ผลเหมือนกับ ping98k/qwen3-8b-recall-writer-4e-2e5

เพื่มเติมคือ 2e4 ลืมวิธีตอบคำถาม math

messages = [
    {"role" : "user", "content" : "Solve (x + 2)^2 = 0."}
]
text = tokenizer.apply_chat_template(
    messages,
    tokenize = False,
    add_generation_prompt = True, # Must add for generation
    enable_thinking = False, # Disable thinking
)

from transformers import TextStreamer
_ = model.generate(
    **tokenizer(text, return_tensors = "pt").to("cuda"),
    max_new_tokens = 256, # Increase for longer outputs!
    temperature = 0.7, top_p = 0.8, top_k = 20, # For non thinking
    streamer = TextStreamer(tokenizer, skip_prompt = True),
)

ping98k/qwen3-8b-recall-writer-4e-2e4

Okay, so I need to solve the equation (x + 2)² = 0. Hmm, let me think. First, I remember that squaring a term means multiplying it by itself. So (x + 2) squared would be (x + 2)(x + 2). Maybe I can expand that to make it easier to solve?

Let me try expanding it. Using the distributive property (FOIL method), first terms: x * x = x². Outer terms: x * 2 = 2x. Inner terms: 2 * x = 2x. Last terms: 2 * 2 = 4. Adding those up: x² + 2x + 2x + 4. Combine like terms: 2x + 2x is 4x, so it becomes x² + 4x + 4. So the equation is x² + 4x + 4 = 0.

Wait, but maybe there's a simpler way? Since it's a square equal to zero, maybe I can take the square root of both sides? Let me recall: if a² = 0, then a must be 0 because the square of a real number is zero

ping98k/qwen3-8b-recall-writer-4e-2e5

We are given the equation:

$$(x+2{)}^2=0(x\; +\; 2)^2\; =\; 0$$

### Step 1: Take the square root of both sides
$$\sqrt{(x+2{)}^2}=\sqrt{0}\backslash sqrt\{(x\; +\; 2)^2\}\; =\; \backslash sqrt\{0\}$$

This gives:
$$\mathrm{\mid }x+2\mathrm{\mid }=0|x\; +\; 2|\; =\; 0$$

### Step 2: Solve the absolute value equation
$$\mathrm{\mid }x+2\mathrm{\mid }=0\Rightarrow x+2=0|x\; +\; 2|\; =\; 0\; \backslash Rightarrow\; x\; +\; 2\; =\; 0$$

### Step 3: Solve for $x$
$$x+2=0\Rightarrow x=-2x\; +\; 2\; =\; 0\; \backslash Rightarrow\; x\; =\; -2$$

---

### ✅ Final Answer:
$$\boxed{{\displaystyle -2}}\backslash boxed\{-2\}$$<|im_end|>

Uploaded model

• Developed by: ping98k
• License: apache-2.0
• Finetuned from model : unsloth/Qwen3-8B-unsloth-bnb-4bit

This qwen3 model was trained 2x faster with Unsloth and Huggingface's TRL library.