in range(var_a, var_b+1, 2):
list_a.append(i)
var_c = 3
list_b = []
var_c = int(var_c)
for i in list_a:
i = int(i)
if i % var_c == 0:
list_b.append(i)
var_d = len(list_b)
print(int(var_d))
|
1 100 [OP_LIST_EVEN] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]
|
How many numbers from 1 to 100 are even and multiples of 3?
|
1λΆν° 100κΉμ§μ μ μ€ μ§μμ΄λ©°, 3μ λ°°μμΈ μλ λͺ κ°μ
λκΉ?
|
Arithmetic calculation
|
var_a = 17
var_b = 8
var_c = var_a - var_b
print(int(var_c))
|
9
|
9
|
17 8 [OP_SUB]
|
var_a = 17
var_b = 8
var_c = var_a - var_b
print(int(var_c))
|
17 8 [OP_SUB]
|
There are 17 dogs and cats in total. If there are 8 cats, how many dogs are there?
|
κ°μ κ³ μμ΄λ₯Ό ν©νλ©΄ 17λ§λ¦¬μ
λλ€. κ·Έμ€μμ κ³ μμ΄κ° 8λ§λ¦¬λΌλ©΄ κ°λ λͺ λ§λ¦¬μ
λκΉ?
|
Arithmetic calculation
|
var_a = 25
var_b = 1
var_c = var_a - var_b
print(int(var_c))
|
24
|
24
|
25 1 [OP_SUB]
|
var_a = 25
var_b = 1
var_c = var_a - var_b
print(int(var_c))
|
25 1 [OP_SUB]
|
There are three different natural numbers A, B, and C. When A is divided by 25, the quotient is B and the remainder is C. Find the largest number that can be C.
|
μλ‘ λ€λ₯Έ μΈ μμ°μ A, B, Cκ° μμ΅λλ€. Aλ₯Ό 25λ‘ λλλ©΄ λͺ«μ Bμ΄κ³ λλ¨Έμ§λ Cκ° λ©λλ€. λλ¨Έμ§ Cκ° λ μ μλ κ°μ₯ ν° μλ₯Ό ꡬνμμ€.
|
Correspondence
|
var_a = 8
var_b = 9
var_c = var_a + var_b
var_d = 13
var_e = var_c - var_d
var_f = 2
var_g = var_e - var_f
print(int(var_g))
|
2
|
2
|
8 9 [OP_ADD] 13 [OP_SUB] 2 [OP_SUB]
|
var_a = 8
var_b = 9
var_c = var_a + var_b
var_d = 13
var_e = var_c - var_d
var_f = 2
var_g = var_e - var_f
print(int(var_g))
|
8 9 [OP_ADD] 13 [OP_SUB] 2 [OP_SUB]
|
13 students stand in a line. Minyoung stands at the 8th from the left, and Hoseok stands at the 9th from the right. How many students are standing between Minyoung and Hoseok?
|
νμ 13λͺ
μ΄ ν μ€λ‘ μ μμ΅λλ€. λ―Όμμ΄λ μΌμͺ½μμ 8λ²μ§Έμ μ μκ³ , νΈμμ΄λ μ€λ₯Έμͺ½μμ 9λ²μ§Έμ μ μμ΅λλ€. λ―Όμμ΄μ νΈμμ΄ μ¬μ΄μ μ μλ νμμ λͺ λͺ
μ
λκΉ?
|
Comparison
|
var_a = 3
var_b = 3
var_c = var_a + var_b
var_d = 3
var_e = 1
var_f = var_d - var_e
var_g = var_c - var_f
var_h = 3
var_i = 3
var_j = var_h + var_i
var_k = 3
var_l = 1
var_m = var_k - var_l
var_n = var_j - var_m
var_o = 1
var_g = int(var_g)
var_n = int(var_n)
for i, elem in enumerate(range(var_n)):
var_o = var_o * (var_g-i)
var_p = 3
var_q = 3
var_r = 1
var_p = int(var_p)
var_q = int(var_q)
for i, elem in enumerate(range(var_q)):
var_r = var_r * (var_p-i)
var_s = var_o * var_r
print(int(var_s))
|
144
|
144
|
3 3 [OP_ADD] 3 1 [OP_SUB] [OP_SUB] 3 3 [OP_ADD] 3 1 [OP_SUB] [OP_SUB] [OP_PERM] 3 3 [OP_PERM] [OP_MUL]
|
var_a = 3
var_b = 3
var_c = var_a + var_b
var_d = 3
var_e = 1
var_f = var_d - var_e
var_g = var_c - var_f
var_h = 3
var_i = 3
var_j = var_h + var_i
var_k = 3
var_l = 1
var_m = var_k - var_l
var_n = var_j - var_m
var_o = 1
var_g = int(var_g)
var_n = int(var_n)
for i, elem in enumerate(range(var_n)):
var_o = var_o * (var_g-i)
var_p = 3
var_q = 3
var_r = 1
var_p = int(var_p)
var_q = int(var_q)
for i, elem in enumerate(range(var_q)):
var_r = var_r * (var_p-i)
var_s = var_o * var_r
print(int(var_s))
|
3 3 [OP_ADD] 3 1 [OP_SUB] [OP_SUB] 3 3 [OP_ADD] 3 1 [OP_SUB] [OP_SUB] [OP_PERM] 3 3 [OP_PERM] [OP_MUL]
|
If 3 male students and 3 female students pass through the door one by one, find the number of cases in which 3 male students pass through the door in succession.
|
λ¨νμ 3λͺ
κ³Ό μ¬νμ 3λͺ
μ΄ ν λͺ
μ© μΆμ
λ¬Έμ μ§λ λ, λ¨νμ 3λͺ
μ΄ μ°μμΌλ‘ μΆμ
λ¬Έμ μ§λλ κ²½μ°μ μλ₯Ό ꡬνμμ€.
|
Possibility
|
var_a = 6
var_b = 5
var_c = var_a + var_b
print(int(var_c))
|
11
|
11
|
6 5 [OP_ADD]
|
var_a = 6
var_b = 5
var_c = var_a + var_b
print(int(var_c))
|
6 5 [OP_ADD]
|
When students are lined up in a single line, how many students are there when 6 people are in front of Yoonjung? (Yoonjung is at 5th from the back.)
|
νμλ€μ΄ μΌλ ¬λ‘ μ€μ μ°μ λ μ€μ μ΄ μμ 6λͺ
μ΄ μκ³ μ€μ μ΄λ λ€μμ 5λ²μ§Έμ μ μμ λ μ€μ μ νμμ λͺ¨λ λͺ λͺ
μ
λκΉ?
|
Comparison
|
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